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Zubin factorized the algebraic expression 20x2 + 5xy2 – 25xyz as given below. In which step did he make the first mistake?Step 1: 5 x 2 x 2 x x x x + 5 x x x y xy-5 5 x x x y zStep 2: 5 x x(2 x 2 x x + y xy-5xy X z)Step 3: 5x(4x + y2 – 5yz)(A) Step 1(B) Step 2(C) Step 3(D) All the steps are correct |
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Answer» n :- → 20x² + 5xy² – 25xyzstep 1) of Zubin :- 5 * 2 * 2 * x * x + 5 * x * y * y - 5 * 5 * x * y * zcorrect .step 2) of Zubin :- 5X * (2 * 2 * x + y * y - 5xy * z) wrong . correct one should taking 5x common we get, 5x(2 * 2 * x + y * y - 5 * y * z) step 3) of Zubin :- 5x(4x + y² - 5yz) .correct .THEREFORE, we can CONCLUDE that, Zubin made mistake in second step. LEARN more :- if a nine digit number 260A4B596 is DIVISIBLE by 33, Then find the number of possible values of A. brainly.in/question/32686002if n is an integer such that 1nn352 is a six digit number brainly.in/question/26617043 |
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