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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
201. |
match the correct combination ?A. (IV) (iv) (R)B. (III) (ii) (Q)C. (II) (iii) (R)D. (I) (i) (P) |
Answer» Correct Answer - D | |
202. |
Which of the folliwning ether wil always give `SN^(2)` mechanism in acidic as well as basic conditions?A. B. C. D. All |
Answer» Correct Answer - `d` All |
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203. |
In which amongs the following product is formed by free radical mechanism ?A. (I) (ii) (P)B. (IV) (ii) (Q)C. (II) (iii) (Q)D. (III) (iii) (P) |
Answer» Correct Answer - B | |
204. |
Q.12, Q.13 and Q.14 by appropriately matching the information given in the three columns of the following table. Match the correct combination?A. (IV) iii) RB. I) ii) R)C. III) iv) P)D. II) ii) R) |
Answer» Correct Answer - A | |
205. |
Q.12, Q.13 and Q.14 by appropriately matching the information given in the three columns of the following table. In which amongs the following more than one products are not formed?A. IV) iv) R)B. III) ii) Q)C. II) iii) R)D. I) i) P) |
Answer» Correct Answer - D | |
206. |
The electrophile involved in the above reaction is:A. Dichloromethyl cation `overset(odot)CHCl_(2)`B. Dichlorocarbon `(:CCl_(2))`C. Trichloromethyl anion `overset(odot)CCl_(3))`D. Formyl cation `overset(odot)CHO` |
Answer» Correct Answer - B | |
207. |
The structure of the compound that gives a tribromo derivative on treatment with bromine water is `:`A. B. C. D. |
Answer» Correct Answer - A | |
208. |
The electrophile involved in the above reaction is:A. Dichloromethyl cation `(overset(o+)(C)HCl_(2))`B. Dichlorocarbene `( :C Cl_(2))`C. Trichloromethyl anion `(overset(Θ)(C)Cl_(3))`D. Formyl cation `(overset(o+)(C)HO)` |
Answer» Correct Answer - B | |
209. |
The structure of the compound that gives a tribromo derivative on treatment with bromine water is `:`A. B. C. D. |
Answer» Correct Answer - A | |
210. |
The product(s) of the following reactions sequence is(are) A. B. C. D. |
Answer» Correct Answer - B | |
211. |
The major product U in the following reactions is A. B. C. D. |
Answer» Correct Answer - B | |
212. |
The product (s) of the following reaction sequence is (are) A. B. C. D. |
Answer» Correct Answer - B | |
213. |
In the following reactions, the major product W is:A. B. C. D. |
Answer» Correct Answer - A | |
214. |
In the following reactions, the major product W is:A. B. C. D. |
Answer» Correct Answer - A | |
215. |
The major product U in the following reactions is A. B. C. D. |
Answer» Correct Answer - B | |
216. |
The major product of the following reaction is : A. B. C. D. |
Answer» Correct Answer - C | |
217. |
The major product of the following reactions is : A. B. C. D. |
Answer» Correct Answer - B | |
218. |
Give the product of the following reactions: A. B. C. D. `(#RES_CHM_AC_E02_005_O04.png" width="30%"> |
Answer» Correct Answer - A | |
219. |
In the diazotisation of anline with sodium nitrite and hydrochloride acid, an excess of hydrochloric acid is used primarily toA. suppress the concentration of free aniline available for couplingB. suppress hydrolysis of phenolC. insure a stoichiometric amount of nitrous acidD. neutralize the base liberated |
Answer» Correct Answer - A | |
220. |
Which of the following reduction reactions does not give an amine as product?A. `R-NO_(2) overset(H_(2))underset("Raney Ni")toB. `R-NO_(2)overset(LiAlH_(4))underset("ether")to`C. `R-NO_(2) overset(Sn//HCl)to`D. `R-NO_(2)overset(Zn//NH_(4)Cl)underset(Delta)to` |
Answer» Correct Answer - D | |
221. |
Which reagent (X) is used to convert I to IIA. KBr/NaOHB. `Br_(2)`/NaOHC. `NaHCO_(3)`D. BN-Bromo succinamide |
Answer» Correct Answer - B | |
222. |
The product of the followeing reaction is A. B. C. D. |
Answer» Correct Answer - A | |
223. |
Organic compounds sometimes adjust their electronic as well as steric structure to attain stability. Among the following, the compound having highest dipole moment is :A. B. C. D. |
Answer» Correct Answer - D | |
224. |
An organic base (X) reacts with nitrous at `0^(@)` to give a clear solution. Heating with KCN and cuprous cyanide followed by continued heating with conc. HCl gives a crystaline solid. Heating this solid with alkaline potassium permangante gives a compound which dehydrates on heating to a crystaline solid. `"X"`. is:A. B. C. D. |
Answer» Correct Answer - D | |
225. |
The product P obtained through the following sequence of reactions is A. 3-chloroanilineB. 4-bromochlorobenzeneC. 3-bromochlorobenzeneD. 3-bromoaniline |
Answer» Correct Answer - C | |
226. |
The product of the following reaction is A. B. C. D. |
Answer» Correct Answer - A | |
227. |
The major product of the following reaction is: A. B. C. D. |
Answer» Correct Answer - C | |
228. |
The product of Reimer-Tiemann reaction is aA. phenolic aldehydeB. hydroxyamineC. nitroaldehydeD. nitroalcohol |
Answer» Correct Answer - A | |
229. |
The nitrogen atom in the following cyclic compounds can be removed as trimethylamine by successive Hoffmann eliminations (involving exhaustive methylation followed by heating with `AgOH`). The amine which will require a greater number of Hoffmann eliminations is:A. B. C. D. |
Answer» Correct Answer - B | |
230. |
Arrange the following in incresing order of rate of Nitration : (a) A. `b lt c lt a lt d lt e`B. `d lt e lt a = c lt b`C. `d lt a = c lt e lt b`D. `a lt c lt b lt e lt d` |
Answer» Correct Answer - B On the basis that the rate determining step is the formation of the carbonium ion, then, with benzene as the reference compound, the rate is faster when the substituent activates the ring `(+I " and /or " + R, o//p)` and the rate is slower when the substituent activates `(-I " and /or " -R, m)`. Halogen is an slower when the substituent deactivates the ring `(-I, R, -I gt + R)`, but the orientation is `o//p`. Hence, the order of increasing rate of nitration is: `underset(((-I, -R)))(PhNO_(2)) lt underset(-I gt +R)underset(((-I, -R)))(PhCl) lt PhH = C_(6)D_(6) lt underset((+I))(PhMe)` Since proton removal from the carbonium ions is fast, no kinetic isotope effect is observed when H si replaced by D.Hence, the rate of nitration of PhH and `C_(6)D_(6)` are the same. Had a kinetic isotope effect been observed, this would mean that the second step had now become rate determining. |
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231. |
In a set of reactions p-nitrotulene yielded a product E. The product E would be: A. B. C. D. |
Answer» Correct Answer - B | |
232. |
Picric acid is:A. B. C. D. |
Answer» Correct Answer - C | |
233. |
Picric acid is:A. B. C. D. |
Answer» Correct Answer - C | |
234. |
When primary amine reacts with choloroform in ethanolic KOH then the product is:A. an isocyanideB. an aldehydeC. a cyanideD. an alcohol |
Answer» Correct Answer - A | |
235. |
The sequence of decreasing aromaticity in the above compounds isA. `I gt II gt III`B. `I gt III gt II`C. `II gt III gt I`D. `III gt II gt I` |
Answer» Correct Answer - B | |
236. |
In the above reaction `o//p` ratio will be highest when :A. `R = - CH_(3)`B. `R = - CH_(2) - CH_(3)`C. `R = - CHMe_(2)`D. `R = - Cme_(3)` |
Answer» Correct Answer - A The steric demand of `H^(Θ)` is, however, extremely small, and when attack on `C_(6)H_(5)Y` is by any other electrophile, `E^(oplus)`, which will necessarily be larger, there will be increasing interaction between E and Y in the transition state for attack at the position `o-` to Y (57 b, `R = E`) as attacking electrophile and substituent increase in size, there can be no such interaction in the transition state for `p-` attack `(57 a, R = E)`. This will be reflected in an increasing `Delta G^(+)` for `o-` attack, a consequently slower reaction, and the relative propotion of `o-` product will thus fall as the size of E and / or Y increas. This is illustrated by the falling `f_(o)-//f_(p)-` ratios which are observed for the nitration of alkylbenzenes `(Y - CH_(3) rarr CMe_(3))` under comparable conditions : `"Increase in size of Y"{:(Y,%o-,%p-,),(CH_(3),58,37,),(CH_(2)Me,45,49,),(CHMe_(2),30,62,),(CMe_(3),16,73,):}` |
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237. |
The sequence of decreasing aromaticity in the above compound isA. `I gt II gt III`B. `I gt III gt II`C. `II gt III gt I`D. `III gt II gt I` |
Answer» Correct Answer - B | |
238. |
On bromination, the electron rich phenoxide ion will be attacked most readilyA. on the negatively charged oxygen atomB. on the ortho and para carbon atomC. on the meta carbon atomD. on the ortho carbon atom. |
Answer» Correct Answer - B | |
239. |
On bromination, the electron rich phenoxide ion will be attacked most readilyA. on the negatively charged oxygen atomB. on the ortho and para carbon atomsC. on the meta carbon atomD. on the ortho carbon atom. |
Answer» Correct Answer - B | |
240. |
When 2-hydroxybenzoic aicd (salicylic acid) is treated with bromine water, the product formed is:A. B. C. D. |
Answer» Correct Answer - D | |
241. |
The product obtained when 4-hydroxybenzene sulphonic acid is treated with an excess of bromine water isA. 2-bromo-4-hydroxybenzene sulphonic acidB. 2,3-dibromo-4-hydroxybenzene sulphonic acidC. 2,6-dibromo-4-hydroxybenzene sulphonic acidD. 2,4,6-tribromophenol |
Answer» Correct Answer - D | |
242. |
In the reaction the product E is :-A. B. C. D. |
Answer» Correct Answer - C | |
243. |
A compound X formed after heating coke with lime react with water to give Y which on passing over redhot iron at 873 produces Z. The compound Z isA. B. C. D. |
Answer» Correct Answer - A | |
244. |
Which of the following statements is/are correct?A. `1^(@), 2^(@)` and `3^(@)` amines can be distinguished by Hinsberg reagent.B. Phenol does not give Lucas test.C. Phenol & alcohols can be distinguished by neutral `FeCl_(3)`D. All of these |
Answer» Correct Answer - D Lucas test is given by alcohols. Neutral `FeCl_(3)` test is given by phenols. |
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245. |
The major product isA. B. C. D. |
Answer» Correct Answer - B | |
246. |
When 2-hydroxybenzoic aicd (salicylic acid) is treated with bromine water, the product formed is:A. B. C. D. |
Answer» Correct Answer - D | |
247. |
The major product of the following reaction is A. B. C. D. |
Answer» Correct Answer - A | |
248. |
The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `H_(2)SO_(4)` at `0^(@)` C gives R. the reaaction of R with `CH_(3) COCl` in the presence of anhydrous `AlCl_(3)` in `CH_(2)Cl_(2)` followed by treatment with `H_(2)O` "produces compound S`. [Et in compound P is ethyl group] The reaction, Q to R and R TO S, areA. Aromatic sulfnation and Friedel-Crafts acylationB. Friedel-Crafts alkylation and Friedel-Crafts acylationC. Friedel-Crafts alkylation, dehydration and Friedel-Crafts acylationD. Dehydration and Friedel acylation |
Answer» Correct Answer - B | |
249. |
The `-NO_(2)` group in an aromatic ring deactivates the ortho and para positions for an electrophilic attack. When `-NO_(2)` group is present at ortho or para positions of a leaving group (Nucleofuge) it activates the ring for nucleophilic attack. The reduction of `-NO_(2)` group by metal in acid causes its reduction to `-NH_(2)` group and then the ring becomes strongly activated for a electrophilic attack. The strong activation of `-NH_(2)` group is moderated by its acylation with `CH_(3)COCl` to `-NHAc` group. Deacylation is carried out by hydrolysis with `H_(3)O^(+)` or `OH^(-)`. The ring alkylation by using `RX//AlX_(3)` is not possible in presence of `-NO_(2)` or `-NH_(2)` group but is possible in presence of `-NHAc` group. The product (G) is :A. B. C. D. |
Answer» Correct Answer - B | |
250. |
The `-NO_(2)` group in an aromatic ring deactivates the ortho and para positions for an electrophilic attack. When `-NO_(2)` group is present at ortho or para positions of a leaving group (Nucleofuge) it activates the ring for nucleophilic attack. The reduction of `-NO_(2)` group by metal in acid causes its reduction to `-NH_(2)` group and then the ring becomes strongly activated for a electrophilic attack. The strong activation of `-NH_(2)` group is moderated by its acylation with `CH_(3)COCl` to `-NHAc` group. Deacylation is carried out by hydrolysis with `H_(3)O^(+)` or `OH^(-)`. The ring alkylation by using `RX//AlX_(3)` is not possible in presence of `-NO_(2)` or `-NH_(2)` group but is possible in presence of `-NHAc` group. The product (H) is :A. B. C. D. |
Answer» Correct Answer - B | |