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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2801. |
Name the various groups attached to the 4 valencies of carbon in an amino acid. |
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Answer» The 4 valencies of carbon in an amino acid: 1. (NH2 ) 2. an acidic carboxylic group (COOH) and 3. a hydrogen atom (H) 4. and side chain or variable R group. |
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| 2802. |
Why amino acids are amphoteric? |
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Answer» The amino acid is both an acid and a base and is called amphoteric. |
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| 2803. |
The human body does not produce.A. VitaminsB. proteinsC. enzymesD. hormones |
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Answer» Correct Answer - A |
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| 2804. |
How waxes are formed? |
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Answer» Waxes are esters formed between a long chain alcohol and saturated fatty acids. |
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| 2805. |
What are fatty acids ? Compare saturated and unsaturated fatty acids. |
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Answer» Fatty acids : Fatty acids are organic acids with a long hydrocarbon chain ending in carboxyl group (-СООН). Characteristics of fatty acids are: (i) Has a long chain of carbon atoms. (ii) Is insoluble in water. (iii) Is soluble in organic solvents. (iv) Must leave an oily spot on a piece of paper. (i) Saturated fatty acids : They do not have any double bond in between carbon atoms of molecular chain. Examples are: Palmitic acid - CH3(CH2)14СООН Stearic acid – CH3(CH2)16СООН (ii) Unsaturated fatty acids: They have one or more double bonds in between carbon atoms of molecular chain. Unsaturated fatty acids have lower melting points as compared to saturated fatty acids. Examples are: Oleic acid – CH3 (CH2)7CH = CH(CH2)7 COOH Linoleic acid – CH3(CH2)4CH = (CHCH2)2 (CH2)6 COOH |
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| 2806. |
…………… form the exoskeleton of insects & arthropods. (a) N – acetyl glucosamine (b) N – butyl glucosamine (c) N – phenyl glucosamine (d) N – methyl glucosamine |
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Answer» (a) N – acetyl glucosamine |
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| 2807. |
How saturated fatty acids differ from unsaturated fatty acids? |
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Answer» Saturated factty acids have the hydrocarbon chain with single bond, whereas in unsaturated fatty acids the hydrocarbon chain will have double bonds. |
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| 2808. |
…………… is not a reducing sugar. (a) Glucose (b) Fructose (c) Sucrose (d) Ketose |
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Answer» Sucrose is not a reducing sugar. |
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| 2809. |
Why oil does not get mixed if added with water? |
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Answer» Oil is a lipid. Lipids are long hydrocarbon chains that are non-polar & thus hydrophobic, which avoids the oil to dissolve in water. |
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| 2810. |
How many peptide linkage present in penta peptide?A. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - C |
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| 2811. |
Sucrose is a combination of …………… and fructose. (a) α – glucose (b) β – glucose (c) Ketoses (d) Maltose |
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Answer» (a) α – glucose |
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| 2812. |
Ring structure of glucose is due to formation of hemiacetal and ring formation betweenA. `C_(1)" and"C_(5)`B. `C_(1)` and `C_(4)`C. `C_(1)` and `C_(3)`D. `C_(2)` and `C_(4)` |
| Answer» Correct Answer - A | |
| 2813. |
…………… is also called as animal starch. (a) Amylose (b) Glycogen (c) Glucose (d) Glycerol |
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Answer» (b) Glycogen |
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| 2814. |
………… reagent is used in starch test. (a) Potassium permanganate (b) Potassium iodide (c) Calcium chloride (d) Calcium iodide |
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Answer» (b) Potassium iodide |
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| 2815. |
Which is an animal starch? Where can we see it in our body? |
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Answer» Glycogen. It is found in liver cells & skeletal muscles. |
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| 2816. |
What is a peptide bond (peptide linkage)? OR Define peptide bond. |
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Answer» Proteins are the polymers of a-amino acids and they are connected to each other. The bond that connects a-amino acids to each other is called peptide bond (peptide linkage, – CONH -). |
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| 2817. |
Ring structure of glucose is due to formation of hemiacetal and ring formation between:A. `C_(1)` and `C_(5)`B. `C_(1)` and `C_(4)`C. `C_(1)` and `C_(3)`D. `C_(2)` and `C_(4)` |
| Answer» Correct Answer - A | |
| 2818. |
How will you identify the presence of starch in a food sample. |
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Answer» The presence of starch is identified by adding a solution of iodine in potassium iodide. Iodine molecules fit nearly into the starch helix, creating a blue – black colour. |
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| 2819. |
Glucose is aA. monosaccharideB. disaccharideC. trisaccharideD. polysaccharide |
| Answer» Correct Answer - A | |
| 2820. |
Starch is changed into diasaccharide in presence of :A. amylaseB. maltaseC. lactaseD. zymase |
| Answer» Correct Answer - A | |
| 2821. |
Iso-electric point of alanine is (pH =6). At which pH, maximum concentration of zwitter ion of alanine will be present ?A. `pH gt 6`B. `pH lt 6`C. `pH = 6`D. `pH = 7` |
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Answer» Correct Answer - C At isoelectric point, conc. of Zwitter ion will maximum. |
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| 2822. |
Hydrolysis of sucrose is called:A. esterficiationB. saponificationC. inversionD. hydration |
| Answer» Correct Answer - C | |
| 2823. |
Sucrose on hydrolysis gives:A. glucose and galactosB. maltose and galactosC. glucose and fructoseD. None of these |
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Answer» Correct Answer - C Sucrose on hydrolysis glucose and fructose. |
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| 2824. |
The correct statement`(s)` about the following sugars `(X)` and `(Y) is//are`: A. `X` is a reducing sugar and `Y` is a non-reducing sugarB. `X` is a non-reducing sugar and `Y` is a reducing sugar.C. The glucosidic linkages in `X` and Y are `alpha` and `beta`, respectively.D. The glucosidic linkages in `X` and `Y` are `beta` and `alpha`, respectively. |
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Answer» Correct Answer - B::C `X` has acetal linkage and `Y` has hemiacetal linkage. Carbohydrate with hemiacetal linkage are reducing `X` is `alpha-` anomer and `Y` is `beta-` anomer of `D(+)` glucose. |
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| 2825. |
Hydrolysis of sucrose is called:A. sapnificationB. hydrationC. inversionD. esterification |
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Answer» Correct Answer - C The hydrolysis of sources bring about a change in the sign of rotation from dextro `(+)` to laevo `(-)` and such a change is known as inversion. `underset([alpha]_(D)=+66.5^(@))underset("sucrose")(C_(12)H_(22)O_(11))+H_(2)Ooverset(HCl)tounderset([alpha]_(D)=+52.5^(@))underset("D-glucose")(C_(6)H_(12)O_(6))+underset([alpha]_(D)=-92.4^(@))underset("D-fructose")(C_(6)H_(12)O_(6))` |
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| 2826. |
Cellulose upon acetylation with excess `anhydride//H_(2)SO_(4)` (catalytic) gives cellulose triacetate whose structure is:A. B. C. D. |
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Answer» Correct Answer - A Cellulose is a linear-chain polysaccharide of `D-`glucose which is joined by `beta-`glycosidic linkage between `C-1` of one glucose and `C-4` of the next glucose. In one unit, only three `OH` groups are free to form triacetate, hence the structure is as given in `(a)`. That is why it is called cellulose triacetate. |
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| 2827. |
Among cellulose, poly viny chloride), nylon and nutural rubber, the polymer is which the intermolecular force of attraction is weakest is:A. NylonB. Poly vinyl chlorideC. CelluloseD. Natural Rubber |
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Answer» Correct Answer - D The natural rubber has intermolecular forces which are weak dispersion force (van-der-waal forces of attaction) and is an example of an elastomer (polymer). |
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| 2828. |
The two forms of `D-glucopyranose obtained from solution of D-glucose are known as:A. anomersB. epumersC. enantiomersD. geometrical isomers |
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Answer» Correct Answer - A The D-glucose exists as `alpha-D(+)`-glucose and `beta-D(+)`- glucose which differ only at `C_(1)` position of `OH` and called anomers. |
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| 2829. |
Write down the heteroheneous catalyst involved in the polymerisation of ethylene. |
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Answer» Correct Answer - Ziegler Natta catalyst. `(R_(3)Al + TiCl_(4))`. Ziegler Natta catalyst. `(R_(3)Al+TiCl_(4))`. |
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| 2830. |
The two forms of `D-glucopyranose obtained from solution of D-glucose are known as:A. EpimersB. AnomersC. EnantiomersD. Geometrical isomers |
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Answer» Correct Answer - B `alpha-D-`Glucopyranose and `beta-D-` Glucopyranse are anomers. |
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| 2831. |
The two forms of `D-glucopyranose obtained from solution of D-glucose are known as:A. IsomersB. AnomersC. EpimersD. Enantiomers |
| Answer» Correct Answer - b | |
| 2832. |
Which of the molecules below will react with `Ag^(+)` ? A. (i), (iii) and (v)B. (ii) and (iv)C. (iv) and (vi)D. (i), (ii), (iii) and (vi) |
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Answer» Correct Answer - C Aldehyde give in open chain form. |
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| 2833. |
Glucose does not react withA. pure HCNB. Schiff s reagentC. `NaHSO_(3)`D. all of these |
| Answer» Correct Answer - d | |
| 2834. |
Which of the molecules below will react with `Ag^(+)`? A. (P), (R ) and (T)B. (Q) and (S)C. (S) and (U)D. (P), (Q),(R ) and (U) |
| Answer» Correct Answer - c | |
| 2835. |
Which one of the following is invert sugar ?A. GlucoseB. FructoseC. SucroseD. None of these |
| Answer» Correct Answer - d | |
| 2836. |
Polypeptide is…… of protein.A. monomerB. primary structureC. derivativeD. anhydride |
| Answer» Correct Answer - b | |
| 2837. |
`overset(+)NH_(3)-CH(R )-CO_(2)H` has its `Ka_(1)=10^(-7)`. The isoelectric point of the a-amino acid occur at pH = 8.2 hence `pKa_(2)` of the conjugate acid of the `alpha` -amino acid is equal to :A. 9.4B. 1.2C. 7.6D. 2.4 |
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Answer» Correct Answer - a Isoelectric pH of a aminoacid =`(pK_(a)^(1)+pK_(a)^(2))/(2)` `:." "8.2=(7+pK_(a)^(2))/(2)` `rArrpK_(a)^(2)=16.4-7=9.4` |
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| 2838. |
The thylakoids in chloroplast are arranged in ……(a) regular rings (b) linear array (c) diagonal direction (d) stacked discs |
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Answer» (d) stacked discs |
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| 2839. |
Main arena of various types of activities of a cell is ………… (a) Nucleus (b) Mitochondria (c) Cytoplasm (d) Chloroplast |
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Answer» Main arena of various types of activities of a cell is Cytoplasm. |
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| 2840. |
Golgi complex plays a major role in …………… . (a) post translational modification of proteins and glycosidation of lipids (b) translation of proteins (c) Transcription of proteins (d) Synthesis of lipid |
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Answer» (a) post translational modification of proteins and glycosidation of lipids |
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| 2841. |
Major site for the synthesis of lipids …………… . (a) Rough ER (b) smooth ER(c) Centriole (d) Lysosome |
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Answer» Major site for the synthesis of lipids smooth ER. |
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| 2842. |
Which organelle is present in higher number in secretory cell? (a) Mitochondria (b) Chloroplast (c) Nucleus (d) Dictyosomes |
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Answer» (d) Dictyosomes |
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| 2843. |
Which is the most common energy carrier in the cell ? |
| Answer» Correct Answer - ATP. | |
| 2844. |
Some tissues have lipids with more complex structures especially theA. neutral tissueB. Connective tissuesC. Muscular tissuesD. Epithelial tissues |
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Answer» Correct Answer - A (A) Some tissues have lipids with more complex sturctures especially the neural tissues. |
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| 2845. |
Read the following statement and find out the incorrect statement(S)A. Palmitic acid is saturated while arachidonic acid is unsaturated fatty acidB. Monoglycerides, diglycerides and trighlycerides are lipids having both glycerol and fatty acids.C. Sturated fatty acids have one or more C=C double bonds while unsaturated fatty acids are without double bondss.D. Fats and oils are differentiated on the basis of melting point. |
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Answer» Correct Answer - C (C) Palmitic acid is sturated while arachidonic acid is unsaturated fatty acid. Monoglycerides , diglycerides and triglycerides are lipid having both glycerol and fatty acids. Unsaturated fatty acids have one of more C = C double bonds while saturated fatty acids are without double bonds. Fat and oils are differentiated on the basis of melting point. |
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| 2846. |
Triglycerides are fatty acid esters of glycerol, which are formed by the esterification of ____ molecule (s) of fatty acids with ____ molecule(s) of glycerol.A. one, twoB. one, threeC. three, oneD. two, one |
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Answer» Correct Answer - C The three hydroxyl groups of a glycerol molecule join with the carboxyl groups of the fatty acid molecules to form a fat or triglyceride molecule. The chemical linkage between the glycerol and fatty acids is caled the ester bond. It results from the elimination of three molecules of water (condensation or dehydration). |
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| 2847. |
The smallest aldose which is able to form cyclic hemiacetal `is//are`:A. D-glyceraldehydeB. D-ErythroseC. D-ThreoseD. D-Ribose |
| Answer» Correct Answer - B::C | |
| 2848. |
Which of the following enzyme is used to join DNA fragments :A. LigaseB. PrimaseC. DNA polymeraseD. Endonuclease |
| Answer» Correct Answer - A | |
| 2849. |
Which purine base is found in RNA ?A. ThymineB. UracilC. CytosineD. Guanine |
| Answer» Correct Answer - D | |
| 2850. |
Length of one loop of B-DNA is `:`A. 3.4 nmB. 0.34 nmC. 20 nmD. 10 nm |
| Answer» Correct Answer - A | |