

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
1001. |
Question : When a green pod containing pea plant is crossed with a yellow pod containing pea plant in the progeny yellow pod containing plants are also produced, so green pod containing plant is |
Answer» only heterozygous |
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1002. |
Question : When a hybrid tall pea plant is cross fertilized with a dwarf pea plant , the ratio of tall is to dwarf plants grown from the seeds will be : |
Answer» 0.12569444444444 |
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1003. |
Question : When a green full pod producing pea plant ils crossed to an yellow constricted pod producing pea plant in the progen gren fullpod and green constricted pod producing pea plants only are formed in 1:1 ratio. The genotype of tested individual is |
Answer» GGFF |
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1004. |
Question : When a hybrid (AaBbCcDd) is selfed then the genotypes AABbCCDd, AaBBCcDd, AaBbCcDd, aabbccdd would be in a proportion of :- |
Answer» `2 : 4 : 8 : 21` |
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1005. |
Question : When a gene pair contains two different genes controlling different traits of a character, it is |
Answer» HOMOZYGOUS |
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1006. |
Question : When a gerey color seed producing pea plant is crossed to white color seed producing pea plant, in the progeny 164 grey seed producing and 156 white seed producing plants are obtained. This cross is |
Answer» Receprocal cross |
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1007. |
Question : When a gamete without any fusion develops into a new organism the phenomenon is called SyngamyExternal FertilizationParthenogenesisParthenocarpy |
Answer» Syngamy |
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1008. |
Question : When a gamete without any fusion develops into a new organism the phenomenon is called: |
Answer» SYNGAMY |
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1009. |
Question : When a gamete without any fusion develop into a new organisms the phenomenon is called |
Answer» Syngamy |
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1010. |
Question : When a foreign DNA is introduced into an organism, how is it maintained in the host and how is it transferred to the progeny of the organism ? |
Answer» SOLUTION :Foreign gene is USUALLY ligated to a plasmid vector and introduced in the HOST. As plasmid replicates, and makes MULTIPLE copies of itself, so does the foreign gene gets replicated and its copes are made. When the host organism divides, its progeny also receives the plasmid DNA containing the foreign gene.![]() |
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1011. |
Question : When a DNA molecule with one radioactive strand undergoes repeated replications in a medium without radioactivity for five times the number of radio labelled strands in the daughter DNA molecules |
Answer» 2 |
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1012. |
Question : When a diploid female plant is crossed with a tetraploid male, the ploidy of endosperm cells in the resulting seed |
Answer» tetraploidy |
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1013. |
Question : When a dihybrid cross is fit into a Punnet square with 18 boxes, the maximum number of different phenotypes available are |
Answer» 8 |
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1014. |
Question : When a dihybrid cross is fitted into a pannet square with 16 boxes, the maximum number of different phenotypes available are |
Answer» 4 |
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1015. |
Question : When a cross is made between tall plant with yellow seeds [TtYy1 and tall plant with seed [Tt yy], What proportion of phenotype in the offspring could be expected to be |
Answer» SOLUTION :![]() = TALL green - 3/8 or 6/16 = DWARF green - 1/8 or 2/16 =PHENOTYPE RATIO = 3:1 |
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1016. |
Question :When a dihybrid cross is fit into a punnett square with 16 boxes , the maximum number of different phenotypes available are : |
Answer» 8 |
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1017. |
Question : When a dihybrid cross is fit into a Punnet square with 16 boxes, the maximum number of different phenotypes available are |
Answer» 8 |
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1018. |
Question : When a corss is made pinkflowered and red flowered snapdragon plants, what proportionof phenotypein the offspring could beexpected to be |
Answer» 0.25 |
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1019. |
Question : When a cross is conducted between black feathered hen and a white feathered cock , blue feathered fowls are formed . When these fowls are allowed for interbreeding , in F_1 -generation , there are 20 blue fowls . What would be the number of black and white fowls . |
Answer» BLACK 20 , WHITE 10 |
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1020. |
Question : When a connective is prolonged into a feathery appendix beyond the anthers it is called ………….andis found inn…………. |
Answer» distractile NERIUM |
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1021. |
Question : When a cell is plasmolysed |
Answer» TURGOR PRESSURE BECOMES negative |
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1022. |
Question : "When a cell is placed in isotonic solution water will come out of it by exosmosis" . Is it true or false . |
Answer» |
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1023. |
Question : When a cell is fully turgid which of the following will be zero |
Answer» TURGOR PRESSURE/pressure potential |
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1024. |
Question : When 12 CO_2 molecueles are utilized in C_2 cycle, number of troise phosphates exported out from the chloroplast into the cytosol for the synthesis of hexose will be |
Answer» 2 |
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1025. |
Question : When 54 molecules of CO_2 fixed by RuBisCO in a C_3 plant , number of G_3 -P participate in regeneration phase respectively |
Answer» Answer :D | |
1026. |
Question : wheat variety having high protein content is |
Answer» Answer :D | |
1027. |
Question : wheat root cells have 42 chromosomes. the number of chromosomes in a cell of pollen grain is |
Answer» ANSWER :B | |
1028. |
Question : Wheat variety, Atlas-66 is improved for …………. . |
Answer» HIGH proteins |
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1029. |
Question : Wheat is which of the following types of fruit |
Answer» Berry |
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1030. |
Question : Whch one of the following is an important breed of fowl? |
Answer» Nageswari |
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1031. |
Question : Whatever be the life span, death of every individual organism is a certainty, i.e., no individual is immortal, except |
Answer» HUMAN beings |
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1032. |
Question : What you meant by resource partitioning in an ecosystem. |
Answer» SOLUTION : If TWO SPECIES foe the same resource, they avoid competition by choosing different times for feeding or different foraging patterens.This is called resource PARTITIONING. | |
1033. |
Question : What .X. indicates in the given figure? |
Answer» Geitonogamy |
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1034. |
Question : What would happen when one grows a recombinant bacterium in a bioreactor but forget to add antibiotic to the medium in which the recombinant is growing ? |
Answer» Solution :In the absence of ANTIBIOTIC, there will be no pressure on RECOMBINANTS to retain the PLASMID (containing the gene of your interest). Since, maintaining a high copy number of plasmids is a METABOLIC burden to the microbial cells, will thus tend to lose the plasmid. | |
1035. |
Question : What would happen when one grows a recombinant bacterium in a bioreactor but forget to add antibiotic to the medium in which the recombinant is growing? |
Answer» SOLUTION :In the absence of antibiotic, all bacteria will grow successfully. There will be no selection pressure. So there will be no pressure on transformed bacteria to RETAIN the recombinant PLASMID and they MAY TEND to lose these plasmids. | |
1036. |
Question : What would happen to immune system, if thymus gland is removed from the body of a person? |
Answer» Solution :Thymus is the primary lymphoid organ. In thymus GLAND, immature lymphocytes DIFFERENTIATE into antigen-sensitive lymphocytes. If thymus gland is removed from the BODY of a person, the immune system BECOMES WEAK. As a result the person.s body becomes prone to infectious diseases. |
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1037. |
Question :What would happen if oxygen availability to activated sludge flocs is reduced ?(A) It will slow down the rate of degradation of organic matter.(B) The centre of flocs will become anoxic, which would cause death of bacteria and eventually breakage of flocs.(C) Flocs would increase in size as anaerobic bacteria would grow around flocs.(D) Protozoa would grow in large numbers. |
Answer» It will slow down the rate of degradation of ORGANIC matter. |
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1038. |
Question : What would happen if oxygen availability to activated sludges flocs is reduced ? |
Answer» It will slow down the rate of degradation of organic matter |
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1039. |
Question : What would happen if histones were to be mutated and made rich in acidic amino acids such as aspartic acid and glutamic acid in place of basic amino acids such as lysine and arginine? |
Answer» Solution :If HISTONE proteins were rich in acidic amino acids INSTEAD of basic amino acids then they may not have any role in DNA packaging in eukaryotes as DNA is ALSO negatively charged molecule. The packaging of DNA around the nucleosome would not happen. Consequently, the chromatin FIBRE would not be formed. | |
1040. |
Question :What would happen if our intestine harbours microbial flora exactly similar to that found in the rumen of cattle ? |
Answer» SOLUTION :If our intestine HARBOURS microbial flora EXACTLY similar to that found in the RUMEN of cattle then we would be able to digest the cellulose PRESENT in our food. | |
1041. |
Question : Whate would happen if in a gene encoding a polypeptide of 50 amino acids , 25^(th) codon (UAU) is mutated to UAA |
Answer» A POLYPEPTIDE of 24 amino acids will be FORMED |
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1042. |
Question :What would happen if a large volume of untreated sewage is discharged into a river ? |
Answer» SOLUTION : Due to increasing urbanisation, sewage is being produced in much larger QUANTITIES than ever before. However, the number of sewage treatment PLANTS has not increased enough to treat such large quantities. So, the untreated sewage is often DISCHARGED directly into rivers leading to their POLLUTION and increase in waterborne diseases. | |
1043. |
Question : What would Earth be like without the greenhouse effect? |
Answer» Solution :GREENHOUSE EFFECT is vital for the sustenance of life. Greenhouse gases like CO2, water vapour etc absorb some of the reflected sun.s radiation and radiate BACK it to the Earth surface, thus maintaining the Earth.s warm condition. Without this effect, life on Earth would be difficult or rather impossible for existence or become hostile to most LIVING organisms. | |
1044. |
Question : How many full turns of the Calvin cycle are required to make one molecule of glucose |
Answer» 5 |
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1046. |
Question : What would be the phenotypic ratio in F_(2) generation in a dihybrid cross if both the genes show lethality in homozygous dominant state - |
Answer» `2 : 2 : 2 : 2` |
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1047. |
Question : What would be the per cent growth or birth rate per indiviual per hour for the same population mentional in the previous question? |
Answer» 100 |
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1048. |
Question : What would be the percent growth or birth rate per individual per hour for the same population mentioned in the previous question (Question 10)? |
Answer» 100 |
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1049. |
Question : What would be the per cent growth or birth rate per individual per hour for the same population mentioned in the previous ques- tion (Question 10 )? |
Answer» 100 Number of Paramecium after 1 HOUR = 150 Birth rate = `("Number of NEW Paramecium")/("Initial number of Paramecium")xx100` `=(100)/(50)xx100=200%` |
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1050. |
Question : What would be the per cent growth or birth rate per individual per hour for the same population mentioned in the previous question ? |
Answer» 100 = `("FINAL population - Initial population ")/("Initial population") XX 100` `= (150 - 50)/(50) xx 100 = 200` |
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