1.

यदि `theta` एक न्यूनकोण है और `tan(4theta-50^(@))=cot(50^(@)-theta)` है तो `theta` का मान ज्ञात डिग्री में क्या होगा?A. 30B. 40C. 50D. 20

Answer» Correct Answer - a
We know that
`tan (90^(@)-theta)=cot theta`
and `cot(90^(@)-theta)=tan theta`
`rArrcot(90^(@)-(4theta-50^(@))=cot(50^(@)-theta)`
`rArr90^(@)-(4theta-50^(@))=50^(@)-theta`
`rArr90^(@)-4theta+50^(@)=50^(@)-theta`
`rArr90^(@)=3theta`
then `theta=30^(@)`


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