1.

""_(Z)X^(M)+""_(2)He^(4)to""_(15)P^(30)+""_(0)n^(1). Then

Answer»

Z=12, M=27
Z=13, M=27
Z=12, M=17
Z=13, M=28

Solution :`""_(Z)X^(M)+""_(2)H^(4)to""_(15)P^(30)+""_(0)N^(1)`
Z=15-2=13. M=31-4=27.
`""_(13)X^(27)+""_(2)He^(4)to""_(15)P^(30)+""_(0)n^(1)`.


Discussion

No Comment Found