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You are to compare two resistance that are in the ratio 1:2. The wire of metre bridge given is of length 99 cm only. With full calculations explain how the error is minimized by taking additional readings with resistance interchanged. |
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Answer» Solution :`R/2 = 1/2 = l/(99-l) ` GIVES `l= 33 CM` But we read the lengths as `l=33` cm and 100-33 = 67 cm and WRITE `R/S = (33)/(67) = 0.4925` Now , then we interchange the resistances, we shouldhave `R/S = 2/1 = l/(99-l) ` which gives `l= 66` cm - But we read lengths as `l= 66` cm and 100 - 66 = 32 cm and write `R/S = (66)/(34) ` or R/S = (34)/(66)=0.5152` is 0.5038 and is very close to `1/2` |
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