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Zinc reacts with dilute `H_(2)SO_(4)` to give `H_(2)`. It also reacts with conc. `H_(2)SO_(4)` to give `SO_(2)` . How will you account for this difference ? |
Answer» Dilute `H_(2)SO_(4)` behaves as a proton acid and zinc metal displaces hydrogen from the acid. `Zn+H_(2)SO_(4)("dil")to ZnSO_(4)+H_(2)` Concentrated `H_(2)O_(4)` behaves as a strong oxidising agent and itself is reduced to `SO_(2)`. `Zn +2H_(2)SO_(4) ("conc.")to ZnSO_(4)+SO_(2)2H_(2)O`. |
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