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यदि `alpha` और `beta` धनात्मक कोण है `sin(4alpha-beta)=1` और `cos(2alpha+beta)=(1)/(2)` है तो `sin(alpha+2beta)` का मान ज्ञात करे? |
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Answer» Correct Answer - d `sin(4alpha-beta)=1=sin90^(@)` `cos(2alpha+beta)=(1)/(2)=cos60^(@)` `ralpha-beta=90^(@)` ` 2alpha+beta=60^(@)` adding `6alpha=150^(@)` `alpha=25 ^(@)` `rArr beta=10^(@)` `rArrsin(alpha+2beta)` `rArrsin(25^(@)+2xx10^(@))` `rArr45^(@)=(1)/sqrt(2)` |
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