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यदि `x=a cos^(3)t` और `y=a sin^(3)t` तो `(dy)/(dx)` ज्ञात कीजिए । |
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Answer» `x=acos^(3)t` `(dx)/(dt)=a. (d)/(dt)(cost)^(2)=3a cos^(2)t.(d)/(dt)(cost)` `=-3acos^(2)t.sint` और `" "y=asin^(3)t` `rArr" "(dy)/(dt)=a.(d)/(dt)(sint)^(3)` `=a.3sin^(2)t.(d)/(dt)sint=3asin^(2)t cost` अब `" "(dy)/(dx)=(dy//dt)/(dx//dt)=(3a sin^(2)t cost)/(-3a cos^(2)t.sint)=-tant` |
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