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यदि ` y= tan ^(-1) ""(cos x)/(1+sin x ),` तो `(dy)/(dx) ` का मान ज्ञात कीजिए| |
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Answer» हम जानते है की ` cos x =sin ((pi)/(2)-x)` तथा ` " "sin x =cos ""((pi)/(2)-x)` ` therefore " "y=tan ^(-1)"" (cos x )/(1+sin x )=tan ^(-1)"" (sin ""((pi)/(2)-x))/(1+cos ((pi )/(2)-x))` ` " "= tan ^(-1) ""(2sin ((pi)/(4) -(x)/(2) )cos ((pi)/(4)-(x)/(2)))/(2cos ^(2) ((pi)/(4)-(x)/(2)))` `" "= tan ^(-1) [tan ((pi)/4-(x)/(2) )] =(pi)/(4)-(x)/(2) ` ` therefore " "(dy)/(dx) =(d)/(dx) ((pi)/(4)-(x)/(2))=(d)/(dx) ((pi)/(4))-(d)/(dx) ((x)/(2))=-(1)/(2)` |
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