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23451.

Question : A: In electrostatic precipitor.s electric charge is generated on the particles in the smoke and they are down towards electrodes and removed. R : About 100% particles present in smoke are removed by electrostatic precipitors.

Answer»

A. Both Assertion and Reason are TRUE and Reason is a CORRECT explanation of the Assertion,
B. Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
C. Assertion is true but Reason is false.
D. Assertion is false but Reason is true. . 

Answer :C
23452.

Question : A : Improvtedreproduction related programmes are called RCH. R : Government and non governmental organization spread reproductive awareness through medium of audio-visual and newspapers.

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A & R are CORRECT , R is explanation of A
A & R are correct , R is not the explanation of A
A is correct, R is incorrect
A is incorrect , R is correct

ANSWER :B
23453.

Question : [A]: If a population is of dominant genotype AA, then the frequency of dominant alleles in the gene pool will be relatively higher. [R]: The percentage of gametes bearin~ re- cessive (aa) allele will be correspondingly low

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If both A and R are true and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

Answer :A
23454.

Question : (a) Identify the selectable markersin the diagram of E. Coli vectior shown above . ( b) How is the coding squence of alpha- galactosidase consider a better markers than the ones identified by you in the diagram ? Explain.

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Solution :Selectable markers are TWO antibiotic- resistant genes.
`"TET^(R)` = Tetracycline - resisttant GENE and `AMP^(R)` = Ampicllin - resistant gene.
`beta` - galactosidas marker provides of
`beta`- galactosiidase when a chromogenic substrate is added in the PLATING medium.
23455.

Question : a. Identify the personalities shown above. b. Briefly give about their contributions to evolution.

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SOLUTION :a. A- Lamarck, B - Darwin
b. Lamarckism or Inheritance of ACQUIRED characters. Darwinism or Natural SELECTION.
23456.

Question : a) Identify the figure given below b) Redraw the structure as a replicating fork and label the parts (c) Write the source of energy for this replication and name the enzyme involved in this process. (d) Mention the differences in the synthesis of protein, based on the polarity of the two template strands.

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Solution :a) REPLICATION FORK
(b)
c) Deoxy nucleotide, triphosphate ACTS as a energy source for replication. DNA POLYMERASE is used for replication
d) mRNA CONTACTING information for protein synthesis will developed from DNA strand having polariy `5. rarr 3.`
23457.

Question : A hypothetical series of 20 multiple alleles is known for a certain locus. How many phenotypic classes are possible?

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20
l 20
240
40

Answer :A
23458.

Question :A hybrid where the cytoplasm of two parental cells are fused by retaining only one parental nucleus is called

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ASYMMETRIC SOMATIC hybrid
Cybrid
An interbred
Symmetric somatic hybrid

Answer :B
23459.

Question : A husband and wife came to an infertility clinic and consulted the doctor to know about why they are infertile. The doctor tested them and gave negative result saying that the sperm lacks sperm lysin secreted by acrosome. a. Give the name of the sperm lysin. b. Mention the function of sperm lysin.

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Solution :a. Antifertilizin
B. To dissolve the MEMBRANES SURROUNDED by OVUM during fertilization.
23460.

Question : A hybrid where the cytoplasm of two parent cells are fused by retaining only one parental nucleus is called

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ASYMMETRIC SOMATIC hybrid
Cybrid
An interbreed
Symmetric somatic hybrid

Answer :B
23461.

Question : A human protein which is being obtained from transgenic animals and is used to treat emphysema is

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ALPHA-lactalbumin
thyroxine
`alpha-`1- antitrypsin
insulin

Answer :C
23462.

Question :A human ovum is released on the 14th day of menstrual cycle. a. What happens to the ovum if it is fertilised by a sperm? b. Where does the fertilisation occur? c. What will happen to the Graafian follicles if the ovum is fertilised?

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Solution :a. Ovum becomes ZYGOTE
B. Anterior PART of the oviduct.
c. Forms CORPUS luteum and secretes progesterone
23463.

Question : A human male produces sperms with the genotypes AB, Ab, aB and ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this perons?

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AABB`XX`aaBB
AABB`xx`aabb
AaBb`xx`AaBb
AABB

Answer :A
23464.

Question : A human male is heterozygous for two autosomal genes A & B and homozygous dominant for 3^(rd) autosomal gene C. The individual is having sry gene (S) on its Y– chromosome. What will be the probability of sperms to carry abcS condition?

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`(1)/(4)`
`(1)/(8)`
0
`(1)/(16)`

ANSWER :C
23465.

Question : A human female with Turner's syndrome

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Is able to produce children with NORMAL husband
Has 45 CHROMOSOMES with XO
Has one additional X chromosome
Exhibits male characters

Answer :B
23466.

Question : A human female with Tunner,s syndrome :-

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has 45 chromosomes with XO
has ONE additional X-chromosome
exhibits male CHARACTERS
is able to produce children with NORMAL husband

Solution :has 45 chromosomes with XO
23467.

Question : A human female experiences two major changes, menarche and menopause during her life. Mention the significance of both the events.

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Solution :In human beings the first menstruation begins at PUBERTY (9 to 15) and is CALLED menarche. Menstruation cycle stops at the age of 50 years, it is called menopause. Menarch indicates the preparation of female reproduction SYSTEM for maturation and pregnancy.
It indicates capacity of ovaries which produce a mature ovum (female gamete) which can fertilizesperm cell and uterus is capable for growth and development of foetus.
Menopause indicates that it is not an age to conceive. The capability of providing healthy EGG cells is less at this age. The level of producing HORMONES by ovaries either gets decreased or stops and menstrual cycle is stopped. Uterus does not remain prepared for development of embryo for longer period.
23468.

Question : A human being suffering from Down syndrome shows trisomy of 21st chromosome. Mention the cause of this chromosomal abnormality.

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SOLUTION :Caused by the presence of an extra COPY of 21st CHROMOSOME DUE to NONDISJUNCTION of 21st autosomal chromosome during meiosis
23469.

Question : A hrmful condition which is also pitential saviour form a mosquito borne infectious disease

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THALASSEMIA
Sicke cell anaemia
Leukemia
Pernicious anamia

ANSWER :C
23470.

Question : (a) How many spermatozoa are formed from one secondary spermatocyte? (b) Where does the first cleavage division of zygote take place?

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Solution :(a) A primary spermatocytes completes the first meiotic division (REDUCTION division) LEADING to formation of two equal haploid cells called secondary spermatocytes (each has n=23 CHROMOSOMES). The secondary spermatocytes undergo the second meiotic division to produce four equal haploid spermatids.
(b) After 30 hours of fertilization when zygote PASSES from isthmus of OVIDUCT towards uterus, the mitotic division name cleavage starts and forms blastocysts.
23471.

Question : a) How has the development of bioreactor helped in biotechnology? b) Name the most commonly used bioreactor and describe its working.

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SOLUTION :a) N/A
B) Sarged stirred-tank BIOREACTOR.
23472.

Question : (a) How has the development of bioreactor helped in biotechnology? (b) Name the most commonly used bioreactor and describe its working

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Solution :(a) Bioreactores are used for processing large VOLUME of culture ofro obtaining products of intereset in sufficent quantities BIOREACTOR is a large vessel in which raw MATERIAL is bilogically converted in to specific product under optimal condition .A bnioreactor prodived the optimal CONDITIONS for acheiing the desired proddut by providing optimum growh conditons such as temperatures pH substrates salts, vitamins ,oxygen
(b)simple stirred tank bioreactor: A stirred tank ractor is usually CYLINDRICAL or with a curved base to facilatee the mi9xing of the reactor contents and the stirrer facitlitates evben mixing and oxygen availiability throughoutthe biroeactor .
23473.

Question :(a) How does a chromosomal disorder differ from a Mendelian disorder? (b ) Name any two chromosomal aberration associated disorders. (c) List the characteristics of the disorders mentioned above that help in their diagnosis.

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Solution :
(b) Two chromosomal aberration-associated disorders are Down's SYNDROME and Klinefelter's syndrome.
(c) (i) Down's syndrome : This is CAUSED by on EXTRA copy of chromosome 21. (trisomy 21). The affected individual is short with a round head. Tongue is furrowed and mouth is partially open. Palmar crease is present. Over all development is retarted.
(ii) Klinefelter's syndrome : It is caused by the absence of an X chromosome. XO. Such females are sterile with rudimentary ovaries. Secondary sexual characters are lacking.
23474.

Question : (a) How did Griffith explain the transformation of R strain (no virulent) bacteria into S strain (virulent)? (b) Explain how MacLeod, Mc Carty and Avery determined the biochemical nature of the molecule responsible for transforming R strain bacteria into S strain bacteria.

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SOLUTION :(a) and (B)
23475.

Question : A horse has a karyotype 64 chromosomes and a donkey har a karyotype of 62 chromosomes. The hybrid offspring of a horse-donkey cross is a mule, which has a 63 chromosomes. A mule is sterile because it cannot successfully

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COURT both mules
copulate with mules
form gametes
complete DEVELOPMENT of the zygote

Answer :C
23476.

Question : A hormone that induces fruit ripening is

Answer»

IAA
`GA_3`
ABA
Ethylene

Answer :D
23477.

Question : (a) Hooks and suckers are present (b) Absorb nutrients from the host directly through their body surface (c) Specialised cells called flame cells help in excretion and osmoregulation (d) Sexes are separate Which of the above given charater is not related with diagram given below?

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a
b
c
Digestion OCCURS in the INDIVIDUAL cells

Answer :D
23478.

Question : A homozygous tall pea plant is crossed with its homozygous recessive parent. Find out the genotypic and phenotypic ratio with the help of Punnet square method.

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Solution :
(Graphic REPRESENTATION UPTO `F_(1)`-generation-1 MARK)
(Graphic representation upto `F_(2)`-generation-1 mark)
(GENOTYPE ratio `-(1)/(2)` mark)
23479.

Question :A homozygous sweet pea plant with blue flowers (RR) and long pollen (R_0R_0)is crossed with a homozygous plant having red flowers (rr) and round pollen (r_0r_0) . The resultant F_1hybrid is test crossed. Which of the following genotype does not appear in its progeny?

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`Rrrr_0`
`RrRr_0`
`Rrr_0 r_0`
`rrR_0 r_0`

ANSWER :B
23480.

Question : A homozygous recessive with cd genes was crossed with dominant (+ +). If their hybrid is test crossed and the following result was obtained + + - 900 cd - 880 + d - 115 + c - 105 than what will be the distance between genes c and d.

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5.75 unit
11 unit
44 unit
90 unit

Answer :B
23481.

Question :A homozygous pea plant bearing axial flowers crossed with another pea plant terminal flower. Workout a cross to verify the genotype of F_(1)hybrid. What is yourconclusion?

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Solution :(1) if we REPRESENT the gene for axial FLOWER by a and gene for terminal flower by a then the GENOTYPE of homozygous pea plant havingaxial flower will be AA and that of terminal flower will be aa.
(2) In peaplants axial flower is a dominant trait while terminal floweris arecessive trait .

(4)The offsprings of `F_(1)`generation show axial flowersas gene gor axial FLOWERS (A) is dominantover the gene for terminal flowers (a)
(5)
23482.

Question : [A]: Homologous organs have similar struc- ture but different functions.[R]: It is believed that homologous structures were created for different purposes and their present function is secondarily achieved out of necessity

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If both A and R are TRUE and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

Answer :A
23483.

Question : [A]: Homology is the similarity between or- gans of same animal based on common ancestory.[R]: Analogy is seen in every organ system from fish to man

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If both A and R are TRUE and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

Answer :D
23484.

Question : [A]: Homologous organs are similar in basic structure and embryonic origin, but serve dif- ferent functions.[R]: Similarity in basic structure points to common ancestry whereas diversity in func- tion reflects adaptation to different modes of life.

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If both A and R are TRUE and R is the CORRECT explanation of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

ANSWER :A
23485.

Question : (a) Hiv and Hepatitis-B are STDs. Mention the two other ways by which they can be transmitted to a healthy person. (b) Why is early deterction of SRD essential ? Wha can it lead to otherwise ? Explain.

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Solution :(a) These DISEASES can be transmitted to a healthy person in the followingways :
1. Unsafe blood transfusion.
2. From infected to FOETUS.
(b) Early detertion of STD isessential for timelycure. Otherwise this can lead to Pelvic INFLAMMATORY Diseases (PID), aboprtions or even cancer of the reproductive tract.
23486.

Question :A hog breeder would use a backcross to

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determine if a particular hog is genotypically pure
eliminate CHANCES of congenital malformations
maintain a pure LINE of desirable traits
produce a bigger and healthier strain

Solution :A backcross consists of crossing a dominant PHENOTYPE with a pure homozygous recessive. In this MANNER the breeder determines if the phenotype is heterozygous or homozygous.
23487.

Question : [A]: Hill and Bendall proposed Z-scheme and suggested that photosystems operate in series.[R]: The light-dependent reactions require the participation of two light gathering units called PS-I and PS-I I.

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If both A and R are true and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

Answer :A
23488.

Question : A higher plant-cell, impregnated with cutin and suberin is placed in water, what would happen after 15 minutes?

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CELL SIZE will increase
cell-size will decrease
no CHANGE in the cell
cell WOULD be killed

Answer :C
23489.

Question : A high does of UT-B radiation causes inflammation of cornea called _______ cataract.

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ANSWER :B::D
23490.

Question : A high density ofelephant population in an area can result in

Answer»

lnterspecific COMPETITION
INTRASPECIFIC competition
MUTUALISM
Predation on one another

Answer :B
23491.

Question : A high density of tiger popdlation in an area un result in

Answer»

PREDATION
INTERSPECIFIC COMPETITION
lnlraspecific competition
Protocooperation

ANSWER :C
23492.

Question : A high density of elephant population in an area can result in

Answer»

INTRASPECIFIC COMPETITION 
INTERSPECIFIC competition 
Predation on ONE another
Mutualism 

Answer :A
23493.

Question : A : High concentration of atmospheric SO_(2) reduces primary productivity. R : SO_(2) converts the chlorophyll a into phaeophytin.

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If both Assertion & REASON are true and the reason is the correct explanation of the assertion, then MARK (1).
If both Assertion & Reason are ture but the reason is not the correct explanation of the assertion, then mark (2).
If Assertion is true statement but Reason is false, then mark (3).
If both Assertion and Reason are false statements, then mark (4).

Answer :A
23494.

Question : A high density of elephant population in an area can result in :

Answer»

INTRASPECIFIC competition
Interspecific competition
Predation competition
Mutualism

Answer :A
23495.

Question : A heterozygous pea plant producing intermediate strach grain size is selfed. What number of progeny will produce large strach grain size out of 4000 pea plants obtained ?

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3000
2000
1000
500

Answer :C
23496.

Question : [A]: Heterosis is superiority of F_1hybrid over its two genetically dissimilar parents. [R]: Heterosis can be measured in terms of size, yield and growth rate

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If both A and R are TRUE and R is the correct EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

Answer :B
23497.

Question : [A]: Hershey and Chase experiment showed that protein is the genetic material of T_2bac- teriophage. [R]: According to Hershey and Chase, RNA is the genetic material in T_2 bacteriophage.

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If both A and R are TRUE and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

Answer :D
23498.

Question : [A]: Heritable changes are also called muta- tions.[R]: Mutations are sudden change in chromo- somal DNA.

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If both A and R are TRUE and R is the CORRECT explanation of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

ANSWER :A
23499.

Question : A heavy metal pollutant released in automobile exhaust is __________.

Answer»


ANSWER :A::D
23500.

Question : A heavy DNA (N^(15)N^(15)) of Egtcoli si allowed to replicated in N^(14) medium for 80 minutes. What would be the proportions of light (N^(14)-N^(14)) and hybrid densities of DNA (N^(14)-N^(15)) molecules?

Answer»

`50:50`
`75:25%`
`87.5:12.5%`
all hybride

Answer :C