यदि `x=sin^(-1).(2t)/(1+t^(2))` और `y=tan^(-1).(2t)/(1-t^(2)),` तो `(dy)/(dx)` ज्ञात कीजिए ।

यदि `x=sin^(-1).(2t)/(1+t^(2))` और `y=tan^(-1).(2t)/(1-t^(2)

1.	यदि `x=sin^(-1).(2t)/(1+t^(2))` और `y=tan^(-1).(2t)/(1-t^(2)),` तो `(dy)/(dx)` ज्ञात कीजिए ।
Answer» `x=sin^(-1).(2t)/(1+t^(2))` `=sin^(-1).(2tan theta)/(1+tan^(2)theta)" माना "t=tan theta` `=sin^(-1)(sin2theta)` `=2theta=2 tan^(-1)t` `rArr" "(dx)/(dt)=(2)/(1+t^(2))` और `" "y=tan^(-1).(2t)/(1-t^(2))=2tan^(-1)t` `rArr" "(dy)/(dt)=(2)/(1+t^(2))` `therefore" "(dy)/(dx)=(dy//dt)/(dx//dt)=(2(1+t^(2)))/(2//(1+t^(2)))=1`