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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 901. |
Between `CaCl_(2)` and KCl, which has a stronger ionic bond? Why? |
| Answer» `Ca^(+2)` ion is smaller than `K^(+)` ion. Greater the charge on cation, the greater is the effective nuclear charge and thus smaller is the size of the cation. Hence, | |
| 902. |
The bond angle in ` PH_3 ` is :A. much lesser than `NH_3`B. equal to `NH_3`C. much greater than `NH_3`D. slightly more than `NH_3` |
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Answer» Correct Answer - A Bond angles diecrease on moving down the group for similar compounds having central atom belonging to same group i.e., ` NH_(3) lt pH_3 lt AsH_3 lt SbH_3` . |
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| 903. |
How many unpaired of electron are present in ` O_2^-` |
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Answer» `O_2^(-) : sigma 1s^2 , sigma^**1 s^2 , sigma2 s^2 , sigma^**2s^2, sigma2p_x^2 underset ([(2pi2p_z^1),(pi2p_y^1)][(pi**2p_y^1),(pi**2p_z^1)]` ` O_2^(-)` has (1) unpaired electron in its antibonding molecualr orbital |
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| 904. |
The correct order of dipole moment is :A. ` CH_4 lt NF_3 lt NH_3 lt H_2O`B. `NF_3 lt CH_4 lt nH_3 lt H_2O`C. `NH_3lt NF_3 lt CH_4 lt H_2O`D. `H_2O lt NH_3 lt NF_3 lt CH_4` |
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Answer» Correct Answer - A Dipole moment of `CH_4 =0` |
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| 905. |
According to molecular orbital theory which of the following is correct `:`A. `LUMO` level for `C_(2)` molecule is a `sigma 2p` orbitalB. In `C_(2)` molecule both the bonds are `pi` bondsC. In `C_(2)^(2-)` ion there is one `sigma `and two `pi` bondsD. all the above are correct. |
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Answer» Correct Answer - 4 For `C_(2)` the electronic configuration is `=sigma1S^(2),sigma^(**)1S^(2),sigma2S^(2),sigma^(**)2S^(2),pi2P_(x)^(2),pi2P_(y)^(2),sigma2P_(z)^(@)` Hence the result follows. |
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| 906. |
Which of the following is ionic solid `:`A. `XeF_(6)(s)`B. `PBr_(5)(s)`C. `CaC_(2)(s)`D. All of these |
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Answer» Correct Answer - 4 All are ionic solids `XeF_(6)(S)` consists `XeF_(5)^(+)&F^(-)` `PBr_(5)(s)......PBr_(4)^(+)&Br^(-)` `CaC_(2)(s).......Ca^(++)&C_(2)^(--)` |
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| 907. |
In ethene, the carbon-carbon bond distance isA. `154 p m`B. `120 p m`C. `134 p m`D. `142 p m` |
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Answer» Correct Answer - C The order of carbon-carbon bond distance is `underset((154 p m))underset("ethane")underset(1n)(C-C) gt underset((134 p m))underset("ethene")underset(1n)(C-C) gt underset((120 p m))underset("ethyne")underset(1n)(C-C)` |
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| 908. |
How many `pi`-bonds are present in ` C_2 (CN)_4` ? |
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Answer» ` sp^3 , sp^2`on all foure carbon of ` CN` ` :. C_2 (CN)_4` has `9pi`-bonds. |
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| 909. |
Carbon atoms in `C_2(CN)_4` are :A. `sp`-hybridsedB. `sp^2 -`hybrdisedC. `sp` and` sp^2 `-hybridesedD. `sp, sp^2` and `sp^3` -hubridesed |
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Answer» Correct Answer - C `C-(CN)_4` is `N equivC-underset (N-=C-C-C-=N)underset(||)(C)-C equivN` ` C=C` is `sp^2` -hybrideised and ` underset ("sp-hybridised" ) (C=N) is `. |
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| 910. |
Many ions, particulary anions, are polyatomic. The atoms in these ions are held together byA. electrovalent bondsB. hydrogen bondsC. covalent bondsD. metallic bonds |
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Answer» Correct Answer - C The example of polyatomic anions mainly include oxoaonins obtained from the molecules of oxoacids such as carbonic acid `(H_2CO_3)`, sulphuric acid `(H_2SO_4)`, and phosphoric acid `(H_3PO_4)`. They are carbonate ion `(CO_3^(2-))`, nitrate ion `(NO_3^(-))`, sulphate ion `(SO_4^(2-))`, and phosphate ion `(PO_4^(2-))`, respectively. |
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| 911. |
The bond between two identical non-metal atoms has a pair of electrons:A. Dissimilar shared between the twoB. By complete transfer from one atom to otherC. In a similar spin conditionD. Equally shared in between the two |
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Answer» Correct Answer - D Bond between two identical non-metals share the pair of electrons equally between them, e.g. : `F_(2),O_(2),N_(2)` |
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| 912. |
Which are true statements among the following ?A. `,13`B. ` 1,2,5`C. ` 1,35`D. ` 1,2,4` |
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Answer» Correct Answer - B These are facts. |
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| 913. |
According to molecular orbital theory, which of the following will not be a viable molecule?A. `H_(2)^(+)`B. `Be_(2)`C. `B_(2)`D. `C_(2)` |
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Answer» Correct Answer - B `Be_(2) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))` B.O. ` = 1/2 (N_(b)-N_(a)) = 1/2 xx (4 - 4) = 0` Since B.O. is zero , the molecule does not exist. |
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| 914. |
The bond between two identical non-metal atoms has a pair of electrons:A. unequally shared between the twoB. transferred fully from one atom to anotherC. with identical spinsD. equally shared between them |
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Answer» Correct Answer - d |
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| 915. |
The strongest covalent bond is formed by the overlap ofA. s and p orbitalsB. s and s orbitalsC. p and d orbitalsD. p and p orbitals |
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Answer» Correct Answer - D Because third overlap leads to the formation of a `pi` bond and `p` orbitals are more directional than s orbitals. Note that we are considering the axial overlap of p orbitals. |
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| 916. |
Which of the following does not exist on the basis of molecule orbital theory ?A. `H_(2)^(+)`B. `He_(2)^(+)`C. `He_(2)`D. `Li_(2)` |
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Answer» Correct Answer - C Helium molecule does not exist as bond order of `He_(2)=0` |
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| 917. |
Which of the following species does not exist under normal condition ?A. `Be_2^+`B. `Be_2`C. `B_2`D. `Li_2` |
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Answer» Correct Answer - B Key Idea Molecules with zero bond order , do not exist. According to molecular orbital theory, (a)`Be_2^+`(4+4-1=7) `=sigma1s^2 , overset***1s^2,sigma2s^2 , overset***2s^1` Bond order (BO) `=(4-3)/2=0.5` (b)`Be_2^+`(4+4=8) `=sigma1s^2 , overset***1s^2,sigma2s^2 , overset***2s^2` Bond order (BO) `=(4-4)/2=0` (c )`B_2^+`(5+5=10) `=sigma1s^2 , overset***1s^2,sigma2s^2 , overset***2s^1,pi2p_x^1~~pi2p_y^1` Bond order (BO) `=(6-4)/2=1` (d)`Li_2^+`(3+3=6) `=sigma1s^2 , overset***1s^2,sigma2s^2` Bond order (BO) `=(4-2)/2=1` Thus, `Be_2` does not exist under normal conditions. |
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| 918. |
The bond between two identical nonmetal atoms has a pair of electronsA. with identical spinsB. transferred fully from one atom to anotherC. equally shared between themD. unequally shared between the two |
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Answer» Correct Answer - C When the atoms are alike, as in the case of the `H-H` bond of `H_2`, the bonding electrons are shared equally. That is, the electrons spend the same amount of time in the vicnity of each atom. |
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| 919. |
A molecule which cannot exist theoretcally is :A. `SF_4`B. `PF_2`C. `OF_4`D. `O_2F_2` |
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Answer» Correct Answer - C Oxygen cannot expaond its octet because of no-availability of d-orbitals. |
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| 920. |
Covelant radius of `Li`is ` 123 pm` .The crystal radius of Li will be:A. ` gt 123pm`B. `lt 123 pm`C. ` = 123 pm`D. ` = (123 ) /2 pm` |
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Answer» Correct Answer - A Covalent radius are always lesser than crystal radius as former involves overlapping region. |
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| 921. |
Most covalent bonds involve the sharing of __________ electrons. (i) three (ii) two (iii) four (iv) sixA. (i), (ii), (iii), (iv)B. (ii), (iii), (iv)C. (i), (ii), (iii)D. (ii), (iii) |
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Answer» Correct Answer - B Most covalent bonds involve the sharing of one, two, or three pairs of electrons. Two atoms form a single covalent bond when they share one pair of electrons, a double covalent bond when they share two electron pairs, and a triple covalent bond when they share three electron pairs. These are usually called simply single, double and triple bonds. Covalent bonds that involve sharing of one and three electrons are known, but are relatively rare. |
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| 922. |
The correct roder o fincreasing `C-O` bond lengths in `CO, CO_3^(2-)` and ` CO_2` is :A. `CO_3^(2-) gt CO_2 gt CO`B. `CO_2 gt CO_3^(2-) gt CO`C. `CO gt CO_3^(2-) gt CO_2`D. `CO gt CO_2 gt CO_3^(2-)` |
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Answer» Correct Answer - D Bond order for` CO,CO_2` and `CO_3^(2-)` are `3,2` and `1.33` . Higher is bond order lesser in bond length. Also `C` is `CO_3^(2-)` is ` sp^2`-hybridsed , in ` CO_2` sp-hybridized . Thus more is s-character , more is overlapping shorter will be bond . |
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| 923. |
According to the valence bond theory, when a covalent bond is formed between two reacting atoms, the potential energy of the system becomesA. negativeB. positiveC. minimumD. maximum |
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Answer» Correct Answer - C When covalent bond is formed, the magnitude of attractive forces becomes equal to that of repulsive forces resulting in minimum potential energy. |
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| 924. |
A covalent bond results from the sharing of electrons between two atoms ofA. metallic elementsB. nonmetallic elementsC. metalloid elementsD. zero or relatively small electronegativity difference |
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Answer» Correct Answer - D Ionic bonding cannot result because electronegativity is not great enough for electron transfer to take place. |
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| 925. |
According to valence bond theory, sharing of electrons during the formation of covalent bond results from the ____________of orbitals from two reacting atomsA. additionB. substractionC. both (1) and (2)D. overlap |
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Answer» Correct Answer - D The basic idea of the valence bond `(VB)` theory which describes how bonding occurs is that atomic orbitals must overlap for electrons to be shared. Valence bond theory accounts (at least qualitatively) for the stability of the covalent bond in terms of overlapping atomic orbitals. |
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| 926. |
Among `NO_4^(-)(I),AsO_3^(3-) (II),CO_3^(2-) (III) ClO_3^(-) (IV) and SO_3^(2-) (V)`. The multiplanar species areA. II, IV, VB. III, IVC. I, II, VD. II, III, IV |
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Answer» Correct Answer - A Among the given species, `AsO_3^(3-), ClO_3^(3-)` and `SO_3^(2-)` have `sp^3` hybridised central atom. Hence they have pyramidal shapes and are therefore multiplanar. |
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| 927. |
The equilateral shape hasA. sp-hybridisationB. `sp^2`- hybridisationC. `sp^3`-hybridisationD. `sp^3d`-hybridisation |
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Answer» Correct Answer - B `120^@` angle |
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| 928. |
What is the valency of carbon in `CO_3^(2-)` ?A. 2B. 3C. 4D. `-3` |
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Answer» Correct Answer - C Carbon is tetra covalent in its compounds |
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| 929. |
The given structures I, II and III of carbonate ion represent A. hybrid structuresB. isomeric structuresC. canonical structuresD. dipole structures. |
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Answer» Correct Answer - C The structures represent canonical or resonating structures of carbonate ion. |
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| 930. |
The carbon monoxide molecule may be represented by the following structures exceptA. B. C. D. |
| Answer» In structure (B) `overset(+)(C)-=underset(ddot)overset(-)O:` oxygen atom has 10 electrons in the valence shell, which is not possible as oxygen can not expand its octet. | |
| 931. |
The number of `sp^2-s` sigma bonds in benzene areA. 3B. 6C. 12D. none |
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Answer» Correct Answer - B All the C-atoms in benzene molecule are sp hybridised i.e., they have sp-sp overlap. |
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| 932. |
Which of the following molecules does not show any resonating structures?A. `NH_(3)`B. `CO_(3)^(2-)`C. `O_(3)`D. `SO_(3)` |
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Answer» Correct Answer - A `NH_(3)` does not show resonating structure due to the absence of double bond. |
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| 933. |
The canonical or resonating structures of a molecule required to describe the structure of a molecule follow which of the following rules ?A. The relative position of all atoms can differ.B. The same number of unpaired and paired electrons in all structures.C. The energy of each structure is different.D. Like charges are present on adjacent atoms. |
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Answer» Correct Answer - B Canonical structures differ only in the position of electrons not in number of paired and unpaired electrons. |
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| 934. |
If the bond length of CO bond in carbon monoxide is `1.128 Å`, then what is the value of CO bond length in `Fe (CO)_(5)` ?A. 1.15ÅB. 1.128ÅC. 1.72ÅD. 1.118Å |
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Answer» Correct Answer - A Due to synergic bond formation between metal and CO, the bond order of CO decreases. |
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| 935. |
The ion that is isoelectronic with `CO` isA. `CN^-`B. `O_2^-`C. `N_2^+`D. `O_2^+` |
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Answer» Correct Answer - A Both CO (6+8 = 14 electrons) and CN (6+7+1=14 electrons) have same number of electrons |
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| 936. |
In the resonating structures of of benzene, the number of `sigma and pi` bonds are:A. `3pi and 12sigma `B. `3sigma and 12pi`C. `6pi and 6sigma`D. `12pi and 12sigma` |
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Answer» Correct Answer - A There are 12 sigma bonds and three `pi`-bonds |
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| 937. |
The decreasing order of dipole moments of the molecules `HF,H_(2)O,BeF_(2),NF_(3)` isA. `HFgtH_(2)OgtBeF_(2)gtNF_(3)`B. `H_(2)OgtHFgtNF_(3)gtBeF_(2)`C. `BeF_(2)gtNF_(3)gtHFgtH_(2)O`D. `NF_(3)gtBeF_(2)gtH_(2)OgtHF` |
| Answer» `{:(H_(2)O,gt,HF,gt,NF_(3),gt,BeF_(2)),(1.88 D,,1.78 D,,0.23 D,,0D):}` | |
| 938. |
Which of the following structures is/are correct? A. I, II and IVB. II, III and IVC. II and IIID. I, II, III and IV |
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Answer» (d) I. Represents Lewis-dot structure of `CCl_(4)`. II. Represents Lewis -dot structure of `Cl_(2)`. III. Represents Lewis -dot structure of `CO_(2)`. IV. Represents Lewis-dot structure of `H_(2)O`. |
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| 939. |
Born-Haber cycle is used to determineA. ElectronegativityB. Lattice energyC. BothD. None |
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Answer» Correct Answer - B Born-Haber cycle is used to determine electron affinity and lattice energy |
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| 940. |
The type of bonds present in sulphuric anhydrideA. `3sigma` and three `p pi-dpi`B. `3sigma` one `p pi-p pi` and two `p pi -d pi`C. `2sigma` three `p pi-d pi`D. `2sigma ` and two `p pi-dpi` |
| Answer» Correct Answer - B | |
| 941. |
The shape of `SO_4^(2-)` ion isA. Square planarB. tetrahedralC. trigonal bipyramidalD. Hexagonal |
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Answer» Correct Answer - B `SO_(4)^(2-)` ion is tetrahderal since hybridization of S is `sp^(3)`. |
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| 942. |
The number of `(ppi-dpi)` `pi`-bonds present in `XeO_(3)` and `XeO_(4)` respectively areA. 3,4B. 4,2C. 2,3D. 3,2 |
| Answer» Correct Answer - A | |
| 943. |
A 5.82 g silver coin is dissolved in nitric acid. When sodium chloride is added to the solution, all the silver gets precipitated as AgCl. The mass of the precipitated silver chloride is 7.2 g. The percentage of silver in the coin is :A. `98%`B. `93.1%`C. `86%`D. `82%` |
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Answer» Correct Answer - B Fraction of Ag in AgCl=`107.9/143.3=0.753` weight of Ag in 7.20 g AgCl = 0.753 x 7.20 g = 5.42 g Ag Hence the 5.82 g coin contains 5.42 g Ag =0 Fraction of Ag in coin =5.42 g/5.82 g =0.931 = 93.1% Ag |
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| 944. |
Which of the following has `ppi-dpi` bonding?A. `NO_3^(-)`B. `SO_3^(2-)`C. `BO_3^(3-)`D. `CO_3^(2-)` |
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Answer» Correct Answer - B N, B, and C are the elements of second period. These elements cannot form `ppi-dpi` bonds as they do not possess `d-`orbitals in their valence shell. On the other hand, S, an element of third period has, `3d` orbitals and, hence, can form `ppi-dpi` bonds with oxygen. In this bonding, the `d-`orbitals of S overlap with the `p-`orbitals of the O atom. |
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| 945. |
Bond order of nitric oxide isA. 1B. 2.5C. 2D. 1.5 |
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Answer» Correct Answer - B E.C. of NO = KK`[sigma(2s)]^(2)[sigma^**(2s)]^2 [sigma(2p_z)]^2 [pi(2p_x)]^2 [pi(2p_y)]^2 [pi^**(2p_x)]^1` `therefore` Bond order =`1/2(8-3)=5/2=2.5` |
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| 946. |
Among the following molecules : `SO_(2),SF_(4) ,CIF_(3) ,BrF_(5)` , and `XeF_(4)` , which of the following shapes does not describe any of the molecules mentioned ?A. BentB. trigonal bipyramidalC. See-sawD. T-Shape |
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Answer» Correct Answer - B Because `SO_(2) to ` bent `SF_(4) to `See -saw `ClF_(3) to `T-Shape `BrF_(5) to ` Square pyramidal `XeF_(4) to ` square planar. |
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| 947. |
Which species has the maximum number of lone pair of electrons on the central atom ?A. ` [ClO_3]^(-)`B. ` XeF_4`C. ` SF_4`D. `[I_3]^(-)` |
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Answer» Correct Answer - D `I_3^(-), XeF_(4) SF_4` and `ClO_3^(-)` have 3, 2, 1,1 lone pair of electrons respectively . |
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| 948. |
Discuss the shape of `H_(3)O^(+)` using VSEPR model .A. LinearB. AngularC. Trigonal planarD. Trigonal pyramidal |
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Answer» Correct Answer - D `H_(3)O^(+)` has `sp^(3)` hybridization and its shape is triangular |
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| 949. |
The number of lone pairs of electrons present on the central atom of `CIF_3` is |
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Answer» Correct Answer - C Cl (Ground state) `=3s^2 3p_x^2 3p_y^2 3p_z^1` excited state `3s^2 3p_x^2 3p_y^1 3p_z^1 3d^1`. It is `sp^3d` hybridized (trigonal bipyramidal). It has T-shape with two lone pairs. |
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| 950. |
Which of the following molecules has one lone pair of electrons on the central atomA. `H_(2)O`B. `NH_3`C. `CH_(4)`D. `PCl_(5)` |
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Answer» Correct Answer - B `NH_(3)` molecule has one lone pair of electrons on the central atom i.e., nitrogen |
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