1.

Your are given the following group of particles, `n_(i)` represents the number of molecules with speed `v_(i)` `(P_(2))/(P_(1))=(m_(2))/(m_(1)) : (p_(2))/(76)=(m_(1)+(50)/(100)m_(1))/(m_(1))=(3)/(2)` calculate (i) average speed (ii) rms speed (iii) most probable speed.

Answer» `v_(ang)=(n_(1)v_(1)+n_(2)v_(2)+n_(3)v_(3)+n_(4)v_(4)+n_(5)v_(5))/((n_(1)+n_(2)+n_(3)+n_(4)+n_(5)))`
`=((2xx1)+(4xx2)+(8xx3)+(6xx4)+(3xx5))/((2+4+8+6+3))`
`=(73)/(23)=3.17ms^(-1)`
(ii) root mean square speed is
`v_(rms)=((n_(1)v_(1)^(2)+n_(2)v_(2)^(2)+n_(3)v_(3)^(2)+n_(5)v_(5)^(2))/(2+4+8+6+3))^(1//2`
`=3.36 ms^(-1)`
(iii) By definition, most probable speed `=3.0ms(-1)`.


Discussion

No Comment Found

Related InterviewSolutions