3593 + Interview Questions in BIOMOLECULES IN GENERAL AWARENESS Page 10 InterviewSolution

451.	Glucose isA. Cane sugarB. Grape sugarC. Malt sugarD. Triose sugar
Answer» Correct Answer - B

Discussion

452.	Which of the following sugars is laevorotatory ?A. FructoseB. GlucoseC. MaltoseD. Galactose
Answer» Correct Answer - A

Discussion

453.	Assertion : D-glucose is dextrorotatory whereas L-glucose is laevorotatory. Reason : D-compounds are always dextro and L-compounds are always laevorotatoryA. If both assertion and reason are true and reason is the correct explanation of assertion.B. If both assertion and reason are true but reason is not the correct explanation of assertion.C. If assertion is true but reason is false.D. If both assertion and reason are false.
Answer» Correct Answer - C D and L have no relation with the optical rotation. Carbohydrates having D configuration may be either dextrorotary or laevorotary e.g., D glucose is dextrorotatory while D-fructose is laevorotatory.

Discussion

454.	Which one of the following is laevorotatoryA. GlucoseB. SucroseC. FructoseD. None of these
Answer» Correct Answer - c

Discussion

455.	Which pair is different for reaction with Fehling solution ?A. Glucose, FructoseB. HCHO,`CH_(3)CHO`C. `CH_(2)COCH_(3),C_(6)H_(5)CHO`D. Glucose,Sucrose
Answer» Correct Answer - d

Discussion

456.	Which of the following monosaccharides is a pentose?A. GlucoseB. ArabinoseC. FructoseD. Galactose
Answer» Correct Answer - B Arabinose in an aldopentose. Glucose and galactose are aldohexoses while fructose is a ketohexose.

Discussion

457.	The correct statement about the following disaccharide is: A. Ring (I) is pyranose with `alpha`- glycosidic linkB. Ring (I) is furanose with `alpha`-glycosidic linkC. Ring (II) is furanose with `alpha`- glycosidic linkD. Ring (II)is pyranose with` beta`-glycosidic link
Answer» Correct Answer - a

Discussion

458.	Which of the following is a disaccharideA. LactoseB. StarchC. celluloseD. Glucose
Answer» Correct Answer - a

Discussion

459.	Which of the following disaccharide consists only of glucose unit?A. maltoseB. sucroseC. lactoseD. non of these
Answer» Correct Answer - a

Discussion

460.	The colour of the precipitate formed when a reducing sugar is heated with Fehling solution is:A. YellowB. RedC. BlueD. Green
Answer» Correct Answer - B

Discussion

461.	On heating glucose with Fehling solution. We get a precipitate whose colour is?A. YellowB. RedC. BlackD. White
Answer» Correct Answer - B

Discussion

462.	On heating glucose with Fehling solution. We get a precipitate whose colour is?A. yellowB. whiteC. redD. pink
Answer» Correct Answer - C

Discussion

463.	Carbohydrates are commonly defined as :A. Polycarbonyl compoundsB. Polycarboxylic acidC. Polyhydroxy carboxylic acid ketoneD.
Answer» Correct Answer - D

Discussion

464.	The colour of the precipitate formed when a reducing sugar is heated with Fehling solution is :A. brownB. redC. blueD. green
Answer» Correct Answer - b

Discussion

465.	The minimum number of carbon atoms that should be present in a carbonhydrate is :A. 2B. 3C. 4D. 6
Answer» Correct Answer - B

Discussion

466.	Osazone formation involves only 2 carbon atoms of glucose because ofA. chelationB. oxidationC. reductionD. hydrolysis
Answer» Correct Answer - B Osazone formation involves only 2 carbon atoms of glucose because of oxidation.

Discussion

467.	Number of possible isomers of glucose is :A. 16B. 14C. 10D. 8
Answer» Correct Answer - A

Discussion

468.	Osazone formation involves only 2 carbon atoms of glucose because ofA. oxidationB. chelationC. reductionD. hydrolysis
Answer» Correct Answer - b

Discussion

469.	Carbohydrates which differ in configurartion at the glycosidic carbon(i.e.,`C_(1)` in aldose and `C_(2)` in ketoses) are called:A. anomersB. epimersC. diastereomersD. enantiomers
Answer» Correct Answer - A

Discussion

470.	Osazone formation involves only 2 carbon atoms of glucose because ofA. oxidationB. reductionC. chelationD. hydrolysis
Answer» Correct Answer - C

Discussion

471.	A pair of diastereomers that differ only in the configuration about a single carbon atom are called:A. anomersB. epimersC. conformersD. enantiomers
Answer» Correct Answer - D

Discussion

472.	Read the following statement and find out the incorrect statement.A. Secondary metabolites are found in plant, fungal an miicrobial cells and we do not understand the role of these secondary metabolites in host organisms.B. Many secondary metabolites like rubber, drugs, spices, scents and pigments are useful to human welfare.C. Some secondary metabolites have ecological significance.D. Flavonoids, antibiotics, coloured pigments and lecithin are secondary metabolites.
Answer» Correct Answer - D (D) Secondary metabolites are found in plant, fungal and microbial cells and we do not understand the role of these secondary metabolites in host organisms. Many secondary metabolites like rubber, drungs, spices, scents and pigments are useful to human welfare. Some secondary metabolites have ecological significance. Favonoids, antibiotic and coloured pigments are secondary metabolites. Lecithin is primary metabolite.

Discussion

473.	Which of the following features(s) is common to all those compounds found in acid soluble pool or filtrate ?A. The are called macromolecules or biomacromolecules.B. The molecular weight is more than ten thousands Dalton or above.C. They have molecular weight ranging from 18 to around 800 Da approximately.D. Both A and B
Answer» Correct Answer - C (C) All those compounds found in acids soluble pool or filtrate have molecular weight ranging from 18 to around 800 Da approximately and called micromolecules.

Discussion

474.	Identify the given structural formulae and select the correct option. A. `{:(" A",," B"),("Adenine",,"Uracil"):}`B. `{:(" A",," B"),("Guanine",,"Thymine"):}`C. `{:(" A",," B"),("Adenine",,"Guanine"):}`D. `{:(" A",," B"),("Cytosine",,"Thymine"):}`
Answer» Correct Answer - A Nitrogen bases are heterocyclic compounds. They are of two types, substituted purines and substituted pyrimidines. Purines are larger-sized nitrogen containing biomolecules. They have `9-`membered double rings. A purine has imidazole ring joined to pyrimidine ring at `4` and `5` positions. It has nitrogens at 1, 3, 7 and 9 positions. There are two types of purines- adenine (A) and guanine (G). Pyrimidines are `6-` membered rings. A pyrimidine ring has nitrogen at `1` and `3` positions. Pyrimidine bases are of three types-cytosine (C), thymine (T) and uracil (U).

Discussion

475.	The three structural formulae A, B and C are given here. Identify them and select the correct option. A. `{:(" "A," "B," "C),((a)"Adenine","Adenosine","Adenylic acid"),("`(N-base)","(Nucleotide)","(Nucleoside)"):}`B. `{:(" "A," "B," "C),((a)"Adenine","Adenosine","Adenylic acid"),("`(N-base)","(Nucleotide)","(Nucleotide)"):}`C. `{:(" "A," "B," "C),((a)"Adenosine","Adenylic acid","Adenine"),("`(Nucleoside)","(Nucleotide)","(N-basie)"):}`D. `{:(" "A," "B," "C),((a)"Adenosine","Adenylic acid","Deoxyadenylic acid"),("`(Nucleoside)","(Nucleotide)",):}`
Answer» Correct Answer - B

Discussion

476.	How many nucleotides are present in one turn of DNA helixA. 4 pairsB. 8 pairsC. 10 pairsD. 9 pairs
Answer» Correct Answer - C

Discussion

477.	ATP isA. Adenosine D-ribose three phosphateB. Adenosine L-ribose three phosphateC. Adenine D-ribose three phosphateD. Adenine L-ribose three phosphate
Answer» Correct Answer - C

Discussion

478.	Which of the following is correct pair of pyrimidine basesA. Adenine and ThymineB. Adenine and GuanineC. Thymine and CytosineD. Guanine and Cytosine
Answer» Correct Answer - C

Discussion

479.	The four elements that make up 99% of all elements found in a living system areA. CHOSB. CHOPC. CHOND. CNOP
Answer» Correct Answer - C Carbon, hydrogen, oxygen and nitrogen are called as big four of the cell. C is 18%, O is 65%, H is 10% and N is 2.5%. These are principal non-metal elements and form 95% of total cellular materials.

Discussion

480.	Study the given statements and select the correct option. Carbohydrates, proteins, nucleic acids and lipids are primary metabolites. Alkaloids, floavonoids, rubber, etc., are secondary metabolites. Linoleic, linolenic and palmitic acids are the three essential fatty acids.A. Statements (i) and (ii) are correct.B. Statements (i) and (iii) are incorrect.C. Statements (i) and (iii) are correct.D. Only statement (ii) is incorrect.
Answer» Correct Answer - A Plants produce various types of chemicals. Some of the organic compounds like carbohydrates, fats, proteins nucleic acids, chlorophylls, etc., are required for their basic metabolic processes and are found throughout the plant kingdom. Such organic compounds are called primary metabolites or biomolecules. These are produced in large quantities and can be easily extracted from the plants. Many pants, fungi and microbes of certain genera and families synthesise a number of organic compounds which are not involved in primary metabolism (photosynthesis, respiration, protein and liquid metabolism) and seems to have no direct role in growth and development of plants. such compounds are called secondary metabolites. These compounds are accessory rather than central to the functioning of the plants in which they are found. Primary metabolites have identifiable functions and play important roles in normal physiological processes. However, the function of all the secondary metabolites in host organism are yet clearly understood.

Discussion

481.	Find iso-electric point of given amino acid `CH_(3)-underset(o+)underset(NH_(3))underset(\|)(CH)-CO_(2)H " " pK_(a) = 2.2`A. `3.3`B. `5.9`C. `9.6`D. `11.8`
Answer» Correct Answer - B `I.P. = (pK_(a_(1))+pK_(a_(2)))/(2)` so `((14.0 - 4.4)+2.2)/(2) = (1.18)/(2) = 5.9`

Discussion

482.	The iso-electric point of the given amino acid is,
Answer» Correct Answer - 3

Discussion

483.	Which of the following treatment will convert amylose directly into glucose?A. heating with dil. `H_(2)SO_(4)`B. fermentation by distaseC. fermentation by zymaseD. heating with dil. NaOH.
Answer» Correct Answer - A Polysaccharides on hydrolysis with dil. Mineral acid give mono saccharides.

Discussion

484.	Which compound is not a lipid?A. lecithinB. cysteineC. cerebrosideD. cephalin
Answer» Correct Answer - B Cysteine is an `alpha`-amino acid.

Discussion

485.	A few drops of sap were collected by cutting across a plant stem by a suitable method. The sap was tested chemically. Which one of the following test results indicates that it is phloem sap ?A. Low refractive indexB. Absence of sugarC. AcidicD. Alkaline
Answer» Correct Answer - D

Discussion

486.	Give two similarities and two differences between inorganic catalysts and biocatalysts.
Answer» Both are neede in very small quantities and both do not initiate but accelerate chemical reactions. Inorganic catalysts are mineral ions or simple molecules and catalyse inorganic reactions. Biocatalysts are complex proteins and catalyse biological reactions.

Discussion

487.	A substance which can act both as an analgesic and antipyretic isA. quinineB. AspirinC. PenicillinD. insulin
Answer» Correct Answer - B Aspirin can act both as an antipyretic as well as analgesic

Discussion

488.	Name the inorganic compounds found in cells.
Answer» Water, minerals and gases.

Discussion

489.	Describe the steps of catalytic cycle of an enzyme action. OR Enlist four steps involved in catalytic action of an enzyme.
Answer» Steps of catalytic cycle of an enzyme action are: (i) The substrate binds to the active site of the enzyme. (ii) This binding of the substrate induces the enzymes to alter its shape and fit more closely around the substrate. (iii) The active site of the enzyme, now is in close proximity of the substrate breaks the chemical bonds of the substrate and an enzyme-product complex is formed. (iv) The enzyme releases the products of the reaction and the free enzyme is ready to take up another molecule of the substrate.

489.

Describe the steps of catalytic cycle of an enzyme action. OR Enlist four steps involved in catalytic action of an enzyme.

Answer»

Steps of catalytic cycle of an enzyme action are:

(i) The substrate binds to the active site of the enzyme.

(ii) This binding of the substrate induces the enzymes to alter its shape and fit more closely around the substrate.

(iii) The active site of the enzyme, now is in close proximity of the substrate breaks the chemical bonds of the substrate and an enzyme-product complex is formed.

(iv) The enzyme releases the products of the reaction and the free enzyme is ready to take up another molecule of the substrate.

Discussion

490.	Enzymes, vitamins and hormones can be classified into a single category of biological chemicals, because all of theseA. are exclusively synthesized in the body of a living organism as at presentB. help in regulating metabolismC. enhance oxidative metabolismD. are conjugated proteins
Answer» Correct Answer - B

Discussion

491.	Enzymes, vitamins and hormones can be classified into a single category of biological chemicals, because all of theseA. help in regulating metabolismB. are exclusively synthesized in the body of a living organism as at presentC. are conjugated proteinsD. enhance oxidative metabolism
Answer» Correct Answer - A

Discussion

492.	Enzymes, vitamins and hormones can be classified into a single category of biological chemicals, because all of theseA. Enhance oxidative metabolismB. Are conjugated proteinsC. Are exclusively synthesized in the body of a living organism as at presentD. Help in regulating metabolism
Answer» Correct Answer - D

Discussion

493.	How many hydrogen bonds are present between pair of thymine and adenine in DNA?A. 1-hydrogen bondB. 2-hydrogen bondC. 3-hydrogen bondD. No bonds occur
Answer» Correct Answer - B The two hydrogen bonds are present between pair of thymine and adenine while three hydrogen bonds are present between cytosine and guanine.

Discussion

494.	Give scientific reasons :On complete hydrolysis DNA gives equimolar quantities of adenine and thymine.
Answer» On complete hydrolysis DNA yields 2-deoxyD-ribose, adenine, thymine, guanine, cystosine and phosphoric acid. Since adenine always forms two hydrogen bonds with thymine, the hydrolysis of DNA gives equimolar quantities of adenine and thymine.

Discussion

495.	Invert sugar is a mixture of equal amount of …………(a) lactose + maltose (b) diastose + galactose (c) glucose + fructose (d) starch + cellulose
Answer» (c) glucose + fructose

Discussion

496.	Assertion(A): Sucrose is called invert sugar. Reason (R): During hydrolysis of sucrose, the optical rotation of the reaction mixture changes from dextro to levo.(a) Both A and R are correct and R is the correct explanation of A.(b) Both A and R are correct but R is not the correct explanation of A.(c) A is correct but R is wrong.(d) A is wrong but R is correct.
Answer» (a) Both A and R are correct and R is the correct explanation of A.

Discussion

497.	Glycogen is a branched chain polymer of α-D-glucose units in which chain is formed by C1—C4 glycosidic linkage whereas branching occurs by the formation of C1-C6 glycosidic linkage. Structure of glycogen is similar to __________. (i) Amylose (ii) Amylopectin (iii) Cellulose (iv) Glucose
Answer» (ii) Amylopectin

Discussion

498.	Give scientific reasons :The disaccharide sucrose gives negative Tollens test while the disaccharide maltose gives positive Tollens test.
Answer» (1) In disaccharide sucrose, the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a nonreducing sugar. As there is no free aldehyde group, it does not reduce Tollen’s reagent to metallic silver. Hence, sucrose gives negative Tollen’s test. (2) While the disaccharide maltose is a reducing sugar because a free aldehyde group can be produced at C of second sugar molecule. It is a reducing sugar. It reduces Tollen’s reagent to shining silver mirror. Hence, Maltose gives positive Tollen’s test.

498.

Give scientific reasons :The disaccharide sucrose gives negative Tollens test while the disaccharide maltose gives positive Tollens test.

Answer»

(1) In disaccharide sucrose, the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a nonreducing sugar. As there is no free aldehyde group, it does not reduce Tollen’s reagent to metallic silver. Hence, sucrose gives negative Tollen’s test.

(2) While the disaccharide maltose is a reducing sugar because a free aldehyde group can be produced at C of second sugar molecule. It is a reducing sugar. It reduces Tollen’s reagent to shining silver mirror. Hence, Maltose gives positive Tollen’s test.

Discussion

499.	Three structures are given below in which two glucose units are linked. Which of these linkages between glucose units are between `C_(1)` and `C_(4)` and which linkages are between `C_(1)` and `C_(6)`? A. (A) is between C-1 and C-4 , (B) and (C) are between C-1 and C-6B. (A) and (B) are between C-1 and C-4 , (C) is between C-1 and C-6C. (A) and (C) are between C-1 and C-4, (B) is between C-1 and C-6D. (A) and (C) are between C-1 and C-6, (B) is between C-1 nad C-4.
Answer» Correct Answer - C (A) and (C) are between C-1 and C-4, (B) is between C-1 and C-6.

Discussion

500.	Assertion(A): A disaccharide lactose act as reducing sugar.Reason (R): In lactose, β – D galactose and β – D glucose are linked by β – 1, 4 – glycosidic bond in which aldehyde group is not involved.(a) A is correct but R is wrong. (b) Both A and R are correct but R is not the correct explanation of A. (c) Both A and R are correct and R is the correct explanation of A. (d) A is wrong but R is correct.
Answer» (c) Both A and R are correct and R is the correct explanation of A.

Discussion

Explore topic-wise InterviewSolutions in .

Glucose isA. Cane sugarB. Grape sugarC. Malt sugarD. Triose sugar

Which of the following sugars is laevorotatory ?A. FructoseB. GlucoseC. MaltoseD. Galactose

Which one of the following is laevorotatoryA. GlucoseB. SucroseC. FructoseD. None of these

Which pair is different for reaction with Fehling solution ?A. Glucose, FructoseB. HCHO,`CH_(3)CHO`C. `CH_(2)COCH_(3),C_(6)H_(5)CHO`D. Glucose,Sucrose

Which of the following monosaccharides is a pentose?A. GlucoseB. ArabinoseC. FructoseD. Galactose

The correct statement about the following disaccharide is: A. Ring (I) is pyranose with `alpha`- glycosidic linkB. Ring (I) is furanose with `alpha`-glycosidic linkC. Ring (II) is furanose with `alpha`- glycosidic linkD. Ring (II)is pyranose with` beta`-glycosidic link

Which of the following is a disaccharideA. LactoseB. StarchC. celluloseD. Glucose

Which of the following disaccharide consists only of glucose unit?A. maltoseB. sucroseC. lactoseD. non of these

The colour of the precipitate formed when a reducing sugar is heated with Fehling solution is:A. YellowB. RedC. BlueD. Green

On heating glucose with Fehling solution. We get a precipitate whose colour is?A. YellowB. RedC. BlackD. White

On heating glucose with Fehling solution. We get a precipitate whose colour is?A. yellowB. whiteC. redD. pink

Carbohydrates are commonly defined as :A. Polycarbonyl compoundsB. Polycarboxylic acidC. Polyhydroxy carboxylic acid ketoneD.

The colour of the precipitate formed when a reducing sugar is heated with Fehling solution is :A. brownB. redC. blueD. green

The minimum number of carbon atoms that should be present in a carbonhydrate is :A. 2B. 3C. 4D. 6

Osazone formation involves only 2 carbon atoms of glucose because ofA. chelationB. oxidationC. reductionD. hydrolysis

Number of possible isomers of glucose is :A. 16B. 14C. 10D. 8

Osazone formation involves only 2 carbon atoms of glucose because ofA. oxidationB. chelationC. reductionD. hydrolysis

Carbohydrates which differ in configurartion at the glycosidic carbon(i.e.,`C_(1)` in aldose and `C_(2)` in ketoses) are called:A. anomersB. epimersC. diastereomersD. enantiomers

Osazone formation involves only 2 carbon atoms of glucose because ofA. oxidationB. reductionC. chelationD. hydrolysis

A pair of diastereomers that differ only in the configuration about a single carbon atom are called:A. anomersB. epimersC. conformersD. enantiomers

Identify the given structural formulae and select the correct option. A. `{:(" A",," B"),("Adenine",,"Uracil"):}`B. `{:(" A",," B"),("Guanine",,"Thymine"):}`C. `{:(" A",," B"),("Adenine",,"Guanine"):}`D. `{:(" A",," B"),("Cytosine",,"Thymine"):}`

How many nucleotides are present in one turn of DNA helixA. 4 pairsB. 8 pairsC. 10 pairsD. 9 pairs

ATP isA. Adenosine D-ribose three phosphateB. Adenosine L-ribose three phosphateC. Adenine D-ribose three phosphateD. Adenine L-ribose three phosphate

Which of the following is correct pair of pyrimidine basesA. Adenine and ThymineB. Adenine and GuanineC. Thymine and CytosineD. Guanine and Cytosine

The four elements that make up 99% of all elements found in a living system areA. CHOSB. CHOPC. CHOND. CNOP

Find iso-electric point of given amino acid `CH_(3)-underset(o+)underset(NH_(3))underset(|)(CH)-CO_(2)H " " pK_(a) = 2.2`A. `3.3`B. `5.9`C. `9.6`D. `11.8`

The iso-electric point of the given amino acid is,

Which of the following treatment will convert amylose directly into glucose?A. heating with dil. `H_(2)SO_(4)`B. fermentation by distaseC. fermentation by zymaseD. heating with dil. NaOH.

Which compound is not a lipid?A. lecithinB. cysteineC. cerebrosideD. cephalin

A few drops of sap were collected by cutting across a plant stem by a suitable method. The sap was tested chemically. Which one of the following test results indicates that it is phloem sap ?A. Low refractive indexB. Absence of sugarC. AcidicD. Alkaline

Give two similarities and two differences between inorganic catalysts and biocatalysts.

A substance which can act both as an analgesic and antipyretic isA. quinineB. AspirinC. PenicillinD. insulin

Name the inorganic compounds found in cells.

Describe the steps of catalytic cycle of an enzyme action. OR Enlist four steps involved in catalytic action of an enzyme.

Enzymes, vitamins and hormones can be classified into a single category of biological chemicals, because all of theseA. are exclusively synthesized in the body of a living organism as at presentB. help in regulating metabolismC. enhance oxidative metabolismD. are conjugated proteins

Enzymes, vitamins and hormones can be classified into a single category of biological chemicals, because all of theseA. help in regulating metabolismB. are exclusively synthesized in the body of a living organism as at presentC. are conjugated proteinsD. enhance oxidative metabolism

Enzymes, vitamins and hormones can be classified into a single category of biological chemicals, because all of theseA. Enhance oxidative metabolismB. Are conjugated proteinsC. Are exclusively synthesized in the body of a living organism as at presentD. Help in regulating metabolism

How many hydrogen bonds are present between pair of thymine and adenine in DNA?A. 1-hydrogen bondB. 2-hydrogen bondC. 3-hydrogen bondD. No bonds occur

Give scientific reasons :On complete hydrolysis DNA gives equimolar quantities of adenine and thymine.

Invert sugar is a mixture of equal amount of …………(a) lactose + maltose (b) diastose + galactose (c) glucose + fructose (d) starch + cellulose

Glycogen is a branched chain polymer of α-D-glucose units in which chain is formed by C1—C4 glycosidic linkage whereas branching occurs by the formation of C1-C6 glycosidic linkage. Structure of glycogen is similar to __________. (i) Amylose (ii) Amylopectin (iii) Cellulose (iv) Glucose

Give scientific reasons :The disaccharide sucrose gives negative Tollens test while the disaccharide maltose gives positive Tollens test.