1.

You are given 10 resistors each of resistance 2 Omega. First they are connected to obtain possible minimum resistance. Then they are connected to obtain possible maximum resistance. The ratio of maximum and minimum resistance is .... .

Answer»

100
10
2.5
25

Solution :100
Minimum RESISTANCE : `R_("max")= 10 xx 2 = 20 Omega`
Minimum resistance : `R_("MIN") = (2)/(10)= 0.2 Omega`
`THEREFORE (R_("max"))/(R_("min")) = (20)/(0.2) = 100`


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