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21551.

Question : A section of the root nodule of a leguminous plant appears pinkish. Name the substance that imparts this colour and also mention its role.

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SOLUTION :LEGHAEMOGLOBIN, HELPS in NITROGEN FIXATION
21552.

Question : A scientist was studying the production of a protein that was released by an animal cell into a culture medium, she found that the protein only appeared in the culture medium after the added a few drops of a hormone to the cell. Before adding the hormone, she labelled the protein inside the cell with a fluorescent dye and looked at the cell under the lgiht microscope. The dye was seen in flattened sheets and tube. like structures throughout the cell, and in stacks of flattened sac-like structures. after adding the hormone, the dye was aslo seen as small dots clustered against the cell membrane, Which statement most likely explains these observations?

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The hormone STIMULATES protein synthesis in the CELL vacuole, the protein is then passed to the Golgi apparatus, and eventually passess through the cell membrane by passive diffusion.
The hormone triggers the synthesis of the protein in the endoplasmic reticulum and it is then secreted outside of the cell via channel proteins in the cell membrane
The protein is made in the endoplasmic reticulum, is passed to the Golgi APPARTUS and is secreted through hormone-stimulated exocytosis.
The protein is made in the Golgi apparatus, is passed to the endoplasmic recticulum and is secreted through hormone-stimulated pinocytosis.

Solution :Hormones bring about their characteristic effects on target cellls by modigying cellular activity. The GIVEN expertiment shows that the hormone is a releasing hormone which has increased the secretion of protein product in the target cell.
21553.

Question : A scientist isolated a piece of DNA whose length is 136 A^(@) by using chemical knives. He removed one complete turn from it. What will be the number of nucleotides present in it?

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200
100
80
60

Answer :D
21554.

Question : A scientist has come across a plant, which he feels is a new species. How will he go about its identification, classification and nomenclature ?

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SOLUTION :The scientist should look at various morphological features of plant. He should begin with broad features. Such as type of roots and venation. After that the scientist should look at the type of phyllotaxy, inflorescence etc. Which will help in classifying the plant in order and family. COMPARE the characteristic features with the similar INFORMATION available in the scientific literature and after that he can decide the EXACT systematic position of the plant name it according to the rules of binomial nomenclature and FIX its systemic position. Newly discovered plant can be identified with the help of taxonomic key, herbaria monographs and preserved plant specimen.
21555.

Question : A Science teacher told students that "Don't put the plant in green light for long time". What happens if a plant is exposed to green light for long time.

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Solution :The GREEN WAVE length of light has low energy levels and is not useful for photosynthesis. So if plants GET response of green light for long, hey may not carry out photosynthesis that might lead PLANT cell to starvation and death.
21556.

Question : A schematic sketch representing the altimentary canal of a cockroach is given below: Fill in the boxes with the appropriate organs from the list. No need to redraw the diagram. Crop , Salivary gland, Gizzard , Rectum, Malpighian tubules, Hepatic caeca.

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Solution :(a) Salivary gland (b) Crop (C) GIZZARD (d) Hepatic CAECA (e) MALPIGHIAN tubules (f) RECTUM
21557.

Question : A sample of urine was diagnosed to contain high content of glucose and ketone bodies. Based on this observation, answer the following : What is the condition called and how can it be rectified ?

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Solution :Diabetes mellitus in which GLUCOSE and KETONE bodies EXCRETED by urine patients can be treated with insulin THERAPY.
21558.

Question : A sample of urine was diagnosed to contain high content of glucose and ketone bodies. Based on this observation, answer the following : Name the cells on which this hormone acts.

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Solution :Insulin hormone MAINLY acts on LIVER cells and adipose TISSUE cells. It increases the consumption of CELLULAR glucose.
21559.

Question : A sample of urine was diagnosed to contain high content of glucose and ketone bodies. Based on this observation, answer the following : Which endocrine gland and hormone is related to this condition ?

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SOLUTION :Pancreas, endocrine GLAND and INSULIN HORMONE is ASSOCIATED with it.
21560.

Question : A rubber band stretches and reverts back to its original position. Bubble gum stretches, but it would not return to its original position. Is there any difference between the two processes ? Discuss it with respect to plant growth. [Hint : Elasticity (reversible) Plasticity (irreversible)]

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SOLUTION :
21561.

Question : A : SA node acts as pacemaker. R: SA node is located in the wall of right atrium near interatrial septa.

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A and B both are correct and RIS correct explanation of A .
A and RARE correctbut Ris notexplanationof A.
A is correctand R is false
A and Rare false

Answer :C
21562.

Question : A root system is extensively branched and bears a very large number of delicate root tips. How do the root tips manage to penetrate the hard core of soil?

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Solution :The cells of root cap SECRETE a MUCILAGINOUS substance that acts as a LUBRICANT. It facilitates the tender root tips to ENTER the hard crust of the soil.
Root cap is composed of parenchymatous cells and these cells store the starch. The starch grains are responsible for geotropism
21563.

Question : A risein P_(CO_(2))increases the oxygen- affinity of haemoglobin.

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ANSWER :FALSE
21564.

Question : A: Rhizopus does not form zygospores R: It shows heterothallism

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A and R both are CORRECT and R is correct EXPLANATION of A. 
A and R are correct but R is not explanation of A. 
A is correct and R is FALSE
A and R are false 

ANSWER :D
21565.

Question : A: Rhizoids of liverworts are unicellular. R : Liverworts can not develop multicellular rhizoids.

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A and R both are CORRECT and R is correct explanation of A. 
A and R are correct but R is not explanation of A. 
A is correct and R is FALSE
A and R are false. 

Answer :C
21566.

Question : A research scholar identified a new animal in his locality. How can he identify and classify the animal? Explain.

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Solution :Animal Kingdom is classified mainly based on the closely resembling characteristic features. Kingdom Animalia is characterised of eukaryotic, multicellular, HETEROTROPHIC organisms. They include about 35 phyla of which 11 are considered as MAJOR phyla.
2. Almost 99 percent of animals are invertebrates or animals without backbone. The remaining represents vertebrates or animals with backbone.
3. On the BASIS of the presence or absence of notochord (VERTEBRAL column), animals are also categorised into two major groups and they are non chordates and chordates.
4. Animals are broadly classified into invertebrates and chordates. The animals which lack vertebral column are called invertebrates.
21567.

Question : A renewable exhaustible natural resource is

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coal
petroleum
minerals
forest

Answer :D
21568.

Question : A red blood cell placed in 50% NaCl solution will :

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undergo CRENATION
swell and EVENTUALLY burst DUE to water intake
stay the same size
NONE of the above

Solution :undergo crenation
21569.

Question : (A): Red algae contribute in producing coral reefs. ( R): Some red algae secrete and deposit calcium carbonate over their walls,

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Both (A) and ( R) are true and ( R) is the CORRECT EXPLANATION of (A)
Both (A) and ( R) are true and ( R) is not the correct explanation of (A)
(A) is true but ( R) is false
Both (A) and ( R) are false

Answer :A
21570.

Question : A reaction is represented as AH_(2) + O_(2) rarr A + H_(2)O_(2). The enzyme that catalyses the above recation it belongs to subclass

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Oxidases
Reductases
DEHYDROGENASES
Hydrolases

Answer :A
21571.

Question : A radula is a unique organ for feeding found in :

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MOLLUSCS
ANNELIDS
ARTHROPODS
all of these

Solution :molluscs
21572.

Question : A quantosome is present in

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Mitochondria
CHLOROPLAST
Golgi bodies
ER

Solution :Chloroplast
21573.

Question : A: Pulmonary vein contains oxygenated blood. R : It brings oxygenated blood from lungs.

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A and B both are correct and RIS correct explanation of A .
A and Rare correctbut Ris notexplanationof A.
A is CORRECTAND R is FALSE
A and Rare false

ANSWER :A
21574.

Question : A : Pulmonary artery contains deoxygenated blood . R : It goes to respiratory organ for oxygenation from heart.

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A and B both are CORRECT and Ris correct explanation of A .
A and Rare correctbut Ris notexplanationof A.
A is correctand R is FALSE
A and Rare false

Answer :A
21575.

Question : A psychotic drug LSD is derived from

Answer»

CLAVICEPS
Candida
Penicillium
PUCCINIA

21576.

Question : A protozoan locomotes by one of three structures ……..,………. Or ……….

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SOLUTION :PSEUDOPODIA , CILIA FLAGELLA
21577.

Question : A: Prothrombin is essential for blood clotting. R : Prothrombin is synthesized in the liver in presence of Ca^(++).

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A and B both are CORRECT and RIS correct explanation of A .
A and Rare correctbut Ris notexplanationof A.
A is correctand R is FALSE
A and Rare false

Answer :C
21578.

Question : A protoplast is a cell :

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WITHOUT nucleus
undergoing DIVISION
without cell wall
without PLASMA membrane

ANSWER :C
21579.

Question : (a) Protonephridia - Metanephridia (b) Dilute urine - Hyperosmotic (c) Concentrated urine - Hypo osmotic (d) Nephron - Functional unit of liver

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ANSWER :(a)
21580.

Question : A prothallus is

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A structure in pteridophytes formed before the thallus develops 
A sporophytic free living structure formed in pteridophytes 
A gametophyte free living structure formed in pteridophytes 
A PRIMITIVE structure formed after fertilization in pteridophytes 

SOLUTION :Generally it is a gametophytic stage in pteridophytes. The spores germinate to give rise to PROTHALLUS. It is short-lived, UNCLEAR and heart shape structure. Rhizoids and egg appratus reproductive organs LIKE are produced on the horizontal surface of it.
21581.

Question : A protein deficiency disease is :

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Kwashiorkar
Marasmus
PELLAGRA
Osteomalacia

Answer :A
21582.

Question : A process is occurring throughout the day, in 'X' organism. Cells are participating in this process. During the process ATP, CO_(2) and water are evoled. It is not a light dependent process. (a) Name the process. (b) It is a catabolic or an anabolic process ? What could be the raw material to this process ?

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Solution :(a) NAME of the process is cellular respiration.
(b) It is a catabolism process in which one molecule of glucose is BURNT.
`C_(6)H_(12)O_(6) + 6O_(2) rarr 6CO_(2) + 6H_(2)O + "ENERGY"`
(c ) In this process glucose and O_(2)` USED. That is a product of photosynthesis.
21583.

Question : A process is occurring throughout the day, in 'X' organism. Cells are participating in this process. During this process ATP, CO_2 and water are evolved. It is not a light dependent process. (a) Name the process. (b) Is it a catabolic or an anabolic process? (c) What could be the raw material of this process?

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Solution :(a) Name of PROCESS is respiration.
(B) CATABOLIC.
(c) Glucose, fat or protein.
21584.

Question : A process is occurring throughout the day, in 'X' organis. Cells are participating in this process. During this processATP, CO_(2) and water are evolved. It is not a light dependent process. (a) Name the process (b) Is it a catabolic or an anabolic process ? ( c) What could be the raw material of this process ?

Answer»

Solution :(a) The NAME of the proces is cellular respiration.
(b)It is a CATABOLIC process which involves break down of glucose molecule.
`underset("Cabohydrate ")(C_(6)H_(12)O_(6))+ underset("oxygen ")(6O_(2)) to underset("carbon dioxide")(6CO_(2))+ underset("WATER")(6H_(2)O)+underset("(ATP)")("Energy")`
( c) Raw material for this process is glucose molecule and oxygen, which are products of PHTOSYNTHESIS, occuring in plants.
21585.

Question : A primary root grows from 5 cm to 19 cm in a week. Calculate the growth rate and relative growth rate over the period.

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Solution :Growth is DEPENDENT on three factors - initial size `(W_(0))`, rate of growth (r) and time interval `(+)` for which the rate of growth is retained., Where,
`therefore""W_(1)=W_(0)E^(rt)""W_(1)="Final size,"`
`W_(0)="Initial size,"`
r = Growth rate,
t =Time,
e = Base of natural logarithm.
`19=5xx(2.7)^(rxx7)=(2.7)^(r)xx7`
`therefore""3.8=(2.7)^(rxx7)`
`log 3.8 xxr xx7xxlog(2.7)`
`0.5798=rxx7xx0.4314`
`0.5798=r=0.1907`
`bar(7xx0.4314)`
`"RELATIVE growth rate"=("Growth in givenperiod")/("MEASUREMENT at start of time PERIOD")`
`=(19)/(5)=3.8 cm`
Thus absolute growth rate is 0.1907 while relative growth rate is 3.8 cm.
21586.

Question : A primary meristem that produces secondary tissues is

Answer»

Apical MERISTEM
CORK CAMBIUM
Inter fascicular cambium
Fascicular VASCULAR cambium

Answer :D
21587.

Question : A pregnant female delivers a baby who suffers from stunted growth mental reardation low intelligence quotient and abnormal skin,This is the result of

Answer»

Low SECRETION of growth hormone
CANCER of the THYROID gland
Over secretion of pars distali
Deficiency of iodine in diet.

Solution :Cancer of the thyroid gland
21588.

Question : A portion of cross section of leaf is shown in the diagram. Answer the following:- A) Label 1 to 4. B) What kind of anatomy is shown in the diagram ? C) Write the structure and function of 2 and 4.

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Solution :A) 1). Mesophyll cells 2) Mesophyll chloroplasts
3) Cells of bundle shealth. 4) Bundle sheath chloroplasts.
B) Kranz anatomy. This kind of anatomy occurs in the LEAVES of `C_(4)` PLANTS in whichthe bundle-sheath cells are arranged in a wreath-like manner.
C) Structure and function of 2. Mesophyll chloroplasts: Mesophyll chloroplasts are granal and contain thylakoids that are stacked to form grana. These chloroplasts PERFORM LIGHT reaction with the evolution of molecular `O_(2)`. The `CO_(2)` is fixed by phospho enol pyruvic acid to form 4 carbon oxalo acetic acid.

4. Bundle sheath chloroplasts are agranal, i.e., grana are absent and the thylakoids are present only as stroma lamellae. Bundle sheath chloroplasts perform `C_(3)` cycle in which the `CO_(2)` is fixed by RuBP catalysed by the enzyme RUBISCO (RuBISCO is present only in bundle sheath chloroplasts). `CO_(2)` is made available by DECARBOXYLATION of 4 carbon organic acid (malic acid).
21589.

Question : A polysaccharide constituent found in the matrix of cartilage is:

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Ossein
COLLAGEN
CHONDROITIN
Hyaline

ANSWER :C
21590.

Question : A pollen tube enters the ovule through chalaza lying opposite the micropyle. It will enter the embryo sac through

Answer»

CHALAZAL END
laterally
ANTIPODAL haustorium
micropylar end

ANSWER :D
21591.

Question : A player has sustained a severe injury during football practice and was told that he has a torn knee cartilage. Can he expect a quick uneventful recovery? Explain your response.

Answer»

Solution :1. The recovery WOULD depend on severity and location of injury.
2. Minor and moderate tears can be treated by non surgical METHODS.
3. Recovery period may be from 6-8 WEEKS.
4. In severe cases, surgery may be repaired.
5. HEALING period may extend UPTO 3 months in this case.
21592.

Question : A plasmolysed cell can be deplasmolysed by placing it in

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PURE water or HYPOTONIC solution
hypertonic solution
isotonic solution
saturated solution.

Solution :the swelling up of a plasmolysed protoplast under the influence of hypotonic solution or water is called deplasmolysis It is DUE to endosmosis Deplasmolysis is POSSIBLE only immediately after plasmolysis otherwise the cell protoplast becomes permanently damaged. During deplasmolysis water diffuses into protoplast.
21593.

Question : A plant with vascular tissues, but without seeds belong to

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GYMNOSPERMS
ANGIOSPERMS
PTERIDOPHYTA
Bryophyta

Answer :C
21594.

Question : A plant with stolons and whorled phyllotaxy is

Answer»

Nerium
Guava
CALOTROPIS
ALSTONIA

ANSWER :A
21595.

Question : A : Plant usually bend towards the source of light. R : Shoot apex shows positive phototropism because of differential growth caused due to unequal distribution of auxin.

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A and R both are CORRECT and R is correct EXPLANATION of A. 
A and R are correct but R is not explanation of A. 
A is correct and R is FALSE
A and R are false 

ANSWER :A
21596.

Question : A plant tissue, when stained, showed the presence of hemicellulose and pectin in cell wall of its cells. The tissue represents (A) Collenchyma (B) Sclerenchyma (C) Xylem (D) Meristem

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COLLENCHYMA
Sclerenchyma
Xylem
Meristem

Solution :Collenchyma
It is a group of cells of SPECIFIC type for mechanical support. Mainly pectin and HEMICELLULOSE thickening at the CORNERS of the cells.
21597.

Question : A plant tissue when stained, showed the presence of hemicellulose and pectin in cell of its cels. Name the tissue.

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SOLUTION :COLLENCHYMA.
21598.

Question : A plant that grows vegetatively during the first season and undergoes flowering and fruiting during the second season is called as …………………

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BIENNIAL
THEROPHYTE
PERENNIAL
GEOPHYTE

SOLUTION :biennial
21599.

Question : A plant species shows several morphological variations in response to altitudinal gradient. When grown under similar conditions of growth, the morphological variations disappear and all the variants have common morphology. What are these variants called ?

Answer»

Solution :These variants are called biotypes. All biotypes are similar GENETICALLY but they are DIFFERENT MORPHOLOGICALLY. The morphological difference happens because of the DIFFERENCES in abiotic factors like temperature, pH of soil, climate ETC. The difference in abiotic factors is the result of different altitudinal gradients.
21600.

Question : A plant species A has a diploid number of chromosomes as 12. Another plant species B has a diploid chromosome number of 16. The allopolyploid developed by hybridization of A and B shall have amphidiploid chromosome number as

Answer»

14
28
40
56

Answer :B