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`y=logtan(x/2)+sin^(-1)(cosx)`, then `dy/dx` isA. `cosec x-1`B. `cosec x`C. `cosec x+1`D. x |
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Answer» Correct Answer - A `(dy)/(dx)=(1)/(tan x//2)sec ^(2)""(x)/(2)*(1)/(2)+ (1)/(sqrt(1 - cos^(2) x))"(-sin x)"` `(1)/(2sin ""(x)/(2)*cos ""(x)/(2))1=cosecx-1` |
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