Related InterviewSolutions

• Factorise by splitting middle term(i) 3x2 + 7x + 2(ii) 4x2 – x – 3(iii)12x2 – 7x + 1(iv) 6x2 + 5x – 6
• Determine which of the following polynomials has x – 1 factor.(i) x4 – 2x3 – 3x2 + 2x + 2(ii) x4 + x3 + x2 + x + 1(iii) x4 + 3x3 – 3x2 + x – 2(iv) x3 – x2 – (2 + √3)x + √3
• Find the value of k, when x – 5 is a factor of x3 – 3x2 + kx – 10.
• Verify that 1 is not a zero of the polynomial 4x4 – 3x3 + 2x2 – 5x + 1.
• Zero of the polynomial p(x) = √3x + 3 is(A) - √3(B) - √3/3(C) 3/√3(D) 3√3
• If 3a – 2b = 11 and ab = 12, then find the value of 27a3 – 8b3.
• If ax3 + bx2 + x – 6 has x + 2 as a factor and leaves a remainder 4 when divided by (x – 2), find the values of a and b.
• Use factor theorem, show that (x + √2) is a factor of (2√2x2 + 5x + √2).
• For what values of a and b so that the polynomial x3 + 10x2 + ax – 6 is exactly divisible by (x – 1) and (x + 2).
• If the polynomials (3x3 + ax2 + 3x + 5) and (4x3 + x2 – 2x + a) leaves the same remainder when divided by (x – 2), find the value of a. Also the find the remainder in each-case.