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, यदि (४+४), बहुपद 2 + 2x +57 + 10 का एक गुणनपर हो, तो ।। का मान जाए।fo |
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Answer» Given,(x + a) is root of equation 2x^2 + 2ax + 5x + 10 Then,For x = - a equation should be equal to zero 2(-a)^2 + 2a*(-a) + 5*(-a) + 10= 0 2a^2 - 2a^2 - 5a + 10 = 0 5a = 10 a = 10/5 = 2 Therefore,Value of a = 2 |
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