InterviewSolution
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यदि ` y= (ax) ^((ax)^((ax)^...infty)),` तब सिद्ध कीजिये की ` " "(dy)/(dx) =(y^(2))/(x(1-ylog ax ))` |
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Answer» ` y= (ax)^(y) rArr " "log y= ylog ax ` `" "rArr " "(1)/(y)(dy)/(dx) =(dy)/(dx) log ax + y*(a)/(ax)` अब सरल करने पर| |
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