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21601.

Question : A plant that grows for many years that flowers and set fruits for several season duringthe life span is called as …………………

Answer»

geophytes
annual
biennial
ephemerals

Solution :geophytes
21602.

Question : A plant shows thallus level of organization. It shows rhizoidsand is haploid. It needs water to complete its life cycle because the male gametes are motile. Can you identify the group to which it belongs?

Answer»

SOLUTION :BRYOPHYTES
21603.

Question : A plant shows thallus level of organization. It shows rhizoids and is haploid. It needs water to complete its life cycle because the male gametes are motile. Identify the group to which it belongs to

Answer»

Pteridophytes 
Gymnosperms
MONOCOTS 
Bryophytes 

Solution :• Bryophytes is such a group of plants in which gametophytic stage is haploid and has thallus. Motile male gametes - special reproduction structure are produced in Antheridia.
• These gametes need thin layer of WATER by doing movements to REACH to female reproductive organ - ovary (Archegonia).
•While DIVISION of labour is SEEN in pteridophytes, gymnosperms and monocots. Their plant body possesses higher type of body organization.
21604.

Question : A plant shows thallus level of organization. It shows rhizoids and is haploid. It needs water to complete its life cycle because the male gametes are motile. It may belong to

Answer»

PTERIDOPHYTES
Gymnosperms
Monocots
BRYOPHYTES

ANSWER :D
21605.

Question : A plant showing reticulate venation and a woody stem is a

Answer»

PTERIDOPHYTE
GYMNOSPERM
MONOCOT
DICOT

21606.

Question : A plant secretion that is a efficient preservative ………..

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AGAR Agar
Careegenin
Amber
Ergot

ANSWER :C
21607.

Question : A plant requires potassium mainly for?

Answer»

SOLUTION :OPENING and CLOSING of STOMATA
21608.

Question :A plant requires phosphorus for its …………………………

Answer»

SOLUTION :CELL MEMBERS
21609.

Question : A plant may have different names in different regions or the country of world. How do botanists solve this problem?

Answer»

Solution :To solve this problem, botanists have devised the system of BINOMIAL nomenclature so that a particular species can have unique name for the purpose of scientific STUDY. ICBN ENSURES that such name has not been USED for any other organism. Each name has two components the generic name and the species name. This system of NAMING is called bionomical nomenclature given by Carolus Linnaeus.
21610.

Question : A plant in your garden avoids photorespiratory losses , has improved water use efficiency , shows high rates of photosynthesis at hifh temperatures and has improved efficiency of nitrogen utilisation . In which of the following physiological groups would you assign this plant?

Answer»

`C_(4)`
CAM
Nitrogen FIXER
`C_(3)`

SOLUTION :`C_(4)`
21611.

Question : A plant leaf shows reticulate venation. What kind of roots would it have?

Answer»

SOLUTION :TAP ROOT.
21612.

Question : A plant if transpiring rapidly. Is it due to presence of root pressure?

Answer»

SOLUTION :Such transpiring plant will not SHOW ROOT PRESSURE. Instead a negative pressure will be observed .
21613.

Question : A plant has 24 chromosomes in microspore mother cell the number of chromosomes in its endosperm will be

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36
24
12
48

Answer :A
21614.

Question : A plant having two genomes and four chromo somes is

Answer»

OPHIOGLOSSUM
HAPLOPAPPUS
Pisum
Allium

ANSWER :B
21615.

Question : A plant growing in a tree as epiphyte accumulates malic acid in dark and cells contains large storage vacuoles. Identify the type of pathway that takes place in this plant.

Answer»

`C_(4)` PATHWAY
Glycolate Metabolic pathway
Di carboxylic ACID pathway
CAM pathway

Solution :CAM pathway
21616.

Question :A plant cell when kept in a solution got plasmolysed. What was the natureof the solution.

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SOLUTION : HYPERTONIC.
21617.

Question : A plant cell when kept in a certain solution got plasmolysed. What was the nature of the solution ?

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SOLUTION :The solution is HYPERTONIC.
21618.

Question : A plant cell attains turgidity due to:

Answer»

electrolysis
exosmosis
plasmolysis
endosmosis

21619.

Question : A plant cell is kept in a hypotonic solution. What will happen to the solute potential of this cell?

Answer»

SOLUTION : It DECREASES.
21620.

Question : A Pinus does not have

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RESIN canals
xylem TRACHEIDS
ovuliferous SCALES
TWO COTYLEDONS

21621.

Question : A piece of wood having no vessels (trachea) must be belong to (A) Teak (B) Mango (C) Pine (D) Palm

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Teak
MANGO
Pine
Palm

Solution :Pine
It is a Gymnosperm. The PLANTS of this group does not possess VESSELS but instead of that they possess TRACHEIDS while Teak, Mango and Palm are angiospermous plant. In xylem of angiosperms vessels, tracheids, parenchymatous cells and xylem FIBRES are present.
21622.

Question : A piece of chromatin with 40 H 4 proteins molecules contains _____number of

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5
10
40
20

Answer :D
21623.

Question : A : Phycomycetes are generally called algal fungi. R: It is believed that phycomycetes have evolved from algae (A) A and R both are correct and R is correct explanation of A. (B) A and R are correct but R is not explanation of A. (C) A is correct and R is false. (D) A and R are false

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A and R both are CORRECT and R is correct EXPLANATION of A. 
A and R are correct but R is not explanation of A. 
A is correct and R is FALSE
A and R are false 

ANSWER :A
21624.

Question : A : Phylogenetic and natural classifications are similar. R : The organisms related evolutionarily are usually similar morphologically also

Answer»

A and R both are CORRECT and R is correct EXPLANATION of A. 
A and R are correct but R is not explanation of A. 
A is correct and R is FALSE
A and R are false 

ANSWER :A
21625.

Question : A phylloclade with one or two internodes only is called a ..............

Answer»

SOLUTION :caldode
21626.

Question : (a) Phycobilins - Proteinaceous pigment (b) Lycopene - Yellow colour (c) Lutein - Red pigment (d) Carotene - Vitamin C

Answer»


SOLUTION :PHYCOBILINS - PROTEINACEOUS PIGMENT
21627.

Question : A phospholipid molecule is amphipathic and produce two layers coming in contact with H_(2)O. The head of phospholipid molecule is

Answer»

at an angle of `40^(@)`
at the OUTER surface
on the inner SIDE
embedded in protein MOLECULES.

ANSWER :B
21628.

Question : A phosphoglyceride is always made up of

Answer»

Only a SATURATED fatty ACID esterified to a GLYCEROL MOLECULE to which a phosphate group is also attached
Only an UNSATURATED fatty acid esterified to a glycerol molecule to which a phosphate grouup is also attached
A saturated or unsaturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
A saturated or unsaturated fatty acid esterified to a phosphate group which is also attached to a glycerol molecule

Answer :C
21629.

Question : A phospholipid molecule has a head and two tails. Thetails are found :

Answer»

at the surfaces of the MEMBRANE
in the INTERIOR of the membrane
SPANNING the membrane
both (a) and (B)

SOLUTION :in the interior of the membrane
21630.

Question : (A) Petrifaction - Impression (B) Actual remains - Volcanic ash (C ) Tail in Baby - Atavism (D) Homologous Structures - Flippers of Dolphin

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A only
A and B
B and C
D only

Answer :B
21631.

Question : A person with swollen neck consults a doctor,Doctor advise to avoid iodized salt.Name his disorder.

Answer»

SOLUTION :EXOPHTHALMIC GOITRE
21632.

Question : A person with swollen neck consults a doctor,Doctor advise to avoid iodized salt State 3 features of the disease

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Solution :1.The ENLARGEMENT of the thyroid GLAND 2.it causes the EYES to protrude 3.This disorder OCCURS more often in females.
21633.

Question : A person with cirrhosis of the liver has lower than normal levels of plasma proteins and higher than normal GFR. Explain why a decrease in plasma protein would increase GFR.

Answer»

SOLUTION :The net filtration pressure of 10 MMHG is responsible for the renal filtration. Net filtration Pressure = Glomerular hydrostatic pressure - (Colloidal OSMOTIC pressure + Capsular hydrostatic pressure). Therefore, when there is decrease in plasma proteins, the value of Colloidal osmotic pressure + Capsular hydrostatic pressure decreases. This CONTRIBUTES to the INCREASED net filtration pressure resulting in increase of GFR.
21634.

Question : A person with blood group A has

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ANTIGEN A and ANTIBODY B
antigen B and antibody a
both antibodies
no antibody and no antigen

Solution : antigen A and antibody b
21635.

Question : A person with A -ve blood group is injured severly in an accident. His relatives with A +ve and B -ve blood groups were ready to donate blood for him. Infer the consequences if he receives blood from them.

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SOLUTION :ANTIGEN and ANTIBODY interaction/Coagulation of blood/Clotting of blood/Agglutination/Incompatability/Death
21636.

Question :A person who is on a long hunger strike and is surviving only on water will have:

Answer»

LESS UREA in his urine
More sodium in his urine
Less AMINO ACIDS in his urine
More glucose in his blood

Answer :B
21637.

Question : A person who is on a long hunger strike and is surviving only on water, will have________

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Less amino acids in his urine
More GLUCOSE in his BLOOD
Less urea in his urine
More sodium in his urine

SOLUTION :Less urea in his urine
21638.

Question : Apersonwhith normal tidal volumehasarespirtoryrate of 14 breaths per mintue. What will be the total tidal respiratory volumeper mintue ?

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3800 ml/mt
7000 ml/mt
14000 ml/mt
1300 ml/mt

Answer :B
21639.

Question : A person surffers punctures in his chest cavity in an accident, without any damage t the lungs, its effect could be

Answer»

reduced breathing rate
rapid INCREASE in breathing rate
no change in respiration
cessation of breathing.

Solution :Punctures in a person's CHEST MAY lead to LOSS of PRESSURE gradient.
21640.

Question : A person undergoing prolonged fasting his urine will be found to contain abnormal quantities of .....

Answer»

Fats
Amino ACID
GLUCOSE
KETONES

SOLUTION :Ketones
21641.

Question :A person suffering from a disease caused by Plasmodium, experiences recurring chills and fever at the time when

Answer»

the sporozoites released from RBC s are being rapidly killed and broken down inside SPLEEN
the trphozoites reach maximum growth and give out certain toxins
the parasite after its rapid multiplication inside RBC s RUPTURES them releasing the merozoites & hemozoin
the MICROGAMETOCYTES and macrogameto-cytes are being destroyed by the WBCs

Answer :C
21642.

Question : A person met with an accident with severe head Injury. He is taken to hospital, where doctors declared 'dead'. But his heart is functioning. Explain the amazing property of heart.

Answer»

Solution :1. The type of heart in human is myogenic because the heart beat ORIGINATES from the muscles of the heart.
2. The NERVOUS and endocrine systems work together with paracrine SIGNALS (metabolic activity) to influence the diameter of the arterioles and alter the blood flow.
3. The neuronal control is achieved through autonomic nervous system (sympathetic and parasympathetic).
4. Sympathetic neurons release norepinephrine and adrenal medulla releases epinephrine.
5. The two horinones bind to `beta`-adrenergic receptors and increase the heart rate.
6. The parasympathctic neurons scomm acetylcholine that binds to muscarinic receptor and decreases the heart beat.
7. Vasopressin and ANGIOTENSIN II, involved in the regulation of the kidneys, results in vasoconstriction while natriuretic PEPTIDE promotes vasodilation.
Vagus nerve is a parasympathetic nerve that supplies the atrium especially the SA and the AV nodes.
21643.

Question : A person is undergoing prolonged fasting, his urine will contain abnormal quantities of

Answer»

fats
ketones
amino acids
glucose

21644.

Question : A person is unable to sleep normally. He may not get proper secretion of ..............

Answer»

Thyroxine
Vasopression
MELATONIN
Oxytocin

SOLUTION :Melatonin
21645.

Question : A person is having problem with calcium and phosphorus metablism in his body which one of the following glands may not be functionoing properly?

Answer»

Parotid
Pancreas
Adrenal cortes
Parathyroid

Solution :Parathyroid GLANDS LOCATED behind the thyroid gland, produce a hormone called parathormone. This hormone maintains calcium and PHOSPHORUS balance in the body. Thus, if a person is having PROBLEM with calcium and phosphorus metabloism in this means, his parathyroid glands are not functioningproperly.
21646.

Question : A person having bothe antigen Aand antigen B on the surface of RNCs belongs to blood group

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A
B
AB
O

Solution :AB
21647.

Question : A person had roti and dal for his lunch. Trace the changes in those during its passage through the alimentary canal.

Answer»

Solution :(1) Digestion of roti (carbohydrates) :
(a) Digestion of carbohydrates in oral cavity :In mouth chapati mixes with saliva. In saliva salivary Amylaze (ptylin) enzyme is present which CONVERTS starch of chapati into Maltose, Isomaltose and small dextrin (`alpha`-dextrin). 30% starch is hydrolysed in mouth.
Starch `underset"pH 6-8"overset"Salivary amylase"to` Maltose + isomaltose + `alpha`-dextrin.
(b) Digestion of carbohydrates in small intestine: From mouth to oesophagus and from there to stomach the path of half digested chapati is regulated by peristalsis (waves of alternate muscular contraction of oesphagus).
The food is stored in stomach for 4-5 hours. There is no enzyme present in gastrine causing digestion of carbohydrates. This half digested food is now known as chyme. Following process is seen in intestine.
(i) Process of pancreatic juice : The carbohydrate of chyme is hydrolysed into disachharide by pancreatic amylase.
Polysachharide (starch) `overset"amylaze"to` Disachharide .
(ii) The process of intestinal juice or succus entericus : Succus entericus possesses MALTASE, iso maltase, sucrase (invertase), lactase and a dextrin. These enzymes work on food and convert them into simple compounds like glucose, fructose or galactose.
Maltose `overset"Maltase"to` Glucose +Glucose
Isomaltose `overset"Isomaltase"to` Glucose + Glucose
Sucrose `overset"Sucrase"to` Glucose + Fructose
Lactose `overset"Lactase"to` Glucose + Galactose
`alpha`-dextrin `overset(alpha- "Dextrinase")to` Glucose .
(2) Digestion of protein : Proteins are made of amino acids, during its digestion protein decomposes and gets converted into amino acid.
There is no enzyme present for digestion of protein in saliva so protein is digested in stomach.
(a) Digestion of protein in stomach: Stomach generally stores food for 4-5 hours gastrin gland secretes gastric juice. It possesses HCI, inactive enzymes, pepsinogen and renin.
Following processes are DONE in stomach :
Pepsinogen (inactive) `overset"dil HCl"to` Pepsin
Protein `overset"Pepsin"to` Peptones + PROTEOSES
Prorenin (inactive) `overset"HCl"to` Renin (active)
(b) Digestion of protein in small intestine :
(i) Process of panereatic juice : Trypsinogen, chymotrypsinogen and procarboxy peptidase are associated with digestion of protein.
Trypsinogen `overset"Enterokinase"to` TRYPSIN
Proteins `overset"Trypsin"to` Dipeptide
Chymotrypsinogen `overset"Trypsin"to` Chymotrypsin
Peptones `overset"Chymotrypsin"to` Dipeptides
Procarboxypeptidase `overset"Trypsin"to` Carboxypeptidase
Proteoses `overset"Carboxypeptidase"to` Dipeptides
(ii) The action of intestinal juice succus entericus (intestinal juice) possesses enzyme enterokinase, amino peptise and dipeptise. It shows following processes
Peptides `overset"Amino peptidase"to` Amino acid
Dipeptides `overset"Dipeptidase"to` Amino acid
Megamolecules are converted into simple components. That is an end product of chapati and Dal which are absorbed by villies of intestine. Undigested food is removed as faeces.
21648.

Question : Aperson attains a maximum of 4 feet height. What could be the reason for this?

Answer»

Hypersecretion of somatotropic HORMONE
Hypersecretion of ACTH
HYPOSECRETION of TSH
Hyposecretion of somatotropic hormone

Solution : Hyposecretion of somatotropic hormone
21649.

Question : A perennial shrub has compound leaves and solitary zygomorphic and epigynous flowers. Each flower reveals dichlamydeous condition with many stamens and multiple fruits with exalbumius seeds. What is the ratio of advanced and primitive characters in it.

Answer»

`1:2`
`2:3`
`1:1`
`3:2`

ANSWER :C
21650.

Question : A patient was advised to give his blood sample between 10.00 pm and 4.00 am for clinical analysis. Identify the parasite that might have infected him.

Answer»

PLASMODIUM vivax
Taenia solium
Entamoeba histolytica
Wuchereria bancrofti

Answer :D