Y^2-38y-1575=0by completing square

1.	Y^2-38y-1575=0by completing square
Answer» Solution for x2-38x-1575=0 equation: x2-38x-1575=0 We add all the NUMBERS together, and all the variables X^2-38x-1575=0 a = 1; B = -38; c = -1575; Δ = b2-4ac Δ = -382-4·1·(-1575) Δ = 7744 The delta value is higher than zero, so the equation has TWO solutions We use following formulas to calculate our solutions: x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a} \sqrt{\Delta}=\sqrt{7744}=88 x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-88}{21}=\frac{-50}{2} =-25 x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+88}{21}=\frac{126}{2} =63

Answer»

Solution for x2-38x-1575=0 equation:

x2-38x-1575=0

We add all the NUMBERS together, and all the variables

X^2-38x-1575=0

a = 1; B = -38; c = -1575;

Δ = b2-4ac

Δ = -382-4·1·(-1575)

Δ = 7744

The delta value is higher than zero, so the equation has TWO solutions

We use following formulas to calculate our solutions:

x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{7744}=88

x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-88}{2*1}=\frac{-50}{2}

=-25

x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+88}{2*1}=\frac{126}{2}

=63

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Y^2-38y-1575=0by completing square​

Solution for x2-38x-1575=0 equation:

x2-38x-1575=0

We add all the NUMBERS together, and all the variables

X^2-38x-1575=0

a = 1; B = -38; c = -1575;

Δ = b2-4ac

Δ = -382-4·1·(-1575)

Δ = 7744

The delta value is higher than zero, so the equation has TWO solutions

We use following formulas to calculate our solutions:

x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{7744}=88

x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-88}{2*1}=\frac{-50}{2}

=-25

x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+88}{2*1}=\frac{126}{2}

=63

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Y^2-38y-1575=0by completing square