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16401.

Question : In tropical rain forests, the canopy is thick and shorter plants growing below it, recive filtered light. How are they able to carry out photosynthesis ?

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SOLUTION :The intensity of light and amount affect the rate of PHOTOSYNTHESIS. So plants of various SIZE can perform photosynthesis but the rate of photosynthesis is different whichwill be dependetn o the intensity of light and amount.
16402.

Question : In transpiration/guttation water loss is dilute solution of inorganic and organic substances.

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SOLUTION :GUTTATION
16403.

Question : In .......... tracheids, thickening material is deposited in the form of rings.

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ANSWER :ANNULAR
16404.

Question : In Torpedo , electric organs are modified

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SCALES
muscles
TEETH
FINS

ANSWER :B
16405.

Question : In thre dimensional view, a transfer RNA molecule appearas

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L SHAPED
Y shaped
E shaped
S shaped

ANSWER :A
16406.

Question : In this type of selection no speciation takes place but the phenotype stability is maintained within the population over generation.

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STABILIZING selection
Directional selection
Disruptive selection
Adaptive radiation

Answer :A
16407.

Question : In this type of fossilization, the molecules of the dead body is replaced for molecules by minerals and the original substance being lost through disintegration.

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ACTUAL remains
petrifaction
natural moulds
cast formation

Answer :B
16408.

Question : In Theobroma cocoa, the inflorescence arise from ..............

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TERMINAL shoot
axillary part
TRUNK of PLANT
leaf node

Solution :trunk of plant
16409.

Question : In the young cob of maize, numerous filamentous hair-like structures protruding from its tip are

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LONG STYLES of carpels
Hair of SEEDS
HAIRY PROJECTIONS from the bracts
Anthers

Answer :A
16410.

Question :In the Whittaker five-kingdom system, organisms in the kingdom Protista are .............. or .............. eukaryotes.

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SOLUTION :UNICELLULAR , COLONIAL
16411.

Question : In the vascular bundle of leaf, xylem is located towards the adaxial side of the leaf.

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ANSWER :1
16412.

Question : In the urinogenital organs of rabbit which one of following part is present in male but not in female ?

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Urethra
FALLOPIAN TUBE
VAGINA
VAS deferens

Solution :Vas deferens
16413.

Question : In the tissues, the factors favourable for the dissociatio of O_(2) from oxyhaemoglobin are

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a, d, f, h
b, c, E, g
a, d, f, g
b, c, e, h

Solution :In the TISSUES, the factors favourable for the DISSOCIATION of `O_(2)` from oxyhaemoglobin are low `pO_(2)", high "pCO_(2)`, HIGHER temperature and low pH (or high `H^(+)`ion).
16414.

Question : In __________ the tissues of male and female genotype type form a mosaic.

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Haplo-diploidy
Gynandromorphy
Genic balance
Lygaeus type

Answer :B
16415.

Question : In the transpiration pull theory, whatcauses the tension that leads to liftingof the water column?

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Solution :Loss of water from the XYLEM to theadjacent cells creates a negative pressurecalled TENSION.
16416.

Question : In the tissues, high concentrations of carbon dioxide

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increases the affinity of haemoglobin to both oxygen and hydrogen
increases the affinity of haemoglobin to oxygen but decreases its affinity to hydrogen
decrease the affnitiy to haemoglobin to oxygen but increases its affinity to hydrogen
decrease the affinity of haemoglobin to both oxygen and hydrogen.

Solution :INCREASE in the `CO_(2)` content of the blood decreases the pH of the blood. This decreases the affinity of `O_(2)` with HB. This is calle Bohr effect and is closely realted to the fact that deoxygented Hb binds hydrgoen ions ore actively than does the Hb. This facililates GASEOUS exchanges because more` O_(2)` is released in the tissues where the amount of `CO_(2)` is more DUE to metablic ACTIVITY. At the same time, more `O_(2)` is taken up by the lungs or gills when the amount of `CO_(2)` is low.
16417.

Question : In the term 'taxonomy' the Greek word taxis means ________.

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SOLUTION :ARRANGEMENT
16418.

Question : In the successive seral stages there is a change in the

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Diversity of SPECIES of ORGANISMS
NUMBER of species of organisms
Increase of total boimass
All the above

Answer :D
16419.

Question : In the stomach, gastric acid is secreted by the……….. .

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GASTRIN SECRETING CELLS
parietal cells
PEPTIC cells
acidic cells

SOLUTION :N/A
16420.

Question : State whether the following statements are true or false.In the sodium-potassium pump, sodium is transported out of the cell and potassium is transported into the cell as ATP is broken by a membrane protein.

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ANSWER :1
16421.

Question :In the root nodules of leguminous plants, what is the role off nitrogenase and leghaemoglobin?

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Solution :Nitrogenase : CATALYSES the conversion of atmospheric/gaseous nitrogen into ammonia. Leghaemoglobin: COMBINES OXYGEN to protect the nitrogenase ENZYME (which is highly sensitive to oxygen),
16422.

Question : In the resting state of the neural membrane, diffusion due to concentration gradients, if allowed, would drive

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`Ca^(2+)` into the cell
`K^+` and `Na^+` out of the cell
`Na^+` into the cell
`Na^+` out of the cell

Solution :The concentration gradients across the resting MEMBRANE are maintained by the ACTIVE transport of ions by the sodium-potassium pump which TRANSPORTS `3 Na^+` outward for `2 K^+` into cell.
16423.

Question : In the resting state of the neural membrane diffusion due to concentration gradients, allowed, would drive

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`NA^(+)` into the CELL
`Na^(+)` outthe cell
`K^(+)` into the cell
`K` and `Na^(+)` out of the cell

16424.

Question : In the resting muscle fibre, tropomysin partially covers

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CALCIUM binding sites on troponin
actin binding sites on myosis
muyosin binding sites on actin
calcium binding sites on actin.

Solution :When the muscle is at REST, the tropomyosin molecule COVERS the binding site of the actin molecule where INTERACTION with myosin occurs.
16425.

Question : In the resting state of the neural membrane, diffusion due to concentration gradients, if allowed would drive:

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`NA^+` out of the CELL
`K^+` into the cell
`Na^+` into the cell
`k^+` and `Na^+` out of the cell

SOLUTION :Na+ into the cell
16426.

Question : In the regions of A-band, the numbers of thick filaments surrounding a thin filament are

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3 
6 
12

ANSWER :A
16427.

Question : In the pyramid for a hypothetical country, the ratio of reproductive females and pre-reproductive females is gt 2. Based on this data, the population size is expected to

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DECREASE steadily
Remain ROUGHLY similar
Will INCREASE for some TIME and then BECOME stable
Increase steadily

Answer :A
16428.

Question : In the plant cell, cytokinesis occurs by ………….

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Separation of the cytoplasm from the periphery to central region.
Separation of the cytoplasm THROUGHOUT the equatorial PLANE SIMULTANEOUSLY.
Separation of the cytoplasm from cell centre to its periphery .
Following of cytoplasm from two side at right angles to the plane of spindle pole.

ANSWER :C
16429.

Question : In the nucleotide namely adenosine-5'-tri phosphate, the sequence of linkages among N(base), C(sugar) and P(phosphate) is

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`C-P-N-P-P`
`N-C-P-P-P`
`P-C-N-P-P`
`P-P-P-C-N`

ANSWER :B
16430.

Question : In the neurilemma, the synaptic vesicles release neurotransmitters into the synaptic ciert by …………………… .

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SOLUTION :EXOCYTOSIS
16431.

Question :In the months of April and May one can see a yellowsulphur like dust floating in the Himalayan pine forests. What is it due to ?

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SOLUTION :POLLEN GRAINS of PINES.
16432.

Question : In the moss life cycle, the sporophyte:

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CONSISTS of leafy green shoots
is the heart-shaped prothallus
consists of a foot, a stalk, and a capsule
is the DOMINANT GENERATION

SOLUTION : consists of a foot, a stalk, and a capsule
16433.

Question : In the members of family Fabaceae, the petals showdescending imbricate aestivation.

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ANSWER :1
16434.

Question :In the members of Fabaceae stamens and pistilare enclosed and protected by the following

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Posterior STANDARD petal
Lateral wing petal
ANTERIOR sepals
Anterior keel PETALS

ANSWER :C
16435.

Question : In the meiotic cell division four daughter cells are produced by two successive divisions in which :

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FIRST division is EQUATIONAL and second is reductional
first division is reductional and second is equational
both divisions are reductional
both divisions are equational

Answer :B
16436.

Question : In the mechanism of action of a protein hormone, one of the second messengers is

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cyclic AMP
insulin
`T_(3)`
gastrin.

Solution :The molecules of hormones that are amino ACID derivatives, peptides or protiens are large and insoluble in lipids and cannot enter the target cell. Therefore, they actg at the cell surface. They bind to specific receptor molecuels located on the cell membrane and GENERATE second MESSENGER, e.g., cyclic AMP, `IP_(3),Ca^(++)`, etc.
16437.

Question : In the mechanism of action of a protein hormone, one of the second messengers is …………..

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Cyclic AMP
Insulin
`T_3`
GASTRIN

Solution :Secondary massengers INVOLVED in PROTEIN HORMONE mechanism.
16438.

Question : In the life cycle of Plasmodium exflagellation occurs in ……………. .

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sporozoties
microgametes
macrogametes
SIGNET RING

ANSWER :B
16439.

Question : In the life cycle of moss, which of the following generations is dominant ?

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HAPLOID GAMETOPHYTE
DIPLOID gametophyte
Haploid SPOROPHYTE
Diploid sporophyte

Solution :Haploid gametophyte
16440.

Question : In the life cycle of common round worm 2nd and 3rd moults occur in

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In the moist SOIL
Intestine of man
In the ALVEOLI of lungs
In the liver

Answer :C
16441.

Question : In the life cycle of ascomycetes and basidomycetes cells are

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Monokaryotic
Dikaryotic
both
None

ANSWER :C
16442.

Question : In the leaves of C_3 plants, peroxisomes are involved in a process celled

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RESPIRATION
`C_3` CYCLE
`C_2` cycle
`C_4` cycle

ANSWER :C
16443.

Question : In the kingdoms……….. and ........, the cell is a complete organism.

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SOLUTION :MONERA , PROTISTA
16444.

Question : In the internal ear the 'organ of corti'. Which bears hair cells, is located in

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SCALA tympanii 
Scala MEDIA 
Scala vestibuli 
SACCULUS 

ANSWER :C
16445.

Question : In the kingdom Animalia, which of the following is not an invertebrate ?

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PLATYHELMINTHES
Rotifera
ARTHROPODA
AMPHIBIA

SOLUTION :Amphibia
16446.

Question : In the inflorescence of Musa

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PEDICELLATE FLOWERS are arranged in acropetal manner
Sessile flowers are arranged in acropetal manner
Sessile flowers are arranged in CENTRIFUGAL manner
Sessile flowers are arranged in basipetal manner

ANSWER :B
16447.

Question : In the inflorescence of Cassia

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the length of pedicels decreases acropetally
The flowers are asymmetric with staminodes
The flowers open CENTRIFUGALLY with sepals and PETALS overlap one another in a PARTICULAR direction
The flowers appear to be in centripetal arrangement with a CENTRAL flower, a product of TERMINAL bud

Answer :A
16448.

Question :In the host body, HIV undergoes replication in

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Macrophages, T-helper cells
BLOOD plasma, RBC
Erythrocytes, TISSUE FLUID
NERVE cells, blood plasma

Answer :A
16449.

Question : In the hexaploid wheat, the haploid (n) and basic (x) number chromosomes are

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N = 21 and x = 21
n = 21 and x = 14
n = 21 and x = 7
n = 7 and x = 21

Answer :C
16450.

Question :In the graphical representation of pulmonary Volumes and capacities, 'x' denotes

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INSPIRATORY reserye volume
Total LUNG capacity
Expiratory capacity
lnspiratory capacity

Solution :