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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
End product of the following sequence of reaction is A. B. `##ALN_CHM_C09(II)_E01_537_O02.png" width="30%">C. `##ALN_CHM_C09(II)_E01_537_O03.png" width="30%">D. `##ALN_CHM_C09(II)_E01_537_O04.png" width="30%"> |
| Answer» Correct Answer - D | |
| 202. |
Which one of the following methods is neither meant for the synthesis nor for separation of amines ?A. Hofmann methodB. Hinsberg methodC. Curtius reactionD. Wurtz reaction |
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Answer» Correct Answer - D Wurtz reaction `Rxx(Na)/("dry ether")rarrR-R+NaX` |
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| 203. |
Indicate wrong electron-migration : |
| Answer» Correct Answer - (III) | |
| 204. |
Indicate the compound which can be nitrated most easily : |
| Answer» Correct Answer - (i) ; because `-CH_(3)` is an activating group hence toluene is most reactive. | |
| 205. |
Among the following compounds which can be dehydrated very easily is-A. `CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)Oh`B. `CH_(3)CH_(2)CH_(2)overset(OH)overset(|)CHCH_(3)`C. `CH_(3)CH_(2)underset(OH)underset(|)overset(CH_(3))overset(|)C CH_(2)CH_(3)`D. `CH_(3)CH_(2)underset(CH_(3))underset(|)CHCH_(2)CH_(2)OH` |
| Answer» Correct Answer - C | |
| 206. |
Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, `BH_(3)` is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using `H_(2)O_(2)//OH^(bar(..))`. The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. `underset((ii)H_(2)O_(2)//OH^(bar(..)))overset((i)BH_(3)//THF)rarr "product"`. The product isA. Threo cyclic alchoholB. Erythreo cyclic alcoholC. Optically active alchoholD. Both (B) and (C) |
| Answer» Correct Answer - D | |
| 207. |
Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, `BH_(3)` is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using `H_(2)O_(2)//OH^(bar(..))`. The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH_(2)` `underset((ii)H_(2)O_(2)//OH^(bar(..)))overset((i)BH_(3)//THF)rarrZ`. `Z` is :A. Optically active `1^(@)-`alcoholB. Optically active `2^(@)-`alcoholC. Optically inactive `1^(@)-`alchoholD. Optically inactive `3^(@)-`alcohol |
| Answer» Correct Answer - C | |
| 208. |
Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, `BH_(3)` is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using `H_(2)O_(2)//OH^(bar(..))`. The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. `Y` is :A. B. C. bothD. None of these |
| Answer» Correct Answer - B | |
| 209. |
Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, `BH_(3)` is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using `H_(2)O_(2)//OH^(bar(..))`. The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. Find the product of following reaction A. B. C. D. |
| Answer» Correct Answer - D | |
| 210. |
Amines are derivatives of ammonia and are classified as `1^(@), 2^(@)`, and `3^(@)`, Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Which of the following shows configurational isomerism ?A. Diethyldimethylammonium iodideB. DimethylpropylamineC. Methylallylphenylbenzyl ammonium bromideD. None of these |
| Answer» Correct Answer - C | |
| 211. |
Amines are derivatives of ammonia and are classified as `1^(@), 2^(@)`, and `3^(@)`, Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Which of the following statement is correct ?A. All classes of amines form hydrogen bonds with each otherB. Only primary and secondary amines form hydrogen bonds with waterC. All classes of amines can form hydrogen bonds with waterD. All amines are completely soluble in water |
| Answer» Correct Answer - C | |
| 212. |
The reactivity of acid derivatives in general follows the order : The above order of reactivity can be explained in terms of the : (i) Basicity of leaving group (ii) Resonance effect (iii) Inductive effect Weaker is the basic character of leaving group, more is the reactivity of acid derivative. In general, all the acid derivatives show resonance as follows: More is the stablization, lesser is the reactivity and vice-versa. Acid derivatives although contain `-overset(O)overset(||)C-` group, yet do not undergo the usual properties of carbonyl group. It is due toA. inductive effectB. resonanceC. elemenric effectD. all of these |
| Answer» Correct Answer - B | |
| 213. |
reacts with : `gamma-`Butyroactone (ester) What are the producut in each case ?A. `NH_(3)`B. `LiAlH_(4)`C. `EtOH,H^(+)`D. `NaBH_(4)//EtOH` |
| Answer» Correct Answer - A::C | |
| 214. |
The reactivity of acid derivatives in general follows the order : The above order of reactivity can be explained in terms of the : (i) Basicity of leaving group (ii) Resonance effect (iii) Inductive effect Weaker is the basic character of leaving group, more is the reactivity of acid derivative. In general, all the acid derivatives show resonance as follows: More is the stablization, lesser is the reactivity and vice-versa. Which among the following ester is most reactive towards nucleophilic attack ?A. `CH_(3)COOCH_(3)`B. `HCOOCH_(3)`C. `CH_(3)CH_(2)COOC_(6)H_(5)`D. All are equally reactive |
| Answer» Correct Answer - B | |
| 215. |
The reactivity of acid derivatives in general follows the order : The above order of reactivity can be explained in terms of the : (i) Basicity of leaving group (ii) Resonance effect (iii) Inductive effect Weaker is the basic character of leaving group, more is the reactivity of acid derivative. In general, all the acid derivatives show resonance as follows: More is the stablization, lesser is the reactivity and vice-versa. Which of the following compounds will be most easily hydrolysed ?A. Acid halideB. Acid amideC. Ester are non-volatileD. Acid anhydride |
| Answer» Correct Answer - A | |
| 216. |
The reactivity of acid derivatives in general follows the order : The above order of reactivity can be explained in terms of the : (i) Basicity of leaving group (ii) Resonance effect (iii) Inductive effect Weaker is the basic character of leaving group, more is the reactivity of acid derivative. In general, all the acid derivatives show resonance as follows: More is the stablization, lesser is the reactivity and vice-versa. Which of the most reactive acid derivative ?A. R-COClB. `(RCO)_(2)O`C. RCOORD. `RCONH_(2)` |
| Answer» Correct Answer - A | |
| 217. |
The electrophile involved in the above reaction is:A. dichlorocarbene `(:C Cl_(2))`B. trichloromethyl anion `(overset(o+)C Cl_(3))`C. formyl cation `(overset(o+)CHO)`D. dichloromethyl cation `(overset(o+)CHCl_(2))` |
| Answer» Correct Answer - A | |
| 218. |
Electrophile `overset(o+)NO_(2)` attacks the following : In which cases `overset(o+)NO_(2)` will attack at meta positionA. II and IVB. I,II and IIIC. II and IVD. I only |
| Answer» Correct Answer - B | |
| 219. |
A new C-C bond is formed in-A. Cannizzaro reactionB. Friedel Crafts reactionC. Both A `&` BD. None of these |
| Answer» Correct Answer - B | |
| 220. |
Among the following the strongest base isA. `C_(6)H_(5)NH_(2)`B. `p-NO_(2)-C_(6)H_(4)NH_(2)`C. `m-NO_(2)-C_(6)H_(4)NH_(2)`D. `C_(6)H_(5)CH_(2)NH_(2)` |
| Answer» Correct Answer - D | |
| 221. |
Which of the following amine will not respond to carbylamine reaction ?A. EthylamineB. `(CH_(3))_(2)NH`C. `CH_(3)NH_(2)`D. Phenylamine |
| Answer» Correct Answer - B | |
| 222. |
Isocyaride test can be given by :A. `C_(2)H_(5)NH_(2)`B. `C_(6)H_(5)NH_(2)` and `HCOOH` respectivelyC. `C_(6)H_(5)NHC_(2)H_(5)`D. `C_(6)H_(5)underset(C_(2)H_(5))underset(|)CH-NH_(2)` |
| Answer» Correct Answer - A::B::D | |
| 223. |
Amines are derivatives of ammonia and are classified as `1^(@), 2^(@)`, and `3^(@)`, Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Methylethylpropyl amine is optically inactive becauseA. it is not tetrahederalB. its molecule is superimposable on its mirror imageC. The enantiomers are rapidly interconvertedD. The nitrogen is `sp^(2)` hybridized |
| Answer» Correct Answer - B | |
| 224. |
In the chemical reactions the compounds `(A)` and `(B)` are .A. Fluorobenzene and phenolB. Benzene diazonium chloride and benzoinitrileC. Nitrobenzene and chlorobenzeneD. Phenol and bromobenzene |
| Answer» Correct Answer - B | |
| 225. |
Consider the reaction `[CH_(3)CH_(2)CH_(2)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(.^(o+)(N))-CH_(2)CH_(3)]OH^(-)overset("Heat")(to)` Which of the following is formed in major amount ?A. `CH_(2)=CH_(2)`B. `CH_(3)CH=CH_(2)`C. Both (A) and (B) in equal amountD. None, as no reaction takes place |
| Answer» Correct Answer - A | |
| 226. |
When acetic acid reacts with ketene , product formed is :A. Ethyl acetateB. aceto-acetic esterC. acetic anhydrideD. No reaction |
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Answer» Correct Answer - C::D `CH_(3)COOH+underset("Ketene")(CH_(2)=C=O)rarr` acetc anhydride |
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| 227. |
Which of he following hydrogens will be most acidic? A. aB. bC. cD. d |
| Answer» Correct Answer - C | |
| 228. |
Phenol is heated with a solution of mixture of `KBr` and `KBrO_(3)`. The major product obtained in the above reaction isA. 4-BromophenolB. 2,4,6-TribromophenolC. 2-BromophenolD. 3-Bromophenol |
| Answer» Correct Answer - B | |
| 229. |
A compound A with molecular formula `C_(15)H_(13)Cl` gives a white precipitate on adding silver nitrate solution A on reacting with alcoholic KOH gives compound B as the main product. B on ozonolysis gives C and C gives Cannizaro reaction but not aldol condensation. D gives aldol condensation but not Cannizaro react A is :A. B. C. `C_(6)H_(5)-CH_(2)CH_(2)CH_(2)-CH_(2)-Cl`D. `C_(6)H_(5)-CH(2)-CH_(2)-underset(Cl)underset(|)CH-CH_(3)` |
| Answer» Correct Answer - B | |
| 230. |
Statement `I:` `1-`Butene on reaction with `HBr` in the presence of a peroxide produces `1-` bromobutane. Statement `II:` It involves the formation of a primary radical. |
| Answer» Correct Answer - C | |
| 231. |
Statement `I:` `1-`Butene on reaction with `HBr` in the presence of a peroxide produces `1-` bromobutane. Statement `II:` It involves the formation of a primary radical.A. If both assertion and reason are correct, and reason is the correct explanation of the assertionB. If both assertion and reason are correct, but reason is not correct explanation of the assertionC. If assertion is correct but reason is incorrectD. If assertion is incorrect but reason is correct |
| Answer» Correct Answer - C | |
| 232. |
The reaction of with `HBr` givesA. B. C. D. |
| Answer» Correct Answer - B | |
| 233. |
Reaction of one molecule of HBr with one molecule of 1,3-butadiene at `40^(@)`C gives predominantly.A. `1-`bromo`-2-`butene under thermodynamically controlled conditionsB. `3-`bromobutene under kinetically controlled conditionsC. `1-`bromo`-2-`butene under kinetically controlled contionsD. `3-`bromobutene under thermodynamically controlled conditions |
| Answer» Correct Answer - A | |
| 234. |
The Cannizzaro reaction is not given byA. TrimethylacetaldehydeB. AcetaldehydeC. BenzaldehydeD. formaldehyde |
| Answer» Correct Answer - B | |
| 235. |
Which of the following does not undergo aldol condenation ?A. HCHOB. `CH_(2)CHO`C. `CH_(3)COCH_(3)`D. `CH_(5)CH_(2)CHO` |
| Answer» Correct Answer - A | |
| 236. |
Which of the following will not undergo aldol condensation-A. AcetaldehydeB. PropanaldehydeC. BenzaldehydeD. Trideutero acetaldehyde |
| Answer» Correct Answer - C::D | |
| 237. |
Which isomerism present in n-propyl amine and isopropyl amineA. MetamarismB. Functional groupC. PositionD. Position and chain |
| Answer» Correct Answer - C | |
| 238. |
In a Cannizaro reaction the intermediate that will be the best hydride donor isA. `C_(6)H_(5)-underset(OH)underset(|)overset(H)overset(|)C-O^(o+)`B. `C_(6)H_(5)-underset(O^(o+))underset(|)overset(H)overset(|)C-O^(o+)`C. D. |
| Answer» Correct Answer - D | |
| 239. |
Among the given compounds, the most susceptible to nucleophilic attack at the cabonyl group is:A. `CH_(3)COCl`B. `CH_(3)CHO`C. `CH_(3)CHO`D. `CH_(3)COOCOCH_(3)` |
| Answer» Correct Answer - A | |
| 240. |
In the reaction, `CH_(3)COOHoverset(L(A)H_(4))rarrAoverset(PC_(5))rarrBoverset(A//C.NOH)rarrC,` the product `C` is :-A. EthyleneB. Acetyl chlorideC. AcetaldehydeD. Acetylene |
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Answer» Correct Answer - A `CH_(3)-overset(O)overset(||)C-OHoverset(LiAIH_(4))rarrCH_(3)overset((A))-CH_(2)-OHoverset(PCl_(5))rarrCH_(3)overset((B))CH_(2)-Cloverset("alc"KOH)rarrCH_(2)overset((C))=CH_(2)` Reduction of `CH_(3)COOH` will produce `CH_(3)-CH_(2)-OH(A)` Now reaction of `CH_(3)-CH_(2)-OH(A)` with `PCl_(5)` will produce `CH_(3)-CH_(2)-Cl(B)`. Now alcoholic `KOH` with `Et-Cl` will produce `CH_(2)=CH_(2)(C)` Ethylene by `E_(2)` elemination. Thus Ans. is (1) Ethylene. |
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| 241. |
In the reaction sequence `RCOCl+H_(2)overset(Pd+BaSO_(4))rarrAoverset(HCN)rarrBoverset(H_(3)O^(o+))rarrC` A,B and C are given by the set :-A. `RCHO,RCH(OH)CN, RCH(OH)CH_(2)NH_(2)`B. `RCHO, RCH(OH)CN, RCH(OH)COOH`C. `RCHO,R-underset(O)underset(||)C-underset(CN)underset(|)CH_(2),R-underset(O)underset(||)C-OH`D. `RCHO,R-CH_(2)-CN,R-CH_(2)-COOH` |
| Answer» Correct Answer - B | |
| 242. |
Identify B, X and R respetectivelly in the following sequence of reactions `C_(2)H_(5)MgBroverset(ClCN)rarrAoverset(H_(3)O^(+))rarrB`, `CH_(3)COCH_(3)underset(NaOH)overset(I_(2))rarrXoverset(Ag)rarrY` `C_(6)H_(5)NH_(2)underset(HCl)overset(NaNO_(2))rarrPoverset(CuCN)rarrQoverset(+4H)rarrR`A. `C_(2)H_(5)COOH, CHI_(3),C_(6)H_(5)CH_(2)NH_(2)`B. `C_(2)H_(5)COOH, CH_(3)I, C_(6)H_(5)COOH`C. `C_(2)H_(5)CH_(2)NH_(2), CH_(3I, C_(6)H_(5)COOH`D. `C_(2)H_(5)COOH, C_(2)H_(5)I, C_(6)H_(5)CONH_(2)``C_(2)H_(5)COOH, C_(2)H_(5)I, C_(6)H_(5)CONH_(2)` |
| Answer» Correct Answer - A | |
| 243. |
The increasing order of the rate of `HCN` addition of compound a-d is (i) `HCHO`(ii) `CH_(3)COCH_(3)` (iii) `PhCOCH_(3)` (iv) `PhCOPh`A. `DltBltCltA`B. `DltCltBltA`C. `CltDltBltA`D. `AltBltCltD` |
| Answer» Correct Answer - B | |
| 244. |
Statement-I: `CH_(3)COCH_(2)COOC_(2)H_(5)` will give iodoform test. Because Statement-II: It contains `CH_(3)overset(O)overset(||)C-` group linked to a carbon atom.A. Statement-I is True, Statement-II is True : Statement-II is a correct explanation for Statement-IB. Statement-I is True, Statement-II is True : Statement-II is `NOT` a correct explanation for Statement-IC. Statement-I is True, Statement-II is False.D. Statement-I is False, Statement-II is True. |
| Answer» Correct Answer - D | |
| 245. |
A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis of (Q) leads to a dicarbonyl compound (R ) which undergors intramolecular aldol reaction to give predominantly (S). `Poverset(1. MeMgBr)underset{:(2.H^(+)","H_(2)O),(3.H_(2)SO_(4)","Delta):}rarr Q underset(2. Zn"," H_(2)O)overset(1. O_(3))rarr R underset(2. Delta)overset(1. OH^(-))rarr S` The structure of product (S) is:A. B. C. D. |
| Answer» Correct Answer - B | |
| 246. |
A tertiary alcohol (H) upon acid-catalysed dehydration gives a product (I). Ozonolysis of (I) leads to compounds (J) and (K). Compound (J) upon reaction with KOH gives benzyl alcohol and a compound (L), whereas (K) on reaction with KOH gives only (M). The structures of compounds (J), (K), and (L), respectively, are:A. `PhCOCH_(3), PhCH_(2)COCH_(3)` and `PhCH_(2)CO O^(-)K^(+)`B. `PhCHO,PhCH_(2)CHO` and `PhCOO^(-)K^(+)`C. `PhCOCH_(3),PhCH_(2)CHO` and `CH_(3)COO^(-)K^(+)`D. `PhCHO, PhCOCH_(3)` and `PhCOO^(-)K^(+)` |
| Answer» Correct Answer - D | |
| 247. |
A tertiary alcohol (H) upon acid-catalysed dehydration gives a product (I). Ozonolysis of (I) leads to compounds (J) and (K). Compound (J) upon reaction with KOH gives benzyl alcohol and a compound (L), whereas (K) on reaction with KOH gives only (M). Compound (H) is formed by the reaction of:A. B. C. D. |
| Answer» Correct Answer - B | |
| 248. |
Ester gives nucleophilic addition reaction followed by elimination reaction with carbon nucleopile. When carbon nucleophile is of an ester then the reaction is known as Claisen condensation reaction. This reaction is also carried out between ester and a ketone. A suC Cessful Claisen condensation requires an ester with two `alpha-` hydrogens and an equivalent amount of base rather than a catalytic amount of base. In the given reaction [X] is :A. `H-overset(O)overset(||)C-Cl`B. `HCl+CO`C. `HCOOC_(2)H_(5)`D. `{:(COOC_(2)H_(5)),(|),(COOC_(2)H_(5)):}` |
| Answer» Correct Answer - C | |
| 249. |
Acetamide is treated Separately with the following reagents. Which one of these would give methylamine?A. `PCl_(5)`B. SodalimeC. `NaOH+Br_(2)`D. Hot concentrated `H_(2)SO_(4)` |
| Answer» Correct Answer - C | |
| 250. |
In the nitration of benzene with a mixture of concentrated `HNO_(3)` and concentrated `H_(2)SO_(4)` the active species involved isA. `NO_(3)^(-)`B. `NO_(2)`C. `NO_(2)^(-)`D. `NO_(2)^(+)` |
| Answer» Correct Answer - D | |