Zn reacts with dilute HNO3,Conc.HNO3 and very dilute HNO3. The oxidati – InterviewSolution

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1.	Zn reacts with dilute HNO3,Conc.HNO3 and very dilute HNO3. The oxidation number of nitrogen changes from HNO3 are a,b,c in product X,Y,Z respectively. What is the value of (a+b+c) is (a) Zn+HNO3→Zn(NO3)2+"X"+H2O dilute (20%) (b) Zn+HNO3→Zn(NO3)2+"Y"+H2O Conc (70%) (a) Zn+HNO3→Zn(NO3)2+"Z"+H2O very dilute (6%)
Answer» Zn reacts with dilute $H N O_{3}, C o n c . H N O_{3}$ and very dilute $H N O_{3}$ . The oxidation number of nitrogen changes from $H N O_{3}$ are $a, b, c$ in product $X, Y, Z$ respectively. What is the value of $(a + b + c)$ is (a) $Z n + H N O_{3} \to Z n (N O_{3})_{2} + " X " + H_{2} O$ dilute ( $20 %$ ) (b) $Z n + H N O_{3} \to Z n (N O_{3})_{2} + " Y " + H_{2} O$ Conc ( $70 %$ ) (a) $Z n + H N O_{3} \to Z n (N O_{3})_{2} + " Z " + H_{2} O$ very dilute ( $6 %$ )

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