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What is the skin friction drag for an incompressible turbulent flow with Reynolds number =1.5 × 10^7 over a flat plate?(a) 2.72 × 10^-3(b) 5.41 × 10^-3(c) 3.82 × 10^-3(d) 2.91 × 10^-3The question was posed to me in an online interview.I'd like to ask this question from Turbulence Modelling in division Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions of Aerodynamics

Answer»

Right answer is (a) 2.72 × 10^-3

Easy explanation: GIVEN, Rec = 1.5 × 10^7

The skin friction drag over a flat plate for an incompressible turbulent FLOW is given by:

CF = \(\frac {0.074}{Re_c^{1/5}}\)

Substituting the VALUES,

Cf = \(\frac {0.074}{1.5 \TIMES 10^{7^{1/5}}}= \frac {0.074}{27.24}\) = 2.72 × 10^-3



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