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Xv. Solve it please.Help me |
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Answer» -step explanation:XV.Given :-a+b+c = 0TO FIND :-Evaluate a³+b³+c³ ?SOLUTION :-Given that a+b+c = 0=> a+b = -c ----------(1)On cubing both sides then=> (a+b)³ = (-c)³=> a³+b³+3ab(a+b) = -c³=> a³+b³+3ab(-c) = -c³ (from (1))=> a³+b³-3abc = -c³=> a³+b³+c³-3abc = 0=> a³+b³+c³ = 3abcTherefore a³+b³+c³ = 3abcAnswer:-If a +b+c = 0 then a³+b³+c³ = 3abcUsed FORMULAE:-(a+b)³ = a³+b³+3ab(a+b) |
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