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यदि `sinthetaxxcostheta=1//2` हो, तो `sintheta-costheta` का मान क्या होगा, जहाँ `0^(@)ltthetalt90^(@)` |
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Answer» Correct Answer - a `sin thetaxx cos theta=(1)/(2)` Multiply by 2 both side `2sin theta cos theta=1` `sin theta=2` `sin 2theta=sin90^(@)` `2theta=90^(@)` `2theta=45^(@)` `theta=45^(@)` So, `sin theta-cos theta` `=sin45^(@)-cos45^(@)` `=(1)/sqrt(2)-(1)/sqrt(2)` |
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