1.

You are given a 2 mu F parallel plate capacitor. How would you establish an instantaneous displacement current of 1mA in the space between its plates ?

Answer»

Solution :Charge on PLATE,
q = CV
`I_(d)dt=CdV`
`therefore I_(d)=C(dV)/(dt)`
`therefore (dV)/(dt)=(I_(d))/(C )=(10^(-3))/(2xx10^(-6))`
`therefore (dV)/(dt)=500(V)/(s)`
By APPLYING variable p.d. of `500(V)/(s)` we can obtain displacement CURRENT of desired value.


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