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Young's double slit experiment is made in a liquid . The 10th bright fringe in liquid lies where 6th dark fringe lies in vacuum. The refractive index of the liquid is approximately . |
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Answer» Solution :FRINGE width `beta = (lambda D)/(d)`. When the apparatus is IMMERSED in a LIQUID,`lambda ` and hence `beta `is REDUCED`mu`(refractive index) TIMES. `10 beta . = (5.5) beta or 10 lambda. ((D)/(d)) =(5.5) (lambda D)/(d)` or`(lambda)/(lambda.) = (10)/(5.5) = mu or mu = 1.8` |
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