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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
The `-NO_(2)` group in an aromatic ring deactivates the ortho and para positions for an electrophilic attack. When `-NO_(2)` group is present at ortho or para positions of a leaving group (Nucleofuge) it activates the ring for nucleophilic attack. The reduction of `-NO_(2)` group by metal in acid causes its reduction to `-NH_(2)` group and then the ring becomes strongly activated for a electrophilic attack. The strong activation of `-NH_(2)` group is moderated by its acylation with `CH_(3)COCl` to `-NHAc` group. Deacylation is carried out by hydrolysis with `H_(3)O^(+)` or `OH^(-)`. The ring alkylation by using `RX//AlX_(3)` is not possible in presence of `-NO_(2)` or `-NH_(2)` group but is possible in presence of `-NHAc` group. The product (G) is :A. B. C. D. |
| Answer» Correct Answer - B | |
| 252. |
What is correct order of rate of nitration of the following compounds ? (A) `C_(6)H_(5)CH_(3)` (B) `C_(6)H_(6)` (C) `C_(6)D_(6)` (D) `C_(6)T_(6)` (E) `C_(6)H_(3)Br_(3)` (F) `C_(6)H_(5)overset(+)(N)R_(3)` (G) `C_(6)H_(5)NMe_(2)`A. `G gt A gt B gt C gt D gt E gt F`B. `G gt B gt C gt D gt A gt F`C. `G gt A gt B = C = D gt E gt F`D. `G gt A gt B gt C = D gt E gt F` |
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Answer» Correct Answer - C `sigma -`complex formation is reductions `:. C_(6)H_(6) = C_(6) D_(6) = C_(6)T_(6)` electron donating group increases rate electron withdrawing group decreases rate. |
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| 253. |
An orgainc compound A upon reacting with `NH_(3)` gives `B` On heating `B` give `C.C` in presence `KOH` reacts with `Br_(2)` to yield `CH_(3)CH_(2)NH_(2) A` is .A. `CH_(3)COOH`B. `CH_(3)CH_(2)CH_(2)COOH`C. `CH_(3)-underset(CH_(3))underset(|)(CH)-COOH`D. `CH_(3)CH_(2)COOH` |
| Answer» Correct Answer - D | |
| 254. |
An organic compound having the molecular formula `C_(7)H_(8)O` is insoluble in `NaHCO_(3)` solution but dissolves in aqueous NaOH. When treated with bromine water the compound rapidly forms a precipitate having the molecular `C_(7)H_(5)Obr_(3)`. The organic compound isA. o-cresolB. m-cresolC. p-cresolD. anisole |
| Answer» Correct Answer - B | |
| 255. |
Which of the following is attacking spcies in conversion Y to P?A. `:CCl_(2)`B. `:CHCl`C. `:CH_(2)`D. `CH_(2)Cl` |
| Answer» Correct Answer - A | |
| 256. |
Which of the following reaction is/are correctA. B. C. D. |
| Answer» Correct Answer - A::B::C::D | |
| 257. |
Which of the following reaction is/are correct:A. B. C. D. |
| Answer» Correct Answer - A::B::C::D | |
| 258. |
The major product of the following reaction is A. B. C. D. |
| Answer» Correct Answer - A | |
| 259. |
The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `H_(2)SO_(4)`at `0^(@)` C gives R. the reaaction of R with `CH_(3) COCl` in the presence of anhydrous `AlCl_(3)"in" CH_(2)Cl_(2)` followed by treatment with `H_(2)O` produces compound S. [Et in compound P is ethyl group] The product S is The product S is A. B. C. D. |
| Answer» Correct Answer - B | |
| 260. |
The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `H_(2)SO_(4)`at `0^(@)` C gives R. the reaaction of R with `CH_(3) COCl` in the presence of anhydrous `AlCl_(3)"in" CH_(2)Cl_(2)` followed by treatment with `H_(2)O` produces compound S. [Et in compound P is ethyl group] The product S is The product S is A. B. C. D. |
| Answer» Correct Answer - B | |
| 261. |
The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `H_(2)SO_(4)` at `0^(@)` C gives R. the reaaction of R with `CH_(3) COCl` in the presence of anhydrous `AlCl_(3)` in `CH_(2)Cl_(2)` followed by treatment with `H_(2)O` "produces compound S`. [Et in compound P is ethyl group] The reaction, Q to R and R TO S, areA. Aromatic sulfonation and Friedel-Crafts acylationB. Friedel-Crafts alkylation and Friedel-Crafts acylationC. Friedel-Crafts alkylation, dehydeation and Friedel-Crafts acylationD. Dehydration and Friedel-Crafts acylation |
| Answer» Correct Answer - B | |
| 262. |
Given is the energy profile diagram of nitration of benzene using mixed acid. `(HNO_(3) + H_(2)SO_(4))` Identify (x) in above reaction:A. B. C. D. None |
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Answer» Correct Answer - A Electrophilic aromatic substitution. |
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| 263. |
Nitration of the following reactant gives maximum % of meta product (using `HNO_(3)//H_(2)SO_(4)`)?A. TolueneB. AnilineC. BenzeneD. Isopropyl benzene |
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Answer» Correct Answer - B Because of protonation of aniline `Ph - overset(..)(N)H_(2) overset(H^(oplus))hArr Ph - overset(o+)(N)H_(3)` |
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| 264. |
Given is the energy profile diagram of nitration of benzene using mixed acid. `(HNO_(3) + H_(2)SO_(4))` Identify `T. S_(1)` in the above reaction.A. B. C. D. None |
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Answer» Correct Answer - B Electrophilic aromatic substitution. |
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| 265. |
Chloroform when treated aniline and alcoholic KOH, the product formed is?A. Phenyl cyanideB. Phenyl isocyanideC. ChlorobenzeneD. Phenol |
| Answer» Correct Answer - B | |
| 266. |
Which of the following statement is/are correct:A. P is benzene diazonioum chlorideB. Q can not give bromine water testC. R and S are position isomersD. During the formation of R and S from Q, formation of a new C-C bond will takes place. |
| Answer» Correct Answer - A::C::D | |
| 267. |
Assertion: Aryl halides undergo nucleophilic substitution reactions with ease. Reason:The carbon halogen bond in aryl halides has partial double bonds character.A. Statement 1: is true Statement 2: is true, Statement 2 is the correct explainion of Statement 1B. Statement 1 is true, Statement 2 is true, Statement 2 is not the correct explainion fo Statement 1.C. Statement 1 is true, Statement 2 is false.D. Statement 1 is false, Statement 2 is true. |
| Answer» Aryl halides do ot undergo nucleophillic substituion reaction under ordinary conditions. Thus, statement `1` is incorrect. In aryl halides, the carbon-halogen bond has a partical double bond character, so it becomes shorter and stronger and cannot be easily reaplaced by a nuclephile. Statement 2 is true. | |
| 268. |
Conversion of benzene diazonium chloride to chloro benzene is an example of which of the following reactions?A. ClaisenB. Friedel-craftC. SandmeyerD. Wurtz |
| Answer» Correct Answer - C | |
| 269. |
Among The following the number of reaction(s) that prouduce(s) benzadelhyde is |
| Answer» Correct Answer - D | |
| 270. |
Nitration takes place at the which position of given compound ? A. AB. BC. CD. D |
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Answer» Correct Answer - B `-CHMe_(2)` (hyperconjugation) |
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| 271. |
Among the following compounds , the strongest acid is:A. `HC = CH`B. `C_(6)`C. `C_(2) H_(6)`D. `CH_(3)OH` |
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Answer» Correct Answer - `d` Order of acidic strength is: `CH_(3)OH gt HC -= CH gt C_(6) H_(6) gt C_(2) H_(6)`. Although all are are neutral towards litmus paper. |
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| 272. |
How many products are capables of beings formed from toluene in each of following reaction ? A. `A = 3, B = 6, C = 8`B. `A = 3, B = 6, C = 6`C. `A = 3, B = 6, C = 10`D. `A = 3, B = 4, C = 6` |
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Answer» Correct Answer - B `A = 3` (ortho, meta and para isomers) `B = 6` `C = 6` |
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| 273. |
`C_(6)H_(5)N_(2)Cl overset(SnCl_(2)//HCl) (A) to overset(C_(6)H_(5)CHO)to(B)` The product (B) in the above sequence of reaction isA. `C_(6)H_(5)-N=N-C_(6)H_(5)`B. `C_(6)H_(5)-N=CH-C_(6)H_(5)`C. `C_(6)H_(5)-NH-N=CH-C_(6)H_(5)`D. |
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Answer» Correct Answer - C Reduction of benzene diazonium chloride with `SnCl_(2)` and HCl gives phenyl hydrazine which reacts with benzaldeyde to form phenyl hydrazone. `C_(6)H_(5)N_(2)Cl overset(SnCl_(2)//HCl)to(C_(6)H_(5)-NH-NH_(2)overset(C_(6)H_(5)CHO)to (C_(6)H_(5)-NH-N=CH-C-(6)H_(5)` |
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| 274. |
What is the correct order of `o//p` ration when `E^(+)` attackes the following system ? (A) `PhF` (B) `PhCl` (C) `PhBr` (D) `PhI`A. `A lt B lt C lt D`B. `A = B = C = D`C. `D lt C lt B lt A`D. `D lt B lt A lt C` |
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Answer» Correct Answer - A That the steric factor is not the sole determinant is, however, seen in the figure for the nitration of the halobenzenes, which are `o//p-`directing but on which overall attack is slightly slower than on benzene. `"Increase in size of Y"darr{:(Y,%o-,%p-,),(F,12,88,),(Cl,30,69,),(Br,37,62,),(I,38,60,):}` Despite the increase in size of the substituent Y from `F rarr I`, the proportion of `o-`isomer increase. An increasing steric effect will, as with the alkyl benzenes, be operating to inhibit `o-`attack, but this must here be outweighed by the electron-withdrawing inductive/field effect exerted by the halogen atom (Y). This effect will tend to decrease with distance from Y, being exerted somewhat less strongly on the distant `p-`position thus takes place on `C_(6)H_(5)F`, despite the small size of F. The electron -withdrawing effect of the halogen (Y) decrease considerably from F to I (the biggest change being between F and Cl), resulting in increasing attack at the `o-`position despite the increasing bulk of Y. |
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| 275. |
Salicylic acid on treatment with bromine water will giveA. 2-bromo-6-hydroxybenzoic acidB. 2,4-6-tribromophenolC. 2,6-dibromobenzoic acidD. 1,3-dibromo-6-hydroxybenzoic acid |
| Answer» Correct Answer - B | |
| 276. |
The action of bromine water (excess) on salicylic acid results in the formation of :A. B. C. D. |
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Answer» Correct Answer - C Ipso substitution take place means all ortho, para will substitute. (`-COOH` group will be replaced by `-Br`) |
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| 277. |
Sodium ethoxide is prepared by reacting ethanol with aqueous sodium hydroxide. |
| Answer» Etanol is not so much acidic. | |
| 278. |
The correct decreasing order of `SN^(1)` reactivity of the folliwng is: I. `PhCH_(2)X`. II. `CH_(2) = CHCH_(2)X` III. `Me_(2)CHX`, IV. `C_(2)H_(5)X`A. `(I) gt (II) gt (III) gt (IV)`B. `(IV) gt (III) gt (II) gt (I)`C. `(II) gt (I) gt (III) gt (IV)`D. `(IV) gt (III) gt (I) gt (II)` |
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Answer» Correct Answer - `a` `SN^(1)` reactivity order is: Benzyl gt Allyl `gt 2^(@) gt 1^(@)` halide. |
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| 279. |
Assertion `(A)`: Reaction between `(Me_(3)CONa)` (sodium ter-butoxide) and ethyliode `(C_(2)H_(5)I)` does not produce an ether. Reason `(R): Sodium ter-butoxide is a very strong base but is not a nucleophile.A. Both `(A)` and `(R)` are true and `(R0` is the correct explanation of `(A)`.B. Both `(A)` and `(R)` are true but `(R)` is not the correct explanation of `(A)`.C. `(A) is true but `(R)` is false.D. `(A) is false but `(R)` is true. |
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Answer» Correct Answer - `a` It produces alkene |
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| 280. |
In the reaction the product E is :-A. B. C. |
| Answer» Correct Answer - C | |
| 281. |
Which of the following compounds will give significant amount of meta- product during mononitration reaction?A. B. C. D. |
| Answer» Correct Answer - B | |
| 282. |
In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of amine produced areA. Four moles of NaOH and two moles of `Br_(2)`B. Two moles of NaOH and two moles of `Br_(2)`C. Four moles of NaOH and one mole of `Br_(2)`D. One moles of NaOH and one mole of `Br_(2)` |
| Answer» Correct Answer - C | |
| 283. |
In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of amine produced areA. Four moles of NaOH and two moles of `Br_(2)`B. Two moles of NaOH and one mole of `Br_(2)`C. Four moles of NaOH and one mole of `Br_(2)`D. One mole of NaOH and mole of `Br_(2)` |
| Answer» Correct Answer - C | |
| 284. |
In the reaction sequence `underset(350^(@))overset(NaOH)rarr A overset(CH_(3)I)rarr B overset(HI)rarr C+D` ltbr. A, B, C, and D are given by the set :A. Sodium phenate, anisole, `C_(6)H_(5)I, CH_(3)OH`B. Sodium phenate, phenitole, `C_(2)H_(5)l, C_(6)H_(5)OH`C. Sodium phenate, anisole, `C_(6)H_(5)OH, CH_(3)l`D. Sodium phenate, phenitole, `C_(6)H_(5)l, C_(2)H_(5)OH` |
| Answer» Correct Answer - C | |
| 285. |
Match the compounds given in Column-I with the items given in Column - II. |
| Answer» Correct Answer - A::B::C::D | |
| 286. |
The major product of the following reaction is : A. B. C. D. BN-Bromo succinamide |
| Answer» Correct Answer - A | |
| 287. |
In the reaction the intermediate(s) is/are:A. B. C. D. |
| Answer» Correct Answer - A::C | |
| 288. |
Match the reactions in Column I with appropriate options in Column II. A. B. C. D. |
| Answer» Correct Answer - A::B::C::D | |
| 289. |
Match the reactions given in Column I with the statements given in Column II |
| Answer» Correct Answer - A::B::C::D | |
| 290. |
Match the reactions given in Column I with the statements given in Column II |
| Answer» Correct Answer - (A-s); (B-r); (C-p); (D-q) | |
| 291. |
Match the column : |
| Answer» Correct Answer - (A-r); (B-s); (C-p); (D-q) | |
| 292. |
Rank the following in order of decreasing rate of reation with alkoxide ion `(CH_(3) CH_(2) O^(-))` in a nucleophilic aromatic substitution reaction : (1) A. `3 gt 4 gt 1 gt 2`B. `3 gt 4 gt 2 gt 1`C. `2 gt 1 gt 4 gt 3`D. `4 gt 3 gt 2 gt 1` |
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Answer» Correct Answer - A `{:(,3,gt,4,gt,1,gt,2,),(NO_(2) rarr,-M,,-M,,-M,,-I,),(NO_(2) rarr,-M,,-I,,,,,):}` `NO_(2)` is ortho-para director for nucleophilic aromatic substitution. |
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| 293. |
Carbylamine test is performed in alc . ` KOH` by heating a mixture of :A. Chloroform and silver powderB. Trihalogentaded methane and a primary amineC. An alkyl halide and a primary amineD. An alkyl cyanide and a primary amine |
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Answer» Correct Answer - `b` Carbylamine test is given by `1^(@)` amine with `CHCl_(3) + KOH` `RNH_(2) + CHCl_(3) + KOH rarr underset("Isocyanide")(R overset(o+)(N) -= overset(o-)(C)` It gives an offensicve smell of isovyanide. Mehcanism proceeds via carbene. `(:C Cl_(2))` or `(:CX_(2))` or `(:CXX^(1))` (`XX^(1) implies` Two different halogens) |
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| 294. |
Nucleophilic Aromatic substitution `(SN_(Ar))`: A substituted benzene derivative containing `- NO_(2)` and `Cl` group at `p-`position is subjected to `Nu-` substitution Match the column I and II `{:(,"Column (I)",,"Column (II)",),(,X = "halogen",,"relative reactivity toward" (SN_(Ar)),),((a),-F,(p),312,),((b),-Cl,(q),1,),((c),-Br,(r),0.8,),((d),-I,(s),0.6,):}` |
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Answer» Correct Answer - A-a-p, b-q, c-r, d-s `rArr` Mesenhemier complex is more stable by stron `-I` group. |
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| 295. |
An organic base (X) reacts with nitrous acid at `0^(@)C` to give a clear solution. Heating the solution with KCN and cuprous cyanide followed by continued heating with conc. HCl gives a crystalline solid. Heating this solid with alkaline potassium permanganate gives a compound which dehydrates on heating to a crystalline solid. "X" is :A. B. C. D. |
| Answer» Correct Answer - D | |
| 296. |
Aniline can be obtained by reduction of nitrobenzene withA. Fe/HClB. Sn/NaOHC. Electrolytic reduction under strong acidic conditionsD. All of these |
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Answer» Correct Answer - A Nitrobenzene reduced into aniline by metal/acid and electrolytic reduction in weakly acidic medium. |
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| 297. |
`n-`Butylbenzene on oxidation with hot alkanine `KMnO_(4)` gives:A. benzoic acidB. butanoic acidC. benzyl alcoholD. benzaldehyde |
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Answer» Correct Answer - A Those carbon having `alpha-` hydrogen convert into benzoic acid. |
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| 298. |
Aniline can be obtained by reduction of nitrobenzene withA. Fe/HClB. Sn/NaOHC. Electrolytic reduction under strong acidic conditionsD. All |
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Answer» Correct Answer - A Nitrobenzene reduced into aniline by metal/acid and electrolytic reduction in weakly acidic medium. |
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| 299. |
What single isomer would be found in greatest yeild when isopropyl chloride undergoes a Friedel-Crafts alklyation with t-butylbenzene?A. p-isopropyl-t-butylbenzeneB. m-isopropyl-t-butylbenzeneC. o-isopropyl-t-butylbenzeneD. None of these |
| Answer» Correct Answer - A | |
| 300. |
Which of following statements is/are correct ?A. `1^(@), 2^(@)` & `3^(@)` amines can be distinguished by Hinsberg reagent.B. Phenol does not gove Lucas test.C. Phenol & alcohols can be distinguished by neutral `FeCl_(3)`D. All of these |
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Answer» Correct Answer - D Lucas test is given by alcohols. Neutral `FeCl_(3)` test is given by phenols. |
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