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Xv. Solve it please.Help me |
| Answer» <html><body><p>-step explanation:XV.Given :-a+b+c = <a href="https://interviewquestions.tuteehub.com/tag/0to-1749267" style="font-weight:bold;" target="_blank" title="Click to know more about 0TO">0TO</a> <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> :-Evaluate a³+b³+c³ ?<a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :-Given that a+b+c = 0=> a+b = -c ----------(1)On cubing both sides then=> (a+b)³ = (-c)³=> a³+b³+3ab(a+b) = -c³=> a³+b³+3ab(-c) = -c³ (from (1))=> a³+b³-3abc = -c³=> a³+b³+c³-3abc = 0=> a³+b³+c³ = 3abcTherefore a³+b³+c³ = 3abcAnswer:-If a +b+c = 0 then a³+b³+c³ = 3abcUsed <a href="https://interviewquestions.tuteehub.com/tag/formulae-996890" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULAE">FORMULAE</a>:-(a+b)³ = a³+b³+3ab(a+b)</p></body></html> | |