844 + Interview Questions in CHEMICAL-BONDING-AND-MOLECULAR-STRUCTURE IN GENERAL AWARENESS Page 1 InterviewSolution

1.	Statement-1 : `NH_(3)` is pyramidal in shape . Statement-2 : `SiCl_(4)` and `GaCl_(4)^(-)` are isostructural . Statement-3 : `sd^(3)` hybridisation may be possibleA. TTFB. TTTC. FTTD. TFT
Answer» Correct Answer - B

Discussion

2.	`O_(2)` and `N_(2)` are respectivelyA. Diamagnetic , ParamagneticB. Paramagnetic , DiamagneticC. Both the paramagneticD. Both are diamagnetic
Answer» Correct Answer - B

Discussion

3.	Molecular shape of `ClF_(3) , l_(3)^(-)` and `XeO_(3)` respectively areA. T-shape , Linear , PyramidalB. Planar , Linear , TetrahedralC. T-shape , Planar , PyramidalD. Trigonal bipyramidal , Linear , Tetrahedral
Answer» Correct Answer - A

Discussion

4.	In case of `XeO_(2) F_(2)` and `XeF_(6)` , Xe is withA. Same hybridization but with different geometryB. Different hybridization with same geometryC. Different hybridization and different geometryD. Same geometry and same hybridization
Answer» Correct Answer - C

Discussion

5.	The shapes of `XeO_(2)F_(2)` molecule isA. trigonal bipyramidalB. square planarC. tetrahedralD. see-saw.
Answer» Correct Answer - D Hybridisation state of Xe in `XeO_(2)F_(2)` : `H=1/2[8+2-0+0]=sp^(3)d`

Discussion

6.	Which is the correct arrangement of the molecules basexd on dipole moments ?A. `BF_(3) = NH_(3) = NF_(3)`B. `BF_(3) gt NH_(3) gt NF_(3)`C. `BF_(3) lt NH_(3) lt NF_(3)`D. `BF_(3) lt NF_(3) lt NH_(3)`
Answer» Correct Answer - D

Discussion

7.	Which one of the following arrangements of molecules is correct on the basis of their dipole moments ?A. `BF_(3) gt NF_(3) NH_(3)`B. `NF_(3) gt BF_(3) gt NH_(3)`C. `NH_(3) = NF_(3) gt BF_(3)`D. `NH_(3) gt NF_(3) gt BF_(3)`
Answer» Correct Answer - D `mu(NH_(3)) gt mu (NF_(3))` `mu (BF_(3)) = 0`

Discussion

8.	The crystal lattice of electro covalent compounds is composed ofA. AtomsB. MoleculesC. Oppositely charged ionsD. Both molecules and ions
Answer» Correct Answer - C

Discussion

9.	Statement 1 : All molecules with polar bonds may not have dipole moments Statement 2 : Dipole moment is a vectot quantity and bond dipoles may cancel out.A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-1B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-1C. Statement-1 is true, Statement-2 is false.D. Statement-1 is false, Statement-2 is true.
Answer» Correct Answer - a Statement 2 is the correct explanation for Statement 1.

Discussion

10.	The crystal lattice of electro covalent compounds is composed ofA. atomsB. moleculesC. oppositeoly charged ionsD. both molecules and ions.
Answer» Correct Answer - C

Discussion

11.	Which is the correct arrangement of the molecules basexd on dipole moments ?A. `BF_(3) gt NF_(3) gt NH_(3)`B. `NF_(3) gt BF_(3) gt NH_(3)`C. `NH_(3) gt BF_(3) gt NF_(3)`D. `NH_(3) gt NF_(3) gt BF_(3)`
Answer» Correct Answer - D is the correct order of dipole moment values.

Discussion

12.	Covalent compounds have olw m.p. because :A. Covalent molecules are held by weak van der Waals forcesB. Covalent bond is less exothermicC. Covalent bond is weeker than ionic bondD. Covalent molecules have definite shapes.
Answer» Correct Answer - A is the correct answer.

Discussion

13.	Pick out the incorrect statementA. `N_2` has greater dissociation energy than `N_2^+`B. `O_2` has lower dissociation energy than `O_2^+`C. Bond length in `N_2^+` is less than in `N_2`D. Bond length in `NO^+` is less than in NO.
Answer» Correct Answer - C

Discussion

14.	If `I_(0)` is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given byA. `[(2h)/m(lambda_0-lambda)]^(1//2)`B. `[(2hc)/m(lambda_0-lambda)]^(1//2)`C. `[(2hc)/m((lambda_0-lambda)/(lambda_0lambda))]^(1//2)`D. `[(2h)/m(1/lambda_0-1/lambda)]^(1//2)`
Answer» Correct Answer - C

Discussion

15.	Which out of `NH_(3) and NF_(3)` has higher dipole ment and why ?
Answer» `NH_(3)` has higher dipole moment the `NF_(3)` .

Discussion

16.	Although geometries of `NH_(3) and H_(2) O ` molecules are distorted tetrahedral, bond angle in water is less then that of ammonia. Discuss .
Answer» In ` NH_(3)`, there is only one lone pair on N-atom to repel the bond pairs whereas in ` H_(2)O` , there are two lone pairs on O-atom to repel the bond paris . Hence the repulsions on bond pairs are greater in ` H_(2) O ` than in ` NH_(3)` and hence the bond angle is less.

Discussion

17.	Asseration: `SeCl_(4)`, does not havea tetrahedral structure. Reason: `Se` in `SeCl_(4)` has two lone pairs.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - C

Discussion

18.	Assertion(A) - The nearly tetrahedral arrangement of the orbitals about the oxygen atom allows each water molecule to form hydrogen bonds with as many as four neighbouring water molecules. Reason(R)-In ice each water molecule forms four hydrogen bonds as each molecule is fixed in the space.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - A

Discussion

19.	Although geometries of `NH_(3)` and `H_(2)O` molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.
Answer» In `overset(* )NH_(3)and "in" H_(2)overset( *)(O":")` molecules the central atom is surrounded by four electron pairs. The geometries of these molecules are expected to be tetrahedral. They however, get distorted on account of the presence f lone electron pairs. On comparisionk, the bond angle in `NH_(3)(107^(@))` is more than in `H_(2)O(104^(@)).` This is on occount of greater magnitude off form of lone pair : lone repulsion in `H_(2)O` molecule as compared to lone pair : shared pair repulsion in `NH_(3)` molecule.

Discussion

20.	Bond angle in `PH_(3)` isA. Much less than `NH_(3)`B. Much less than `PF_(3)`C. More than `NH_(3)`D. More than `PF_(3)`
Answer» Correct Answer - A::B Bond angles `{:(NH_(3)gt,PF_(3)gt,PH_(3),,),((107^(@)),(98^(@)),(94^(@)),,):}` `PF_(3) gt PH_(3)` F-atoms are larger than H-atoms and need more space `NH_(3) gt PH_(3)` Bond angle decreases down group 15 hydrides .

Discussion

21.	Which has regular tetrahedral geometary ?A. `SF_(4)`B. `BF_(4)`C. `XeF_(4)`D. `[Ni(CN)_(4)]^(2)`
Answer» Correct Answer - b `B `in `BF_(4)^(-)` is `sp^(2)` hybridised.

Discussion

22.	Among the triatomic molecules/ions `BeCl_(2),N_(3)^(-),N_(2)O, NO_(2)^(+), O_(3), SCl_(2), lCl_(2)^(-),l_(3)^(-)` and `XeF_(2)`, the total number of linear molecules (s)/ion(s) where the hybridisation of the central atom does not have contribution from the `d`- orbitals (s) is [atomic number of `S=16, Cl=17, I=53` and `Xe=54`]
Answer» Correct Answer - 4 `underset("Linear sp hybridisation")underbrace(CI-Be-CI overset(-1)(N)=overset(+1)(N)=overset(-1)N N-=NrarrO " O"=overset(o+)(N)=O)`.

Discussion

23.	Among the following moleculas/ions `BeCl_(2) ,N_(3)^(-) ,N_(2)O,NO_(2)^(+),O_(3),SCl_(2),ICI_(2)^(-) ,I_(3)^(-) and XeF_(2)`, the total number of linear molecule(s)ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is (Atomic number : S 16, Cl =37 ,I = 53 and Xe 54)
Answer» Correct Answer - 4 `BeCl_(2) to sp tp ` linear `SCl_(2) to sp^(3) to ` bent `N_(3)^(-) to sp to ` linear `I_(3)^(-) to sp^(2)d to ` linear `N_(2)O to sp to ` linear `Icl to sp^(3) d to ` linear ` NO_(2)^(+) to sp to ` linear `XeF_(2) to sp^(3) d to ` linear `O_(3) to sp^(2) to ` bent Thus , there are total four linear molecular/ions where the hybridisation of the central atom does not have contribution from the d-orbitals .

Discussion

24.	The bond length between C- C bonds in `sp^2` hybridised molecule isA. 1.2 Ã…B. 1.32 Ã…C. 1.54 Ã…D. 1.4 Ã…
Answer» Correct Answer - B

Discussion

25.	Assertion (A): Among the two O-H bonds in `H_(2)O` molecule, the energy required to break the first O-H bond and the other O-H bond is the same. Reason (R) This is because the electronic environment around oxygen is the same even after brekage of one O-H bond.A. A and R both are correct and R is the correct explanation of A.B. A and R both are correct but R is not the correct explanation of A.C. A is true but R is false.D. A and R bot are false.
Answer» Correct Answer - D Correct assertion. Among the two O-H bonds in `H_(2)O` molecule, the energy required to break the first O-H bond and the second O-H bond are different Correct reason. The electronic environment is different after the breakage of one O-H bond.

Discussion

26.	Is there any change in hybridisation of the `B` and `N` atom as a result of the following reaction? `BF_(3)+NH_(3)rarr F_(3)B.NH_(3)`
Answer» In `BF_(3),` B atom is `sp^(2)` hybridised. It froms an addition compound with `overset(* *)NH_(3)` (Where N atom is `sp^(3)` hybridised). In doing so it takes up an electron pair from `NH_(3).` This indicated that B atom undergoes a charge in hybridisation from `sp^(2)` to `sp^(3).` At the same there is no change in hybridisation of N atom.

Discussion

27.	Wrtie the state of hybridisation of boron in `BF_(3)`.
Answer» Correct Answer - `sp^(2)` .

Discussion

28.	Is there any change in the hybridisation of B and N atoms as a result of the reaction , `BF_(3) + NH_(3) to F_(3) B. NH_(3)` ?
Answer» In `BF_(3) B is sp^(2)` hybridised and in `NH_(3)` , N is `sp^(3)` hybridised . After the reaction, hybridisation of B Changes to `sp^(3)` but that N remains unchanged .

Discussion

29.	The correct sequence of decrease in the bond angles of the following hybrides isA. `NH_(3) gt PH_(3) gt AsH_(3) gt SbH_(3)`B. `NH_(3) gt AsH_(3) gt PH_(3) gt SbH_(3)`C. `SbH_(3) gt AsH_(3) gt PH_(3) gt NH_(3)`D. `PH_(3) gt NH_(3) gt AsH_(3) gt SbH_(3)`
Answer» Correct Answer - A In similar molecules, as the electronegativity of the central atom decreases and the size increases, the bond angle decreases.

Discussion

30.	Arrange the molecules `H_(2), O_(2), F_(2) and N_(2)` in order of increasing bond lengths.
Answer» `{:(H-H lt " "N-=N lt" " O=O lt " "F-F),("(74 pm) (110 pm) (120 PM) (144 PM)"):}`

Discussion

31.	The magnetic moment of `KO_(2)` at room temperature is …… BM.A. 1.41B. 1.73C. 2.23D. 2.64
Answer» Correct Answer - B `KO_(2)` contains `O_(2)^(-)` ion which has one unpaired electron . Hence `mu= sqrt(n (n + 2) )BM= sqrt(1(1+2))` `sqrt(3) = 1.73` BM .

Discussion

32.	One the basic of ground electronic configuration, arrange the following molecules in the oder of increasing `O -O` bond lengths `KO_(2), O_(2) ,O_(2)[AsF_(6)]` .
Answer» `KO_(2) rarr K^(o+) +O_(Theta)`(Peroxide ion) `O_(2)[AsF_(6)]rarrO_(2)^(o+)("Dioxygenyl") +[As^(+5) F_(6)^(-6)]^(Theta)` Bond order of `O_(2)^(Theta),O_(2)` and `O_(2)^(o+) =1.0,2` and 1.5 respectively `:.` Bond length `prop (1)/("Bond order")` Therefore increasing `(O-O)` bond lenght is `O_(2)^(o+)[AsF_(6)]^(Theta) ltO_(2) ltK^(o+)O_(2)^(Theta)` .

Discussion

33.	Arrange the following compounds in the increasing order of bond length of O-O bond `O_(2), O_(2) [AsF_(6)], KO_(2)` Explain on the basis of ground state electronic of dioxygen in there molecules .
Answer» `O_(2) [AsF_(6)]` has ` O_(2)^(-) ` ion while `KO_(2) ` has ` O_(2)^(-)` ion . E.C. of ` O_(2) = KK sigma _(2s)^(2) sigma _(2s)^(2) sigma _(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(1)pi_(2p_(y))^(1) " "` Bond order ` (1)/(2) (8-4) = 2 ` E.C. of ` O_(2)^(+) = KK sigma _(2s)^(2) sigma _(2s)^(2) sigma _(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(1)pi_(2p_(y))^(0) " "` Bond order ` = (1)/(2) (8-3) = 2.5` E.C. of ` O_(2)^(-) = KK sigma _(2s)^(2) sigma _(2s)^(2) sigma _(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(2)pi_(2p_(y))^(**1) " "` Bond order `= (1)/(2) (8-5) = 1.5 ` Higher the bond order , smaller is the bond length . Hence , order of O-O bond length is : ` O_(2) [AgF_(6)] lt O_(2) lt KO_(2)`.

Discussion

34.	Which of the following statemwnt regarding valence bond theory `(VBT)` is not true ? .A. A molecule is considered to be a collection of atoms, and the interactions between different atoms is considered .B. For a molecule to be stable the electrostatic attactions must predominate over the repulsion .C. The potential energy of a diatomic molecule is less than the sum of potential energies of free atoms .D. The net force of altration acting on the atoms in a molecule is not zero .
Answer» Correct Answer - D

Discussion

35.	Explain how the valence bond theory accounts for (i) a carbon-carbon double bond (C = C ) (ii) a carbon-carbon triple bond `(C-=C)`
Answer» Explain with examples of ethylene and acetylene

Discussion

36.	Statement 1: The addition of electron in antibonding M.O. decreases bond order. Statement 2: Antibonding electrons tend ot bring the atoms close together.A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-5B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-5C. Statement-1 is true, Statement-2 is false.D. Statement-1 is false, Statement-2 is true.
Answer» Correct Answer - c Correct statement-2 Bond order =`1/2[N_(b)-N_(a)]`

Discussion

37.	Statement 1: `PF_(5)` molecule is little less stable as compared to `SF_(6)` molecule. Statement :2 In `PF_(5)` molecule is little less stable as compared to `SF_(6)` molecule.A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-4B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-4C. Statement-1 is true, Statement-2 is false.D. Statement-1 is false, Statement-2 is true.
Answer» Correct Answer - a Statement 2 is the correct explanation for Statement 1.

Discussion

38.	L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well. In the homonuclear molecule3 which of the following sets of M.O. orbitals are degenerate ?A. `sigma_(1s)and sigma_(1s)^()`B. `pi_(2px)and pi_(2py)`C. `pi_(2px)and sigma_(2pz)`D. `sigma_(2pz)and pi_(2px)^()`
Answer» Correct Answer - B `pi_(2px) and pi_(2py)` M.O. orbitals are degenerate.

Discussion

39.	L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well. The bond order (B.O.) in `B_(2)` molecule is:
Answer» Correct Answer - B B.O. is one `B_(2)=[sigma_(1s)]^(2)[sigma_(1s)^()]^(2)[sigma_(2s)]^(2)[sigma_(2s)^()]^(2)[pi_(2px)]^(1)[pi_(2py)]^(1)`

Discussion

40.	L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well. In the formation of `N_(2)^(+)` from `N_(2),` the electron is removed from aA. `sigma`orbitalB. `pi`orbitalC. `sigma`-orbitalD. `pi`-prbital.
Answer» Correct Answer - A The electron is removed from `sigma` M.O.

Discussion

41.	L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well. Bond arder is :A. directly related to bond lengthB. inversely related to bond lengthC. incersely related to bond strengthD. never fractional.
Answer» Correct Answer - B is the correct answer.

Discussion

42.	L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well. Which of the followijng combinatinos is not allowed (assume z axis as the internuclear azis) ?A. 2s and 2sB. `2p_(x)and 2p_(x)`C. 2s and `2p_(z)`D. `2p_(y)and 2p_(y)`
Answer» Correct Answer - D `2p_(x)and 2p_(y)` atomic orbitals do not combine due to lack of symmetry.

Discussion

43.	Which of the following statements is not regarding bonding molecular orbitalsA. Bonding molecular orbitals possess less energy than combining atomic orbitalsB. Bonding molecular orbitals have low electron density between the two nucleiC. Every electron in bonding molecular electron density between the two nuclei orbitals contributes to attraction between atomsD. They are formed when the lobes of the combining atomic orbitals have same sign.
Answer» Correct Answer - B

Discussion

44.	Name the different type of bonds present in `NH_(4) Cl` after drawing its structure.
Answer» `[H-underset(H) underset(\|)overset(H)overset(\|)NtoH]^(+)Cl^(-)` . Thus , it has covalent, coordinate and ionic bonds.

Discussion

45.	In which of the following the central atom does not use `sp^(3)` - hydrid orbitals in its bonding.A. `BeF_(3)^(-)`B. `OH_(3)^(-)`C. `NH_(2)^(-)`D. `NH_(3)`
Answer» Correct Answer - A ` Be F_(3)^(-) = Be F_(2) + F^(-). Be F_(2)` involves sp hybridisation .

Discussion

46.	The number and types of bonds between two carbon atoms in calcium carbide areA. one sigma , one piB. one sigma , two piC. two sigma, one piD.
Answer» Correct Answer - B `CaC_(2)` is `Ca^(2+)underset(C^(-))overset(C^(-))\|\|\|` . Thus , it has one sigma and two po bonds.

Discussion

47.	In which of the following `p pi-d pi` bonding is observed ?A. `NO_(3)^(-)`B. `SO_(3)^(2-)`C. `BO_(3)^(3-)`D. `CO_(3)^(2-)`
Answer» Correct Answer - b Only sulphur has d-orbitals.

Discussion

48.	Which is correct statement about `sigma - and po-` molecular orbitals ? Statements are : `pi-` bonding orbitals are ungerade `pi`-antibonding orbitals are ungerade `sigma`-antibondding orbitals are geradeA. 1 onlyB. 2 and 3 onlyC. 3 onlyD. 2 only
Answer» Correct Answer - A ` sigma`-orbitals are gerade , `sigma^()` are ungerade, `pi` are ungerade whereas `pi^()` are gerade .

Discussion

49.	Which has `p_(pi) - d_(pi)` bonding ?A. `NO_(3)^(-)`B. `SO_(3)^(2-)`C. `BO_(3)^(3-)`D. `CO_(3)^(2-)`
Answer» Correct Answer - B Only `SO_(3)^(2-) has p_(pi - d_(pi)` bonding as one of the bonds involves p-orbital of O and d-orbitals of S Supplement Your Knowladge, All others involve only `p_(pi)-p_(pi)` bonding .

Discussion

50.	The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. (v) gt (iv) gt (i) gt (iii) gt (ii)B. (v) gt (i) gt (ii) gt (iii) gt (iv)C. (ii) gt (iv) gt (iii) gt (i) gt (v)D. (iv)gt (iii) gt (i ) gt (ii) gt (v)
Answer» Correct Answer - A

Discussion

Explore topic-wise InterviewSolutions in .

Statement-1 : `NH_(3)` is pyramidal in shape . Statement-2 : `SiCl_(4)` and `GaCl_(4)^(-)` are isostructural . Statement-3 : `sd^(3)` hybridisation may be possibleA. TTFB. TTTC. FTTD. TFT

`O_(2)` and `N_(2)` are respectivelyA. Diamagnetic , ParamagneticB. Paramagnetic , DiamagneticC. Both the paramagneticD. Both are diamagnetic

Molecular shape of `ClF_(3) , l_(3)^(-)` and `XeO_(3)` respectively areA. T-shape , Linear , PyramidalB. Planar , Linear , TetrahedralC. T-shape , Planar , PyramidalD. Trigonal bipyramidal , Linear , Tetrahedral

In case of `XeO_(2) F_(2)` and `XeF_(6)` , Xe is withA. Same hybridization but with different geometryB. Different hybridization with same geometryC. Different hybridization and different geometryD. Same geometry and same hybridization

The shapes of `XeO_(2)F_(2)` molecule isA. trigonal bipyramidalB. square planarC. tetrahedralD. see-saw.

Which is the correct arrangement of the molecules basexd on dipole moments ?A. `BF_(3) = NH_(3) = NF_(3)`B. `BF_(3) gt NH_(3) gt NF_(3)`C. `BF_(3) lt NH_(3) lt NF_(3)`D. `BF_(3) lt NF_(3) lt NH_(3)`

Which one of the following arrangements of molecules is correct on the basis of their dipole moments ?A. `BF_(3) gt NF_(3) NH_(3)`B. `NF_(3) gt BF_(3) gt NH_(3)`C. `NH_(3) = NF_(3) gt BF_(3)`D. `NH_(3) gt NF_(3) gt BF_(3)`

The crystal lattice of electro covalent compounds is composed ofA. AtomsB. MoleculesC. Oppositely charged ionsD. Both molecules and ions

The crystal lattice of electro covalent compounds is composed ofA. atomsB. moleculesC. oppositeoly charged ionsD. both molecules and ions.

Which is the correct arrangement of the molecules basexd on dipole moments ?A. `BF_(3) gt NF_(3) gt NH_(3)`B. `NF_(3) gt BF_(3) gt NH_(3)`C. `NH_(3) gt BF_(3) gt NF_(3)`D. `NH_(3) gt NF_(3) gt BF_(3)`

Covalent compounds have olw m.p. because :A. Covalent molecules are held by weak van der Waals forcesB. Covalent bond is less exothermicC. Covalent bond is weeker than ionic bondD. Covalent molecules have definite shapes.

Pick out the incorrect statementA. `N_2` has greater dissociation energy than `N_2^+`B. `O_2` has lower dissociation energy than `O_2^+`C. Bond length in `N_2^+` is less than in `N_2`D. Bond length in `NO^+` is less than in NO.

Which out of `NH_(3) and NF_(3)` has higher dipole ment and why ?

Although geometries of `NH_(3) and H_(2) O ` molecules are distorted tetrahedral, bond angle in water is less then that of ammonia. Discuss .

Asseration: `SeCl_(4)`, does not havea tetrahedral structure. Reason: `Se` in `SeCl_(4)` has two lone pairs.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true

Although geometries of `NH_(3)` and `H_(2)O` molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.

Bond angle in `PH_(3)` isA. Much less than `NH_(3)`B. Much less than `PF_(3)`C. More than `NH_(3)`D. More than `PF_(3)`

Which has regular tetrahedral geometary ?A. `SF_(4)`B. `BF_(4)`C. `XeF_(4)`D. `[Ni(CN)_(4)]^(2)`

The bond length between C- C bonds in `sp^2` hybridised molecule isA. 1.2 Ã…B. 1.32 Ã…C. 1.54 Ã…D. 1.4 Ã…

Is there any change in hybridisation of the `B` and `N` atom as a result of the following reaction? `BF_(3)+NH_(3)rarr F_(3)B.NH_(3)`

Wrtie the state of hybridisation of boron in `BF_(3)`.

Is there any change in the hybridisation of B and N atoms as a result of the reaction , `BF_(3) + NH_(3) to F_(3) B. NH_(3)` ?

The correct sequence of decrease in the bond angles of the following hybrides isA. `NH_(3) gt PH_(3) gt AsH_(3) gt SbH_(3)`B. `NH_(3) gt AsH_(3) gt PH_(3) gt SbH_(3)`C. `SbH_(3) gt AsH_(3) gt PH_(3) gt NH_(3)`D. `PH_(3) gt NH_(3) gt AsH_(3) gt SbH_(3)`

Arrange the molecules `H_(2), O_(2), F_(2) and N_(2)` in order of increasing bond lengths.

The magnetic moment of `KO_(2)` at room temperature is …… BM.A. 1.41B. 1.73C. 2.23D. 2.64

One the basic of ground electronic configuration, arrange the following molecules in the oder of increasing `O -O` bond lengths `KO_(2), O_(2) ,O_(2)[AsF_(6)]` .

Arrange the following compounds in the increasing order of bond length of O-O bond `O_(2), O_(2) [AsF_(6)], KO_(2)` Explain on the basis of ground state electronic of dioxygen in there molecules .

Explain how the valence bond theory accounts for (i) a carbon-carbon double bond (C = C ) (ii) a carbon-carbon triple bond `(C-=C)`

Name the different type of bonds present in `NH_(4) Cl` after drawing its structure.

In which of the following the central atom does not use `sp^(3)` - hydrid orbitals in its bonding.A. `BeF_(3)^(-)`B. `OH_(3)^(-)`C. `NH_(2)^(-)`D. `NH_(3)`

The number and types of bonds between two carbon atoms in calcium carbide areA. one sigma , one piB. one sigma , two piC. two sigma, one piD.

In which of the following `p pi-d pi` bonding is observed ?A. `NO_(3)^(-)`B. `SO_(3)^(2-)`C. `BO_(3)^(3-)`D. `CO_(3)^(2-)`

Which is correct statement about `sigma - and po-` molecular orbitals ? Statements are : `pi-` bonding orbitals are ungerade `pi`-antibonding orbitals are ungerade `sigma`-antibondding orbitals are geradeA. 1 onlyB. 2 and 3 onlyC. 3 onlyD. 2 only

Which has `p_(pi) - d_(pi)` bonding ?A. `NO_(3)^(-)`B. `SO_(3)^(2-)`C. `BO_(3)^(3-)`D. `CO_(3)^(2-)`

The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. (v) gt (iv) gt (i) gt (iii) gt (ii)B. (v) gt (i) gt (ii) gt (iii) gt (iv)C. (ii) gt (iv) gt (iii) gt (i) gt (v)D. (iv)gt (iii) gt (i ) gt (ii) gt (v)