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1.

Which of these models is a hybrid of LES and RANS?(a) DNS model(b) DES model(c) WALE model(d) RNG – LES modelI had been asked this question during an online exam.This interesting question is from Turbulence Modelling topic in chapter Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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The CORRECT choice is (b) DES model

The best I can EXPLAIN: DES model is a hybrid of LES and RANS model and makes use of advantages of both. For treating near –wall REGIONS, DES works like the RANS model and for rest of the region, it works as the LES model.

2.

How does the turbulent boundary layer vary with respect to the Reynolds number?(a) Rex^–\(\frac {1}{5}\)(b) Rex^–\(\frac {1}{4}\)(c) Rex^–\(\frac {1}{2}\)(d) Rex^-2I have been asked this question in an interview for internship.Question is from Turbulence Modelling topic in chapter Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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The correct choice is (a) Rex^–\(\frac {1}{5}\)

The EXPLANATION is: The turbulent BOUNDARY layer thickness in an incompressible FLOW is GIVEN by:

δ = \(\frac {0.37x}{Re_x^{-1/5}}\)

Thus the turbulent boundary layer thickness VARIES as Rex^-1/5 whereas in case of laminar flow, it varies as Rex^-1/4.

3.

What is the skin friction drag for an incompressible turbulent flow with Reynolds number =1.5 × 10^7 over a flat plate?(a) 2.72 × 10^-3(b) 5.41 × 10^-3(c) 3.82 × 10^-3(d) 2.91 × 10^-3The question was posed to me in an online interview.I'd like to ask this question from Turbulence Modelling in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right answer is (a) 2.72 × 10^-3

Easy explanation: GIVEN, Rec = 1.5 × 10^7

The skin friction drag over a flat plate for an incompressible turbulent FLOW is given by:

CF = \(\frac {0.074}{Re_c^{1/5}}\)

Substituting the VALUES,

Cf = \(\frac {0.074}{1.5 \TIMES 10^{7^{1/5}}}= \frac {0.074}{27.24}\) = 2.72 × 10^-3

4.

What is the equation for momentum thickness?(a) δ^* = \(\int_0^∞ \frac {u}{U_e} \big [ \)1 – \(\big ( \frac {u}{U_e} \big )^2 \big ] \)dy(b) δ^* = \(\int_0^∞ \frac {u}{U_e} \big [ \)1 – \(\frac {u}{U_e}\big ] \)dy(c) δ^* = \(\int_0^∞ \big [ \)1 – \(\frac {u}{U_e} \big ] \)dy(d) δ^* = \(\int_0^∞ \frac {u}{U_e} \big [ \)1 + \(\frac {u}{U_e} \big ]\)dyThe question was asked during an interview.Question is taken from Boundary Layer Properties topic in section Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct answer is (b) δ^* = \(\int_0^∞ \frac {u}{U_e} \big [ \)1 – \(\frac {u}{U_e}\big ] \)dy

The explanation: WITHIN the boundary layer, momentum thickness is DESCRIBED in RELATION to the momentum flow rate. This rate is lower than that which would occur if there were no boundary layer, when the velocity would be equal to the mainstream velocity UE in the vicinity of the surface considered at the station.

It is given by:

δ^* = \(\int_0^∞ \frac {u}{U_e}\big [ \)1 – \(\frac {u}{U_e} \big ] \)dy

Where, u is velocity at some point x on the plate

Ue is the freestream velocity.

5.

Which of these is a two – equation model?(a) Baldwin – Lomax model(b) Prandtl’s equation model(c) Spalart – Allmaras model(d) K – Epsilon modelThis question was addressed to me during a job interview.Question is taken from Turbulence Modelling topic in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct CHOICE is (d) K – EPSILON model

Best explanation: K – epsilon model is a two – equation model which includes two transport equations REPRESENTING the turbulent flow PROPERTIES. The first transport equation is solved is the turbulent kinetic energy, and the second one is the turbulent dissipation rate.

6.

The displacement thickness is the distance by which, due to the presence of the boundary layer, the flow streamline is displaced.(a) True(b) FalseI got this question by my college director while I was bunking the class.My question is based upon Boundary Layer Properties topic in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right answer is (a) True

The best explanation: Displacement thickness is one of the properties of boundary layer which is the DISTANCE by which the external streamline gets displaced due to the PRESENCE of the boundary layer.

Without the presence of boundary layer, which is the case of inviscid flow, the streamline would be straight and parallel to the FLAT surface. But due to the presence of boundary layer in real life scenario having viscous flow, the streamline is displaced.

The formula for the displacement thickness δ^* is given by:

δ^* = \(\INT _0^{y1}\)(1 – \(\frac {ρu}{ρ_e u_e}\))dy

7.

Which of these relations is applicable for turbulent and laminar boundary layer?(a) δTturbulent < δTlaminar(b) δTturbulent = δTlaminar(c) δturbulent < δlaminar(d) δturbulent > δlaminarThis question was posed to me in homework.This key question is from Boundary Layer Properties in chapter Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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The CORRECT OPTION is (d) δturbulent > δlaminar

To explain: In case of turbulent flow, there is a high energy and momentum exchange compared to the laminar flow DUE to the PRESENCE of eddies. This leads to the thermal and velocity boundary layer THICKNESS of the turbulent flow to be higher than that of the laminar flow. Thus, δturbulent > δlaminar and δTturbulent > δTlaminar.

8.

When there’s flow over a flat plate, there’s laminar boundary layer at the leading edge followed by turbulent boundary layer.(a) True(b) FalseThis question was addressed to me during an interview.I'd like to ask this question from Boundary Layer Properties in section Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right ANSWER is (a) True

To explain I would say: When a flat plate is kept in the freestream flow, there’s a FORMATION of a laminar boundary LAYER at the leading edge. This boundary layer THICKNESS grows to a point where a transition point is reached. Beyond that point, there’s turbulence due to the PRESENCE of eddies and there’s turbulent boundary layer formation whose thickness keeps on increasing.

9.

Which of these is not a property of boundary layer?(a) No – slip condition at the surface(b) Temperature of fluid at the surface is equal to wall temperature(c) Flow velocity increases along y – direction(d) Thermal boundary layer is equal to velocity boundary layerThe question was asked in an interview.This is a very interesting question from Boundary Layer Properties in portion Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right option is (d) Thermal boundary layer is EQUAL to velocity boundary layer

The EXPLANATION is: When there’s a viscous flow over a flat plate, there’s a boundary layer formation which has certain properties. On the surface, there’s a no slip CONDITION. Apart from this the temperature of the fluid which is immediately at the surface has the same temperature as the surface which is known as the wall temperature. The velocity profile inside a boundary layer increases along the y – direction until it BECOMES equal to the freestream velocity. The only property that is incorrect is that the thermal boundary layer is equal to the velocity boundary layer.

The boundary of thermal layer is defined as the layer where the outer EDGE temperature becomes equal to the freestream temperature. Similarly, at the velocity boundary layer, the outer edge velocity is equal to the freestream velocity.

10.

One equation turbulence model account for the history effects such as turbulent energy, diffusion and convection.(a) True(b) FalseI got this question during an online exam.I would like to ask this question from Turbulence Modelling topic in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct ANSWER is (b) False

For explanation: One equation turbulence model only solves one TURBULENT TRANSPORT equation mostly the kinetic energy. It is the two equation turbulent model that ACCOUNTS for the history EFFECTS such as turbulent energy, diffusion and convection.

11.

What is the thermal boundary layer?(a) T = 0.90Te(b) T = 0.89Te(c) T = 0.99Te(d) T = 0.97TeI have been asked this question in an interview.This intriguing question comes from Boundary Layer Properties in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct answer is (c) T = 0.99Te

To elaborate: The FLOW temperature just like velocity varies within the BOUNDARY layer. It is a function of y – direction. The temperature ranges from TW which is the temperature at the wall (y = 0) to T = 0.99Te at y = δt, where δt is the thermal boundary layer thickness. This VARIATION of temperature is known as temperature PROFILE.

12.

In which case are the velocity and thermal boundary layer equal?(a) Pr = 0(b) Pr = 1(c) Pr > 1(d) Pr < 1I got this question during an internship interview.This question is from Boundary Layer Properties topic in section Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right answer is (b) PR = 1

For explanation I would say: In most of the CASES the two thermal and velocity BOUNDARY layers are not same except in one exceptional case when the Prandtl number=1, in which case δt = δ. When Prandtl number is greater than 1, δt < δ and when Prandtl number is LESS than 1, δt > δ. In real life scenario, the Prandtl number is equal to 0.71 thus the thermal boundary layer thickness is greater than the velocity boundary layer thickness.

13.

How is the boundary layer thickness defined? (ue is the outer edge velocity)(a) u = 0.99ue(b) u = 0.89ue(c) u = 0.90ue(d) u = 0.50ueThis question was addressed to me in class test.Query is from Boundary Layer Properties in portion Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right choice is (a) U = 0.99ue

Best explanation: Inside the BOUNDARY layer, the velocity INCREASES along the y – direction until it becomes equal to the freestream velocity. The thickness of boundary layer δ is defined as the POINT from the surface where the velocity is 0.99 times the free stream velocity.

14.

Which of these models compute large vortexes directly while neglecting small scale eddies?(a) DNS(b) LES(c) RANS(d) FANSI got this question in a national level competition.My question is taken from Turbulence Modelling in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct choice is (b) LES

For explanation I would say: In Large Eddy simulation, large EDDIES are computed by resolving large time and length SCALES. In LES, the smaller length scales are IGNORED making it an economical and LESS time consuming than DNS.

15.

Turbulent boundary layer is considered to be a combination of inner and outer layer.(a) True(b) FalseI have been asked this question during an internship interview.My question comes from Turbulence Modelling topic in chapter Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct option is (a) True

Best EXPLANATION: Turbulent boundary layer consists of inner and outer layers. There is a VISCOUS – dependent part of the PROFILE very close to the surface and different LENGTH scaling parameters are needed for the REMAINING Reynolds – stress – dependent part of the profile.

16.

What are the shortcomings of DNS?(a) Possible for low Reynolds number(b) Low scale resolution(c) Time consuming(d) Possible for high Reynolds numberThis question was posed to me in an interview.My query is from Turbulence Modelling topic in portion Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct option is (a) Possible for low Reynolds number

Explanation: The DNS solves the time – DEPENDENT NAVIER’s Stokes equation by resolving eddies of all scales for a SUFFICIENT time before reaching STATISTICAL equilibrium. The only shortcoming is that DNS is only applicable for low Reynolds number flow which has simple GEOMETRY.

17.

Why are turbulence models used?(a) Define reynolds stress for closure problems(b) Model hypersonic flows(c) Lack of system to accurately find turbulent flow characteristic(d) Closure of continuity equationI had been asked this question during an interview.The question is from Turbulence Modelling topic in section Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Right ANSWER is (a) Define reynolds stress for closure problems

For explanation: While solving Navier’s Stokes equation for turbulent flow which governs the velocity, pressure of the fluid, the quantity is decomposed into mean and fluctuating components. While solving these using RANS equation, we get a reynolds stress term that needs to be closed in order to SOLVE it. HENCE we make use of TURBULENCE modeling which defines these reynolds stresses in terms of the known averaged quantities.

18.

What is the value of kinetic energy thickness?(a) δ^** = \(\int_0^∞ \frac {u}{U_e}\big [\)1 – \(\big ( \frac {u}{U_e}\big )^2 \big ] \)dy(b) δ^** = \(\int_0^∞ \frac {u}{U_e} \big [\)1 – \(\frac {u}{U_e}\big ] \)dy(c) δ^** = \(\int_0^∞ \big [ \)1 – \(\frac {u}{U_e} \big ] \)dy(d) δ^** = \(\int_0^∞ \frac {u}{U_e} \big [ \)1 + \(\frac {u}{U_e}\big ] \)dyThe question was posed to me by my school teacher while I was bunking the class.My question comes from Boundary Layer Properties in portion Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

Answer» CORRECT option is (a) δ^** = \(\int_0^∞ \FRAC {u}{U_e}\big [\)1 – \(\big ( \frac {u}{U_e}\big )^2 \big ] \)dy

Best explanation: Kinetic energy thickness is the distance the boundary is displaced by in the perpendicular direction to compensate for the reduced kinetic energy of the fluid due to the formation of boundary layer. It is given by:

δ^** = \(\int_0^∞ \frac {u}{U_e}\big [\)1 – \(\big ( \frac {u}{U_e}\big )^2 \big ] \)dy

Where, u is velocity at some point x on the plate.

Ue is the freestream velocity.
19.

According to the y – momentum equation, how does the pressure vary inside the boundary layer normal in the direction normal to the surface?(a) Increases(b) Decreases(c) Remains constant(d) First increases then decreasesI have been asked this question in an interview for job.This key question is from Boundary Layer Properties topic in chapter Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct choice is (C) Remains constant

To elaborate: The y – momentum equation for a boundary LAYER is given by:

\(\frac {∂p}{∂y}\) = 0

According to the FORMULA, at any x POINT in the boundary layer, pressure remains constant in the direction normal to the SURFACE.

20.

What leads to shear stress between the adjacent layers of fluid inside the boundary layer adjacent to the surface?(a) Aerodynamics drag(b) Viscosity(c) Pressure drag(d) Wave dragI got this question at a job interview.The origin of the question is Boundary Layer Properties topic in section Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct answer is (b) Viscosity

For explanation: There is shear stress between the ADJACENT layers of fluid in both laminar and turbulent FLOW inside the boundary LAYER. This is due to the viscosity and it is given by the relation:

τ = μ\(\frac {∂u}{∂y}\)

Where, \(\frac {∂u}{∂y}\) is the transverse VICTORY gradient.

21.

Which of these models solves turbulent kinetic energy and specific dissipation?(a) K – omega model(b) K – epsilon model(c) RANS model(d) RNG – LES modelI have been asked this question in homework.My enquiry is from Turbulence Modelling topic in section Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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Correct option is (a) K – omega MODEL

Easy explanation: K – omega is ONE of the POPULAR turbulence model. It is a TWO-equation model which solves two transport equations –turbulent kinetic energy and specific dissipation. Turbulent kinetic energy determines the energy whereas the specific dissipation determines the turbulence scale.

22.

When the Reynolds number approaches infinity, what happens to the boundary layer thickness?(a) Approaches infinity(b) Approaches zero(c) Approaches once(d) Remains sameI have been asked this question during an online interview.This intriguing question originated from Boundary Layer Properties in chapter Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

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The correct ANSWER is (b) Approaches zero

Explanation: As the Reynolds number INCREASES, the boundary LAYER thickness decreases when compared to the length of the body. Usually for very large AIRCRAFTS, the value of \(\frac {δ}{L}\) is AROUND 0.01 which is a very small value. So hypothetically, as Re ➔ ∞, δ ➔ 0.