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यदि `x=a(theta+sin theta),y=a(1-cos theta)` तो `theta=(pi)/(2)` पर `(d^(2)y)/(dx^(2))` ज्ञात करें | |
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Answer» दिया है, `x=a(theta+sin theta)implies(dx)/(d theta)=a(1+cos theta)" "...(1)` तथा `y=a(1-cos theta)implies(dy)/(d theta)=a sin theta" "...(2)` अब `" "(dy)/(dx)=(dy//d theta)/(dx//d theta)=(a sin theta)/(a(1+cos theta))=(2sin""(theta)/(2)cos""(theta)/(2))/(2 cos^(2)""(theta)/(2))=tan""(theta)/(2)` `implies" "(d^(2)y)/(dx^(2))=(d)/(dx)(tan""(theta)/(2))=(d)/(d theta)(tan""(theta)/(2)).(d theta)/(dx)` `=(1)/(2)sec^(2)""(theta)/(2)//(dx)/(d theta)=((1)/(2)sec^(2)""(theta)/(2))/(a(1+costheta))` `theta=(pi)/(2)" पर "(d^(2)y)/(dx^(2))=(1)/(2)sec^(2)""(pi)/(4).(1)/(a(1+cos""(pi)/(2)))=(1)/(a)` |
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