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Young's double slit experiment is carried out using microwaves of wavelength lamda = 3 cm. Distance between the slits is d = 5 cm and the distance between the plane of slits and the screen is D= 100cm. (a) Find the number of maximas and (b) Their positions on the screen. |
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Answer» Solution :(a) Since `d sin THETA = n lamda rArr sin theta = (n lamda)/(d) LT= 1` `therefore n lt= d/lamda = 5/3 = 1.6` maximum number of maxima are (2 [n]+1)= 3. Thus, in this case we can have only THREE maximas, one central maxima and two on its either side.  (b) The position of nth maxima `y = (n lamda D)/(d)` for n = 1 `y =(lamda D)/(d) = (3 XX 100)/(5) = 60CM` Thus, the three maximas will be at y = 0 and y = `pm60cm` |
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