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Y a+b+c=0then valueof2СІ6²t+cbecaab |
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Answer» Step-by-step explanation: ab+bc+ca=0 bc=−ca−ab bc=−a(b+c)---eq1 like WISE, ab=−c(a+b)---eq2 & ca=−b(c+a)---eq3 = a −bc 1
+ b 2 −ca 1
+ c 2 −ab 1
TAKING the value from eq1, 2&3 = a 2 +a(b+c)1 + b 2 +b(a+c)1 + c 2 +c(a+b)1= a(a+b+c)1+ b(a+b+c)1+c(a+b+c)1=abc(a+b+c+ab+bc+ca)
As ab+bc+ca=0 So, =0 |
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