`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pressure of `XY_(2)` is `600` mm Hg, the total equilibrium pressure is `800` mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.A. `50.0`B. `100.0`C. `166.6`D. `400.0`

`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pre

1.	`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pressure of `XY_(2)` is `600` mm Hg, the total equilibrium pressure is `800` mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.A. `50.0`B. `100.0`C. `166.6`D. `400.0`
Answer» Correct Answer - B `{:(,XY_(2),hArr,XY,+,Y),("Initial",P,,0,,0),("Final",P-x,,x,,x):}` Initial `P=600` mm Hg, Final `P=800` mm Hg Total "moles" `prop` final P. `:. P-x+x+x prop 800` `600-x+x+xprop 800` `x=200` mmHg `K=(x xx x)/(P-x)=(200xx200)/(400)=100 Hg`

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`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pressure of `XY_(2)` is `600` mm Hg, the total equilibrium pressure is `800` mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.A. `50.0`B. `100.0`C. `166.6`D. `400.0`

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