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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
An inorganic compound (A) made of two most occuring elements into the earth crust, having a polymeric tera-hederal network structure. With carbon, compound (A) produces a poisonous gas (B) which is the most stable diatomic molecule. Compounds (A) and (B) will beA. `SiO_(2), CO_(2)`B. `SiO_(2), CO`C. `SiC, CO`D. `SiO_(2)N_(2)` |
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Answer» Correct Answer - B |
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| 52. |
Which of the following statement (s) is/are correct regarding graphite and inorganic graphite ?A. All atoms in graphite as well as inorganic graphite are `sp^(2)` hybridised.B. Graphite is not having any charge separation like inoraganic graphite.C. Both are slippery in natureD. Both are conducting electricity but graphite is less conducting in nature compared to inorganic graphite. |
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Answer» Correct Answer - A::B::C |
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| 53. |
Which of the following statements regarding graphite is not correct ?A. It is a good conductor of electricityB. It is denser than diamondC. It is oxidised to `C_(6)(COOH)_(6)` with alkaline `KMnO_(4)`D. It is thermodyanamically more stable than diamond |
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Answer» Correct Answer - B |
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| 54. |
Which of the following is correct statement regarding `N(CH_(3))_(3)` and `N(SiH_(3))_(3)`?A. `Sp^(3)` with pyramidal shape in `(CH_(3))_(3)N` and `Sp^(2)` with planar triangular shape in `(SiH_(3))_(3)N`B. In both `(CH_(3))_(3) N` and `(SiH_(3))_(3)N`, the hybridzation of N is `Sp^(3)` are both are pyramidal in shapeC. In both `(CH_(3))_(3)N` and `(SiH_(3))_(3)N`, the hybridzation of N is `Sp^(2)` are both are planar triangular in shapeD. `Sp^(2)` with planar triangular shape in `(CH_(3))_(3) N` and `Sp^(3)` with tetrahedral shape in `(SiH_(3))_(3)N` |
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Answer» Correct Answer - A |
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| 55. |
The length of the `N - Si` bond in `(SiH_(3))_(3) N` is shorter than what is normally expected for an `N - Si` single bond. This is due toA. `Sp^(2) - Sp^(2) sigma` overlap between N and Si atomsB. Localized `p pi - d pi` bonding between the N atom and one of the three Si atomsC. Delocalized four-centred two -electron `p pi - d pi` bonding spread over the N-atom and all the three Si atomsD. Localized `p pi - d pi` bonding between the N atom and one of the one Si atoms |
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Answer» Correct Answer - C |
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| 56. |
The hybridization state of nitrogen atoms in the molecules `(SiH_(3))_(3)N` and `(CH_(3))_(3) N` areA. both `sp^(3)`B. respectively `sp^(2)` and `sp^(3)`C. respectively `sp^(3)` and `sp^(2)`D. both `sp^(2)` |
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Answer» Correct Answer - B |
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| 57. |
Trisilyamine `(SiH_(3))_(3)` N isA. trigonal pyramidal and acidicB. trigonal pyramidal and basicC. trigonal pyramidal and neutralD. trigonal planar and weakly basic |
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Answer» Correct Answer - D |
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| 58. |
The silicons ae organosilicon polymers containing `Si-O-Si` linkage. They are usually prepared by hydrolysis of alkylchlorosilanes, the silanols formed as intermediates on hydrolysis condense by intermolecular elimination of water with the formation of `Si-O-Si` linkage `underset(-O-Si(CH_(3))_(2)-O-Si(CH_(3))-O-Si(CH_(3))_(2)-O-)underset(|)underset(O)underset(|)(-O-Si(CH_(3))_(2)-O-Si(CH_(3))-O-Si(CH_(3))_(2)-O-)` The above silicone can be obtained by hydrolysis of which of the following ?A. `(CH_(3))_(3)SiCl`B. `CH_(3)SiCl+(CH_(3))_(3)SiCl`C. `(CH_(3))_(2)SiCl_(2)`D. `CH_(3)SiCl_(3)+(CH_(3))_(2)SiCl_(2)` |
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Answer» Correct Answer - D |
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| 59. |
Diamond is formed by the fussion of several carbon tetrahedrons in which carbon atoms in each ring is |
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Answer» Correct Answer - 6 |
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| 60. |
The order of the stability of dihalides of Si, Ge, Sn and Pb changes in sequenceA. `SiX_(2) lt lt SnX_(2) lt lt GeX_(2) lt lt PbX_(2)`B. `SiX_(2) lt lt GeX_(2) lt lt SnX_(2) lt lt PbX_(2)`C. `PbX_(2) lt lt SnX_(2) lt lt GeX_(2) lt lt SiX_(2)`D. `GeX_(2) lt lt SiX_(2) lt lt PbX_(2) lt lt SnX_(2)` |
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Answer» Correct Answer - B |
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| 61. |
What is the coordinates no. of Sn in crystalline layer structure of solid `SnF_(4)`? |
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Answer» Correct Answer - 6 |
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| 62. |
Which of following is a correct setA. Graphite, `SP^(2)`B. Diamond, `SP^(2)`C. Graphite, `SP^(3)`D. Diamond, SP |
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Answer» Correct Answer - A |
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| 63. |
In the following sub quenstions, choose the correct answer from among the following possibilities and select correct code of your answer (Answer of 1, 2, 3 and 4 respectively) 1) the most stable low valent halide (1) `GeCl_(2) (2)SnCl_(2) (3) PbCl_(2)`. 2) A non existing halide (1) SnCl_(4) (2) PbCl_(4) (3) PbI_(4)`. 3) A purely acidic oxide (1) PbO_(2) (2)SnO_(2) (3) SiO_(2)` 4) Thermally most stable hydride (1) `NH_(3) (2) PH_(3) (3) AsH_(3)`.A. 3, 2, 1, 3B. 1, 3, 3, 1C. 3, 3, 3, 1D. 1, 1, 1, 3 |
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Answer» Correct Answer - C |
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| 64. |
Decreasing order of "P" orbital Character in the following a) `SiO_(2)` , `CO_(2)` , c) GraphiteA. `a gt b gt c`B. ` b gt a gt c`C. `b gt c gt a `D. `a gt c gt b` |
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Answer» Correct Answer - D |
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| 65. |
Which is the anhydride of orthosilicic acidA. SiB. SiOC. `SiO_(2)`D. SiO_(3)` |
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Answer» Correct Answer - C |
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| 66. |
The anhydride of carbonic acid `H_(2) CO_(3)` isA. `C_(2)O_(2)`B. CO_(2)O_(2)`C. `CO_(2)`D. CO |
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Answer» Correct Answer - B |
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| 67. |
Silicones are group of organo silicon polymer, select correct statement (s) about them.A. `R_(3)SiCl` produce very complex cross linked polymeric silicones on hydrolysisB. Their water repellency arises because silicone chain is surrounded by organic side groupsC. Their strength and inertness are related to their stable silica like skeleton of `underset(|)overset(|)(-Si)-O-overset(|)underset(|)(Si)-Ooverset(|)underset(|)(-Si-)`D. Hydrolysis product of `CH_(3)SiCl_(3)` will block the end of the straight chain produce by hydrolysis of `(CH_(3))_(2)SiCl_(2)` |
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Answer» Correct Answer - B::C |
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| 68. |
The compound E isA. COB. `CO_(2)`C. `C_(3)O_(2)`D. oxide of metal |
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Answer» Correct Answer - A |
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| 69. |
The correct statement about F isA. it has `3 sigma` and `2 pi` bondB. it has `3 sigma` bond and one `pi` bondC. it has angular shapeD. it is CO gas |
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Answer» Correct Answer - A |
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| 70. |
The compound H isA. `CO_(2)`B. `CO`C. `CaO`D. `Ca(OH)_(2)` |
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Answer» Correct Answer - A |
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| 71. |
The compound E isA. `HCOONa`B. ` underset(COONa)underset(|)(COONa)`C. `underset(COOH)underset(|)(COOH)`D. `H - COOH` |
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Answer» Correct Answer - B |
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| 72. |
The compound H isA. `Ca(HCO_(3))_(2)`B. `Ca(OH)_(2)`C. `CaCO_(3)`D. `CaCl_(2)` |
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Answer» Correct Answer - A |
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| 73. |
Which of the following is cross link formation linkage in slicones ?A. `(CH_(3))_(3)Si-O-`B. `underset(|)underset(O)underset(|)((CH_(3))_(2)Si-O-)`C. `underset(|)underset(O)underset(|)overset(|)overset(O)overset(|)((CH_(3))Si-O-`D. `underset(CH_(3))underset(|)overset(CH_(3))overset(|)(-CH_(2)-Si-CH_(2)-)` |
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Answer» Correct Answer - C |
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| 74. |
Oftern aground glass stropper gets stuck in the neck of a glass bottle containing`NaOH` solution . This is due to ,A. The presence of dirt particles in betweenB. The formation of solid silicate in between by the reaction of `SiO_(2)` of glass with NaOHC. The formation of `Na_(2)CO_(3)` in between by the reaction of `CO_(2)` of air and NaOHD. Glass contains a boron compound which forms a ppt with the NaOH solution |
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Answer» Correct Answer - B |
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| 75. |
Which of the following statements is correct ?A. Graphite is thermodynamically more stable than diamondB. Diamond is thermodynamically more stable than graphiteC. Graphite has such a hgih thermodynamically stability that diamond spontaneously chages into graphite under ordinary conditions.D. Graphite and diamond have equal thermodynamic stability. |
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Answer» Correct Answer - A::B::C::D |
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| 76. |
An inorganic compound (X) on hydrolysis produces a gas which on treatment with sodium followed by its reaction with ethyl chloride forms another compound (Y). Compound (Y) on heating with Pd catalyst gives (2Z)-pent-2-ene as major product. Hence the inorganic compound (X) isA. `Tl_(4)C`B. `BaC_(2)`C. `SiC`D. `Mg_(2)C_(3)` |
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Answer» Correct Answer - D |
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| 77. |
The tetravalent elements A and B form dioxides both react with NaOH to form similar salts `angleOAO " is " 180^(0) " is " 109^(0) 28^(I)`. Both are acidic in nature A and B are respectivelyA. Ge and SiB. S and SiC. C and SiD. Si and C |
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Answer» Correct Answer - C |
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| 78. |
The material used in solar cells containsA. CsB. SiC. SnD. Ti |
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Answer» Correct Answer - B |
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| 79. |
Consider following three compounds: (i) `C_(x)O_(y)` (ii) `C_(x) O_(y+ 1)` (iii) `C_(x + 2) O_(y + 1)` If `x = y = 1`, then calcuate the value of `|p - q|`, where p and q are total number of `sp^(2)` and sp hybridised carbon atoms respectively in given three compounds. |
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Answer» Correct Answer - 5 |
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| 80. |
Match the following |
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Answer» Correct Answer - A-r, B-s, C-p, D-q |
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| 81. |
Which of the following exists as covalent crystals in the solid state?A. IodineB. SiliconC. SulphurD. Phosphorous |
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Answer» Correct Answer - B |
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| 82. |
Silicones are used as.A. ConductorsB. InsulatorsC. SemiconductorsD. To prepare graphite |
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Answer» Correct Answer - B |
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| 83. |
Match the following |
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Answer» Correct Answer - A-p, B-q, C-p, D-s |
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| 84. |
`RCIunderset(Si)overset(cu-powder)toR_(2)SiCL_(2)overset(H_(2)O)toR_(2)Si(OH)_(2)overset(condensation)toA` Compound (A) isA. a linear siliconeB. a chlorosilaneC. a linear silaneD. a network silicon |
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Answer» Correct Answer - A |
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| 85. |
Which of the following is correct about silicones ?A. Silicones are organo silicon compounds containing `Si = O = Si` linkageB. `R_(3)SiCl` on hydrolysis and on subsequent polymerisation gives linear siliconesC. When water is eliminated from the terminal `-OH` groups of linear silicones, cross linked silicones are formedD. `RSiCl_(3)` on hydrolysis and on subsequent polymerisation gives cross linked silicones |
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Answer» Correct Answer - D |
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| 86. |
Which of the following is the correct order of reducing power of hydrides ?A. `CH_(4) lt SiH_(4) lt GeH_(4) lt SnH_(4) lt PbH_(4)`B. `CH_(4) gt SiH_(4) GeH_(4) gt SnH_(4) gt PbH_(4)`C. `CH_(4) gt GeH_(4) gt SiH_(4) gt PbH_(4) gt SnH_(4)`D. `SiH_(4) lt CH_(4) lt SnH_(4) lt GeH_(4) lt PbH_(4)` |
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Answer» Correct Answer - A::B::C::D |
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| 87. |
Which of the following is incorrect statement ?A. Graphite is thermodynamically more stable than diamondB. Graphite is oxidized to mellitic acid when treated with alkaline `KMnO_(4)`C. Diamond is chemically inert than graphiteD. `Sn^(+2)` ion is more stable than `Pb^+2)` |
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Answer» Correct Answer - D |
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| 88. |
The correct order of thermal stability of silicon tetrahalides isA. `SiF_(4) lt SiCl_(4) lt SiBr_(4) lt SiI_(4)`B. `SiF_(4) gt SiCl_(4) gt SiBr_(4) gt SiI_(4)`C. `SiF_(4) lt lt SiCl_(4) lt SiBr_(4) lt SiI_(4)`D. `SiF_(4) lt SiCl_(4) lt SiBr_(4) lt lt SiI_(4)` |
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Answer» Correct Answer - B |
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| 89. |
Select correct order about stability of cationsA. `Ge^(4+) gt Sn^(4+) gt Pb^(4+)`B. `Ge^(2+) gt Pb^(4+) lt Pb^(2+)`C. `Pb^(2+) gt Pb^(4+), Sn^(4+) gt Sn^(2+)`D. All are correct statements |
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Answer» Correct Answer - D |
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| 90. |
Which of the following is/are correctly matched ?A. `Be_(3)Al_(2)[Si_(6)O_(18)]`-cyclic silicateB. `Be_(2)[SiO_(4)]`- neso silicateC. `Sc_(2)[Si_(2)O_(7)]`- pyrosilicateD. `Ca_(3)[Si_(3)O_(9)]` - cyclic silicate |
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Answer» Correct Answer - A::B::C::D |
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| 91. |
Which of the following statement is/are correct regarding the compounds of carbon family elements ?A. Maximum co-ordination number of carbon is commonly occuring compounds is 4, whereas that of silicon is 6.B. The stability order of group 14 dihalides is `SiX_(2) lt GeX_(2) lt SnX_(2) lt PbX_(2)`C. The order of boiling point of hydrides of group 14 element is `CH_(4) lt SiH_(4) lt GeH_(4) lt SnH_(4)`D. `MeSiCl_(3)` on hydrolysis and subsequent condensation will produce `(Me)Si(OH)_(3)` |
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Answer» Correct Answer - A::B::C |
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| 92. |
The number of Carbon compounds is very large because itA. Is tetravalentB. Forms double and triple bondC. Is non metalD. Shows Catenation |
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Answer» Correct Answer - D |
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| 93. |
Which is not correct ?A. `GeO_(2)` is amphotericB. `SiO_(2)` is acidic oxideC. `SnCl_(4)` is more stable than `SnCl_(2)`D. `PbCl_(4)` is more stable than `PbSl_(2)` |
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Answer» Correct Answer - D |
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| 94. |
The silicons ae organosilicon polymers containing `Si-O-Si` linkage. They are usually prepared by hydrolysis of alkylchlorosilanes, the silanols formed as intermediates on hydrolysis condense by intermolecular elimination of water with the formation of `Si-O-Si` linkage Which of the following is not the property of silicone?A. They are thermally stableB. They are having high volatialityC. They are having water repellant propertyD. They are electric insulators |
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Answer» Correct Answer - B |
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| 95. |
The silicons ae organosilicon polymers containing `Si-O-Si` linkage. They are usually prepared by hydrolysis of alkylchlorosilanes, the silanols formed as intermediates on hydrolysis condense by intermolecular elimination of water with the formation of `Si-O-Si` linkage To get the silicone of `R_(3)Si-(O SiR_(2)_(n)-SiR_(3)`, having 4 SiO-Si linkage, the unit taken isA. 3 unit of `R_(3)SiCl` and 2 unit `R_(2)SiCl_(2)`B. 3 unit of `R_(2)SiCl_(2)` and 2 unit `R_(3)SiCl`C. 2 unit of `R_(2)SiCl_(2)` and 2 unit `R_(3)SiCl`D. 4 unit of `R_(3)SiCl_(2)` and 2 unit `R_(3)SiCl` |
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Answer» Correct Answer - B |
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| 96. |
`SiO_(2) + 3 H_(2)F_(2) to X + 2H_(2)O` During the formation of X an intermediate product Y is formed. Hybridisation of central atom in X and Y respectively :A. `sp^(3) d^(2), sp^(3)`B. `sp^(3) d, sp^(3)d^(2)`C. `sp^(3)d,sp^(2)`D. `sp^(3)d^(2), sp^(2)` |
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Answer» Correct Answer - A::B::C::D |
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| 97. |
In `SiF_(6)^(-2)` because of small size of FA. `SiF_(6)^(-2)` because of small size of FB. `SiF_(6)^(-2)` because of large size of FC. `SiCl_(6)^(-2)` because of small size of ClD. `SiCl_(6)^(-2)` because of large size of Cl |
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Answer» Correct Answer - A::B::C::D |
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| 98. |
Among the following substituted silanes, the one which will give rise to cross `` linkes silicons polymer on hydrolysis isA. `R_(3)SiCl`B. `R_(4)Si`C. `RSiCl_(3)`D. `R_(2)SiCl_(2)` |
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Answer» Correct Answer - C |
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| 99. |
Which is not correctA. `Ge(OH)_(2)` is amphotericB. `GeCl_(2)` is more stable than `GeCl_(4)`C. `GeO_(2` is weakly acidicD. `GeCl_(4)` in Hcl forms `[GeCl_(2)]^(2-)` ion |
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Answer» Correct Answer - B |
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| 100. |
The order of catenation power isA. `C gt Si gt Ge gt Sn`B. `Si gt C gt Ge gt Sn`C. `Sn gt Ge gt Si gt C`D. `Ge gt Sn gt C gt Si` |
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Answer» Correct Answer - A |
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