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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 501. |
Structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.(i) ‘a’ carbon of glucose and ‘a’ carbon of fructose.(ii) ‘a’ carbon of glucose and ‘e’ carbon of fructose.(iii) ‘a’ carbon of glucose and ‘b’ carbon of fructose.(iv) ‘f ’ carbon of glucose and ‘f ’ carbon of fructose. |
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Answer» (iii) ‘a’ carbon of glucose and ‘b’ carbon of fructose. |
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| 502. |
Prove that sucrose is 1. invert sugar 2. non – reducing sugar. |
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Answer» 1. Sucrose is an invert sugar: Sucrose (+66.6°) and glucose (+52.5°) are dextro rotatory compounds while fructose is levo rotatory (- 92.4°). During hydrolysis of sucrose, the optical rotation of the reaction mixture changes from dextro to levo. Hence sucrose is also called invert sugar. 2. In sucrose, C1 of α – D glucose is joined to C2 of α – D fructose. The glycosidic bond thus formed is called α – 1, 2 – glycosidic bond. Since both the carbonyl carbons (reducing groups) are involved in the glycosidic bonding, sucrose is a non – reducing sugar. |
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| 503. |
Find the odd one out and give the reasons.Mannose, sucrose, lactose, maltose, diastose |
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Answer» Mannose, It is a monosaccharide whereas otheres are disaccharide. |
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| 504. |
Three structures are given below in which two glucose units are linked. Which of these linkages between glucose units are between C1 and C4 and which linkages are between C1 and C6?(i) (A) is between C1 and C4, (B) and (C) are between C1 and C6(ii) (A) and (B) are between C1 and C4, (C) is between C1 and C6(iii) (A) and (C) are between C1 and C4, (B) is between C1 and C6(iv) (A) and (C) are between C1 and C6, (B) is between C1 and C4 |
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Answer» (iii) (A) and (C) are between C1 and C4, (B) is between C1 and C6 |
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| 505. |
Assertion(A): Maltose, a disaccharide acts as a reducing sugar.Reason (R): Maltose consists of two molecules of α – D glucose with linked by α, 1, 4 – glycosidic bond and one glucose has the carbonyl group.(a) Both A and R are correct and R is the correct explanation of A.(b) Both A and R are correct but R is not the correct explanation of A. (c) A is correct but R is wrong. (d) A is wrong but R is correct. |
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Answer» (a) Both A and R are correct and R is the correct explanation of A. |
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| 506. |
Sucrose and maltose are disaccharides but sucrose Is a non reducing sugar while maltose Is a reducing sugar. |
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Answer» 1. Sucrose is a disaccharide that composed of α – D glucose and β – D fructose. In sucrose Cl of α – D glucose is joined to C2 of D – fructose. The glycosidic bond thus formed is called α – 1, 2- glycosidic bond. Since both the carbonyl carbons (reducing carbons) are involved in the glycosidic bonding, sucrose is a non-reducing sugar. 2. But maltose contains two molecules of x – D glucose units that are linked by an α – 1, 4 – glycosidic bond. Anomeric carbon of one unit and C – 4 of other unit are connected together. Smce one of the glucose bas the carbonyl group intact it acts as reducing sugar. |
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| 507. |
Assertion: Enzymes are globular proteins. Reason: Enzymes are regenerated during reactions.A. Both A and R are true and R is the correct explanation of AB. both A and R true but R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true |
| Answer» Correct Answer - A | |
| 508. |
Which of the following is not a reducing sugar?(a) Glucose(b) Fructose(c) Sucrose(d) Maltose |
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Answer» The answer is (c) Sucrose |
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| 509. |
Assertion:Maltose is a reducing sugar , one molecule of which gives two molecules of d-glucose on hydrolysis. Reason: Maltose has a 1,4 `beta`-glycosidic linkage.A. Both A and R are true and R is the correct explanation of AB. both A and R true but R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true |
| Answer» Correct Answer - C | |
| 510. |
Which of the following statements is/are correct? I. Glucose is reducing sugar II. Sucrose is reducing sugar III. Maltose is non reducing sugar IV. Lactose is reducing sugarA. I and II onlyB. I and III onlyC. I and IV onlyD. All |
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Answer» Correct Answer - C |
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| 511. |
In which of the following case, the forms of amino acid and pH is (are) correctly matched ?A. `{:("Alanine : pH=3 , "H_(3) overset(+)(N)-C-COO^(-)),(" |"),(" "CH_(3)):}`B. `{:("Leucine : pH=10 , "H_(2)N-"C H"-COO^(-)),(" |"),(" "CH_(2)-"C H"-CH_(3)),(" |"),(" "CH_(3)):}`C. `{:("Asparic acid : pH=9 , "H_(2)N-"C H"-COO^(-)),(" |"),(" "CH_(2)-COO^(-)):}`D. `{:("Lysine : pH=3 , "H_(3)overset(+)(N)-CH-COOH),(" |"),(" "CH_(2)CH_(2)CH_(2)CH_(2) overset(+)(N)H_(3)):}` |
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Answer» Correct Answer - B::C::D |
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| 512. |
Assertion`:` In the iodometric titration, starch is used as an indicator. Reason `:` Starch is a polysaccharide.A. If both the assertion and reacons are true and reason is a true explanation of the assertion.B. If both the assertion and reasons are true but the reason is not the correct explanation of assertion.C. If the assertion is ture but reason is false.D. If assertion is false but reasion is true. |
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Answer» Correct Answer - B Starch `(C_(6)H_(10)O_(5))_(n)` is a polysaccharide. It consists of two fractions `-` one is known as `alpha-`amylose or amylopectin. In iodimetric and iodometric titrations, starch solution is used as an indicator . It gives blue or violet colour with free iodine. At the end point, the blue or violet colour disappears when iodine is completely changed to iodide. |
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| 513. |
In which of the following case, the forms of amino acid and pH is (are) correctly matched ?A. `{:("Alanine : pH=3 , "H_(3) overset(+)(N)-C-COO^(-)),(" |"),(" "CH_(3)):}`B. `{:("Leucine : pH=10 , "H_(2)N-"C H"-COO^(-)),(" |"),(" "CH_(2)-"C H"-CH_(3)),(" |"),(" "CH_(3)):}`C. `{:("Asparic acid : pH=9 , "H_(2)N-"C H"-COO^(-)),(" |"),(" "CH_(2)-COO^(-)):}`D. `{:("Lysine : pH=3 , "H_(3)overset(+)(N)-CH-COOH),(" |"),(" "CH_(2)CH_(2)CH_(2)CH_(2) overset(+)(N)H_(3)):}` |
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Answer» Correct Answer - B::C::D |
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| 514. |
The substituents `R_(1)` and `R_(2)` for nine peptides are listed in the table given below. How many of these peptides are positively charged at `pH=7.0` ? A. 6B. 4C. 5D. none of these |
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Answer» Correct Answer - B The Amino acids at its isoelectric point is completely in zwitter ion form. Amino acids with additional acid group have isoelectric pH less than 7. increasing pH above isoelectric point makse them anionic. The amino acids with additional basic group have their isoelectric pH greater than 7 and decreasing pH below isoelectric point ( by adding acid solution ) makes them cationic . Thus four peptides with following `R_(1)` and `R_(2)` are basic and will remain protonated (catanioc ) at pH =7 `|:("Peptide",|,R_(1),|"R_(2)),(IV,CH_(2)CONH_(2),(CH_(2))_(4)NH_(2),),(VI,(CH_(2))_(4)NH_(2),(CH_(2))_(4)NH_(2),),(VIII,CH_(2)OH,(CH_(2))_(4)NH_(2),),(IX,(CH_(2))_(4)NH_(2),CH_(3),):|` |
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| 515. |
Peptides are formed by the joining of amino acids through amide linage. Which of the following statement is not true in this respect?A. Amide groups do not contribute in the hydrogen bonding interactionsB. `p pi` resonance stabilizes the amide linkagesC. Amide groups are more resistant to hydrolysis than similar ester groupsD. Stable conformations of peptides are restricted to those having planar amide groups |
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Answer» Correct Answer - A Hydrogen bonding plays an important role in the secondary structure of proteins. These are formed between amide groups of two chains. |
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| 516. |
Starch is a polymer ofA. fructoseB. glucoseC. lactoseD. Ribose |
| Answer» Correct Answer - B | |
| 517. |
some statement are given below glucose is penta hydroxy aldehyde fructose is ketohexose contain four chiral center polymer of glucose is starch Fatty acids are aliphatic saturated higher monocarboxylic acids. Among the above, correct statements (s) is/areA. only 1 and 3B. only 4C. only 1,3 and 4D. only 1 and 4 |
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Answer» Correct Answer - C |
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| 518. |
Starch is polymer ofA. `alpha`-glucoseB. `beta`-glucoseC. fructoseD. mannose |
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Answer» Correct Answer - A |
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| 519. |
Starch is polymer ofA. `alpha-D-"Glucose"`B. `beta-D-"Glucose"`C. `alpha-D-"Glucose"` and `beta-D-"Glucose"`D. `alpha-D-"Fructose"` |
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Answer» Correct Answer - A Starch is polymer of `alpha-D`-glucose. |
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| 520. |
Assertion : Starch is the storage polysaccharide in plants . Reason : Starch is a polymer of `beta`- glucose .A. If both assertion and Reason are true and the Reason is the correct explanation of the assertion .B. If both Assertion and Reason ate true , but the reason is not the correct explanation of the assertion .C. If Assertion is true , but Reason is falseD. if both Assertion and Reason are false. |
| Answer» Correct Answer - B | |
| 521. |
The substituents `R_(1) and R_(2)` for nine peptides are listed in the table given below. How many of these peptides are positively charged at pH = 7.0 ? `{:(H_(3)N-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-COO),(" | | | |"),(" "H" "R_(1)" "R_(2)" H"):}` `{:("Peptide","R"_(1),"R"_(2)),("I","H","H"),("II","H","CH"_(3)),("III","CH"_(2)"COOH","H"),("IV","CH"_(2)"CONH"_(2),("CH"_(2))_(4)"NH"_(2)),("VI",("CH"_(2))_(4)"NH"_(2),("CH"_(2))_(4)"NH"_(2)),("VII","CH"_(2)"COOH","CH"_(2)"CONH"_(2)),("VIII","CH"_(2)"OH",("CH"_(2))_(4)"NH"_(2)),("IX",("CH"_(2))_(4)"NH"_(2),"CH"_(3)):}` |
| Answer» Correct Answer - 4 | |
| 522. |
Peptides are amino acid polymer in which the individual amino acid units are calledA. monomerB. residueC. epimerD. amide |
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Answer» Correct Answer - B |
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| 523. |
The substituents `R_(1)` and `R_(2)` for nine peptides are listed in the table given below. How many of these peptides are positively charged at `pH=7.0` ? |
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Answer» Correct Answer - `4` |
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| 524. |
Struchures of some common polymers are given. Which one is not correctly represented?A. Teflon `(CF_(2)-CF_(2)-)_(n)`B. Neoprene `(.^(CH_(2)-underset(underset(Cl)(|))(C)=CH-CH_(2)-CH_(2)-))_(n)`C. D. Nylon-66 `[-NH(CH_(2))_(6)NHCO(CH_(2))_(4)-CO-]_(n)` |
| Answer» Correct Answer - A::C::D | |
| 525. |
Starch is a polymer ofA. GlucoseB. FructoseC. MaltoseD. Sucrose |
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Answer» Correct Answer - A (A) Starch is polymer of glucose (`alpha`-D-Glucose). |
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| 526. |
Basic amino acid is :(a) Lysine (b) Glycine (c) Cystine (d) Alanine |
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Answer» Option : (a) Lysine |
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| 527. |
The correct statements about peptides areA. A dipeptide has one peptide link between two amino acids.B. By convention N-Terminus is kept at left and C-terminus at right in the structure of a peptideC. If only one amino group and one carboxylic acid, group are available for reaction, then only one dipeptide can formsD. A polypeptide with more than hundred amino acid reciduces (mol. Mass `gt 10,000`) is called a protein. |
| Answer» Correct Answer - A::B::C::D | |
| 528. |
Assterion : Each enzyme has a substrate binding site in its molecule which forms highly reactive enzyme-substrate complex. Reason : The enzyme-substrate complex is long-lived and dissociates into its product and unchanged enzyme. |
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Answer» Correct Answer - C A particular substrate molecule is acted upon by a particular enzyme . After coming with the active site (a pocket into which the substrate fits) of the enzyme, the substrate molecules or reactants form a complex called enzyme-substrate complex. The enzyme substrate complex is short lived. In the complexed state, the molecules of the substrate undergo chemical change. The products remain attached to the enzyme for some time so that an enzyme-product complex is also formed. However, the products are soon released and the freed enzyme is able to bind more substrate molecules. |
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| 529. |
State the Beadle and Tatum theory. |
| Answer» One gene-one enzyme theory. | |
| 530. |
Which of the following is a basic amino acid?(a) Glycine(b) Aspartic acid(c) Lysine(d) Glutamine |
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Answer» The answer is (c) Lysine |
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| 531. |
Assertion : Unsaturated fats are more reactive as compared with the saturated fats. Reason : Unsaturated fats have only single bonds in their structure.A. If both assertion and reason are true and the reason is the correct explanation of the assertionB. If both assertion and reason are true and the reason is not the correct explanation of the assertionC. If assertion is true but reason is falseD. If both assertion and reason are false |
| Answer» Correct Answer - C | |
| 532. |
D-Mannose differs from D-glucose in its stereochemistry at `C-2`. The pyranose form of D-Mannose is.A. B. C. D. |
| Answer» Correct Answer - A::C | |
| 533. |
Formation of peptide and glycosidic bonds involvesA. EsterificationB. HydrationC. DehydrationD. Acidification |
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Answer» Correct Answer - C (C) Formation of peptide and glycosidic bonds involves dehydration |
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| 534. |
Assertion : Human diet should compulsorily contain glycine, serine and tyrosine. Reason: Essential amino acids cannot be synthesized in the human body.A. If both assertion and reason are true and the reason is the correct explanation of the assertionB. If both assertion and reason are true and the reason is not the correct explanation of the assertionC. If assertion is true but reason is falseD. If both assertion and reason are false |
| Answer» Correct Answer - D | |
| 535. |
Glucose and mannose are :A. epimersB. anomersC. ketohexosesD. disaccharides |
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Answer» Correct Answer - A Glucose and mannose are epimers because they both differ in configuration at `C_2` position. The isomers which differ at `C_2` position are known as epimers of each other. |
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| 536. |
A tripeptide has …….. Peptide bonds.A. threeB. twoC. fourD. one |
| Answer» Correct Answer - b | |
| 537. |
Assertion : Hydrolases are the enzymes which catalyse the hydrolysis of ester, ether, peptide, glycosidic, C-C or P-N etc., bonds. Reason : Lyases are the enzymes catalysing the linking together of 2 compounds like joining of C-O, C-N, P-O etc. bonds. |
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Answer» Correct Answer - C There are various types of enzyme depending on their action. Hydrolases catalyse the hydrolysis of ester, ether, peptide, glycosidic, `C-C`, C-halide, P-N bonds etc., which are formed by dehydration and condensation. Hydrolases break up large molecules into smaller ones with the help of hydrogen and hydroxyl groups of water molecules. The phenomenon is called hydrolysis. Lyases are the enzymes which cause cleavage, removal of groups without hydrolysis, addition of groups to double bonds or removal of a group producing double bond, e.g., histidine decarboxylase breaks histidine to histamine and `CO_(2)`. |
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| 538. |
Where are the following found ? Glycosidic bonds, Ester bonds, Peptide bonds, Energy-rich bonds, Double bonds. |
| Answer» (i) In carbohydrates (ii) In fats (iii) In proteins (iv) In nucleotides (v) In unsaturated fatty acids. | |
| 539. |
Serine `(HOCH_(2)CH(NH_(2))COOH)` is an essential amino acid. The correct Fisher projection of serine isA. B. C. D. |
| Answer» Correct Answer - D | |
| 540. |
A diabetic person carries a packet of glucose with him always becauseA. glucose increases the blood sugar level slowlyB. glucose reduces the blood sugar levelC. glucose increases the blood sugar level almost instantaneouslyD. glucose reduces the blood sugar level slowly |
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Answer» Correct Answer - C The sugar level in the blood of a diabetic person may suddenly fall, immediate intake of glucose increases the blood sugar level almost instantaneously. |
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| 541. |
Glucose does not react withA. `Br_2//H_2O`B. `H_2N-OH`C. HID. `NaHSO_3` |
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Answer» Correct Answer - D Glucose does not react with `NaHSO_3` |
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| 542. |
Choose the peptide that matches the abbreviation Phe-Val-Ala.A. B. C. D. |
| Answer» Correct Answer - A | |
| 543. |
Which of the following statements are correct with reference to isoelectric point?A. It is the poin at which amino acids bear no net charge.B. It corresponds to the pH at which concentration of zwitter ion in mixtureC. At isoelectric point amino acid exists as a baseD. None of the above. |
| Answer» Correct Answer - A::B | |
| 544. |
The number of peptide bonds in the compound. A. 1B. 2C. 3D. 4 |
| Answer» Correct Answer - A | |
| 545. |
Which one of the following does not exhibit the phenomenon of mutarotation ?A. (-)-fructoseB. (+)-sucroseC. (+)-lactoseD. (+)-maltose |
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Answer» Correct Answer - B All reducing monosaccharides and disaccharides (except sucrose due to the absence of hemiacetal linkage) undergo mutarotation in aqueous solutions. |
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| 546. |
Which one of the following does not exhibit the phenomenon of mutarotation ?A. (+)sucroseB. (+) lactoseC. (+) MaltoseD. (-) Fructose |
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Answer» Correct Answer - A Key idea reducing sugars that exist in hemiacetal and hemiketal forms, exhibit the phenomenon of mutarotation in aqueous solution. During mutarotaiton, the ring open upto give the open chain form which the reclose eithe rin the inverted position of in the original position giving an equilibrium mixture of two anomers with a small amount of open chain form. thus, all reducingmonosaccharides and disaccharides undergo mutarotation in aqueous solution. Among the given carbohydrates, only sucrose is a non-reducing sugar as in it the hemiacetal and hemiketal groups of glucose and fructose are linked together through O-atom and thus, not free. due to the absence of free hemiacetal or hemiketal group, sucrose does not exhibit mutarotation. |
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| 547. |
Which one of the following does not exhibit the phenomenon of mutarotation ?A. `(+)`SucroseB. `(+)` LactoseC. `(+)` MaltoseD. `(-)` Fructose |
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Answer» Correct Answer - A Sucrose does not show mutarotation. |
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| 548. |
When D-Glucose is treated with base it is converted into:A. D-FructoseB. D-MannoseC. D-GalactoseD. D-Arabinose |
| Answer» Correct Answer - A::B | |
| 549. |
Which one of the following does not exhibit the phenomenon of mutarotation ?A. `(-) - ` FructoseB. `(+) -` SucroseC. `(+) -` LactoseD. `(+) -` Maltose |
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Answer» Correct Answer - B `(+)-` Sucrose does not undergo mutarotation in solution because it does not contain a "free" aldehyde or ketone group. Only reducing sugars (remember, sucrose is a non-reducing sugar) that exist in hemiacetal and hemiketal forms, undergo mutarotation in aqueous solution. In sucrose, the hemiacetal and hemiketal groups of glucose and furctose are linked together through `O-`atom and thus, not free. Due to the absence of free hemiacetal or hemiketal group, sources does not exhibit mutarotation. |
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| 550. |
Which of the following statements are correct with reference to amino acid?A. A amino acid that contains carboxylic acid and amino group.B. Amino acids are the building blocks of peptides and proteinsC. An amino acid may exist as a zwitter ion under suitable conditions.D. Amino acids are negatively charged in basic medium |
| Answer» Correct Answer - A::B::C::D | |