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Y=sin^2x^2 – cos^2 x^2 find dy/dx |
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Answer» Answer: From the given y = sin 2 x + cos 2 x
The right side of the equation is = 1
y = 1
d y d x = d d x ( 1 ) =
or we can do it this way. y = sin 2 x + cos 2 x
d y d x = 2 ⋅ ( sin x ) 2 − 1 ⋅ d d x ( sin x ) + 2 ( cos x ) 2 − 1 d d x ( cos x ) d y d x = 2 ⋅ sin x ⋅ cos x + 2 ⋅ cos x ⋅ ( − sin x )
d y d x = 2 ⋅ sin x ⋅ cos x − 2 ⋅ sin x ⋅ cos x
d y d x = 0 |
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