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`z_1 and z_2`, lie on a circle with centre at origin. The point of intersection of the tangents at`z_1 and z_2` is given by |
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Answer» `|Z_2|^2+|Z_3-Z_2|^2=|Z_3|^2` `|Z_1|^2+|Z_3-Z_1|^2=|Z_3|^2` `Z_2Z_2+(Z_3-Z_2)*(Z_3-Z_2)=Z_2Z_3` `Z_2Z_2+Z_3Z_3-Z_2Z_3-Z_3Z_2=Z_3Z_3` `2Z_2-Z_3-Z_3Z_2/Z_3=0-(1)` `2Z_1-Z_3-Z_3Z_1/Z_2=0-(2)` subtracting equation 2 from equation 1 `2(Z_2-Z_1)-Z_3(Z_2/Z_2-Z_1/Z_1)=0` `Z_3=(2(Z_2-Z_1)Z_1Z_2)/(Z_1Z_2-Z_1Z_2)` option b is correct. |
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