1.

`XeF_(6)+PF_(5) to `A. `XeF_(6)`B. `[XeF]^(+)[PF_(6)]^(-)`C. `XeF_(4)`D. `[PF_(4)]^(+)[XeF_(3)]^(-)`

Answer» Correct Answer - B
`PF_(5)` is a fluoride ion acceptor so it yields cationic species with xenon fluorides.
`XeF_(2) + PF_(5) rarr [XeF]^(+)[PF_(6)]^(-)`


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