1.

Y=log(√1+cos (5x÷2)÷1-cos(5x÷2) ​

Answer»

ANSWERIf y=LOG 1+cos3x1−cos3x y=log( 1+cos3x1−cos3x ) 1/2 y= 21 [log(1−cos3x)−log(1+cos3x)]DIFFERENTIATE w.r. to X both sidesdxdy = 21 [ 1−cos3x1 (3sin3x)− 1+cos3x−3sin3x ]dxdy = 23sin3x [ 1−cos3x1 + 1+cos3x1 ]dxdy = 23sin3x [ (1−cos3x)(1+cos3x)1+cos3x+1−cos3x ]dxdy = 23sin3x × 1−cos 2 3x2 dxdy = 1−cos 2 3x3sin3x dxdy = sin 2 3x3sin3x = sin3x3 =3cosec 3X.



Discussion

No Comment Found

Related InterviewSolutions