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6251.

Element 'X' has twelve protons in its nucleus. To which group of the periodic table it will belong?

Answer»

1
2
6
8

Answer :B
6252.

Element X forms a chloride with the formula XCl_2, which is a solid with a high melting point. Xwould most likely be in the same group of the Periodic Table as

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NA

Solution :The element X forms a chloride `XCl_2` , therefore, its VALENCY is 2. Out of the given elements Na, Mg,Al and Si, the element of valency 2 is Mg. So, X would most likely be in the same group of the Periodic Table as Mg.
6253.

Element X forms a chloride with the formula XCl_(2), which is a solid with a high melting point. X would most likely be in the same group of the periodic table as ….

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Na
Mg
Al

6254.

Element X forms a chloride with the formula XCl which is a solid with a high melting point. X world most likely be in the same group of the Periodic Table as

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Na
Mg
Al
Si

Answer :B
6255.

Element X forms a chloride with the formula XCI_2, which is a solid with a high melting point. X would most likely be in the same group of the Periodic Table as (a) Na (b) Mg (c) Al (d) Si

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SOLUTION :As X forms the CHLORIDE with the formula `XCI_2`, it indicates that the element X is divalent. Further `XCI_2` is a solid with high melting point, it SHOWS that the chloride is ionic in nature.
That further means that the element X is METALLIC in nature, such that is gives away electrons to chlorine to form the ionic chloride. These conditions are fulfilled if X is taken as Mg. Thus, OPTION (b) is correct.
6256.

Element X forms a chloride with the formula XCI_2 which is a solid with a high melting point. X would most likely be in the same group of the periodic table as

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Na
Mg
AI
Si

Answer :B
6257.

Element X forms a chloride with formula XCI_2, which is a solid with a high melting point. X would most likely be in the same group of the Periodic Table as

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`NA`
`MG`
`AI`
`Si`

SOLUTION :`XCI_2` indicates that it has a valency EQUAL to 2. Magnesium and other elements in this group have the valency equal to 2.
6258.

Element with atomic number 18 belongs to

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2ND period, 8th group 
3RD period, 8th group 
2nd period, 18TH group
3rd period, 18th group

ANSWER :D
6259.

Element with atomic number 16 is _____

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ANSWER :SULPHUR
6260.

Element with atomic mass 14 is _____

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ANSWER :NITROGEN
6261.

Element which has most negative electron gain enthalpy is

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F
O
Cl
S

Answer :C
6262.

Elementare arranged in the ___________ order of their atomic numberto the form modern periodic table.

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SOLUTION :INCREASING
6263.

Element 'A' has Electronic confguration 2,7 'B' has configuration2,8,6, 'C' has configuration 2,8,8 while 'D' has 2,8,7. Which element will show similar chemical properties?

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A and C
A and D
B and C
B and D

Solution :The elements having same number of valence electron will show SIMILAR CHEMICAL propertics. Elements A and D will show similar chemical properties.
6264.

Electrovalentcompounds are usually

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solids with low melting POINTS
solids with HIGH melting points
volatile LIQUIDS
organic COMPOUNDS

ANSWER :b
6265.

Electroplating is one of the practical utilities of electrolysis .Copper can be coated on an iron bangle by this process. Which is the electrolyte used here ?

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ANSWER :COPPER SULPHATE SOLUTION
6266.

Electroplating is one of the practical utilities of electrolysis .Copper can be coated on an iron bangle by this process. Write down any other practical utility of electrolysis.

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ANSWER :* PRODUCTION of METALS.*Production of NON metals.*REFINING of mtals.
6267.

Electropositive atoms tend to form

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NEGATIVE IONS
positive ions
covalent bonds
METALLIC bonds

Solution :Electropositively is the TENDENCY of an atom to lose electron
6268.

Electroplating is one of the practical utilities of electrolysis .Copper can be coated on an iron bangle by this process. Which metal is connected to negative terminal of the battery in this process ?

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ANSWER :IRON
6269.

electrons present in theoutermost shell of an atom ___________

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SOLUTION :DECREASES
6270.

Electrons occupy the degenerate orbitals with par allel spins. How can you justify this statement with respect to stability

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Solution :Sommerfeld suggested that the subenergy LEVELS or subshells associated with each main energy level are RESPONSIBLE for the FINE structure of hydrogen spec- trum. These subenergy levels or subshells EXIST due to the difference in energies of electrons revolving in different ELLIPTICAL orbits belonging to the same main energy level
6271.

Electrons are filled in K, L and M shells in the elements of the third period.

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ANSWER :TRUE
6272.

Electrons are added to an element Y . What charge will Y have after the addition of electrons ?

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SOLUTION :NEGATIVE
6273.

Electrons are added to an element Y . Is Y oxidised or reduced ?

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SOLUTION :REDUCED
6274.

Electronic configuration of Mg is _________

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(2, 8, 4)
(2, 8, 1)
(2, 8, 3)
(2, 8, 2)

SOLUTION : (2, 8, 2)
6275.

Electronegativity of fluorine is greater than that of chlorine.

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ANSWER :1
6276.

Electronegativity of F is larger than that of Cl but electron gain enthalpy of Cl is larger than of F.(T/F)

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ANSWER :TRUE
6277.

"Electronegativity is the case of gaining electrons". (a) Which type of elements will have high electronegativity ? (b) How does electronegativity change as we move (i) across a period (ii) down a group ?

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SOLUTION :(a) Non-metals
(B) (i) INCREASES
(II) DECREASES
6278.

Electron deficient impurities make which type of semiconductor

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<P>p type
n type
Both
No SEMICONDUCTOR is FORMED by doping

Answer :A
6279.

Electron affinity is not a periodicproperty .

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SOLUTION :CORRECT Statement : ELECTRON affinity is a PERIODICPROPERTY .
6280.

Electron affinity is measured in …………… .

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`KJ^(-)`
`MOIL|^(-)`
`KJ//mol`
`KJ//mol^(2)`

ANSWER :C
6281.

Electromagnetic separation is employed for the concentration of those ores in which

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(a) the ORE is MAGNETIC
the GANGUE is magnetic
both the ore and the gangue are magnetic
either the ore or the gangue is magnetic

Answer :D
6282.

Electromagnets , springsand anchorsare preparedfrom ______________.

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SOLUTION :wroght IRON
6283.

Electromagents are used to concentrate _____ ores.

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ANSWER :MAGNETIC
6284.

Electrolyte used in Hall's process ………………..

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PURE alumina +molten CRYOLITE + fluorspar
Pure alumina + molten BAUXITE + fluorspar
Pure bauxite + molten cryolite +fluorspar
Pure bauxite + molten Haematite +fluorspar

Answer :A
6285.

Electrolyte reduction of alumina into aluminium is …………… .

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HALL's PROCESS
Alumina THERMIC process
Baeyer's process

Answer :A
6286.

Electrolysis of water in presence of Sulphuric acid to yield Hydrogen and Oxygen is what kind of reaction?

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Decomposition
Combination
Oxidation
Displacement

Answer :A
6287.

Electrolysis of water is a decomposition reaction. The mole ratio of hydrogen and oxygen gases liberated during electrolysis of water is

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`1:1`
`2:1`
`4:1`
`1:2`

Solution :HYDROGEN and oxygen gases are produced in the molar RATIO of `2:1` on electrolysis of water
`2H_(2)Ooverset("Electrolysis")(to)2H_(2)+O_(2)`
6288.

Electrolysis of molten magnesium chloride results in the formation of 0.4 g magnesium. Calculate the volume of chlorine liberated during the reaction at STP. When an electrolytic cell consisting of molten AlCl_(3) and molten NaCl are connected in series with the above cell, calculate the amount of aluminium and sodium deposited at cathode.

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Solution :`MgCl_(2) RARR MG^(+2) + 2C^(-)`
For the deposition for 12 g of Mg (equivalent weight of magnesium) one faraday is required
`:.` 12 g requires 1 faraday
0.4 g requires ?
`= (0.14)/(12) = 0.03` Faraday
1 Faraday GIVES 11.2 L of `Cl_(2)` at STP, therefore, 0.03 faraday gives ?
`= 0.336 1 L " of " Cl_(2)` at STP
1 faraday required to deposit 9 g of Al
`:.` 0.03 faraday required to deposit ? = 0.27 g
1 faraday required to deposit 23 g of Na
`:.` 0.03 faraday required to deposit ?
`= 0.03 xx 23 = 0.69 g`
6289.

Electrolysis of molten lead bromide is considered as redox reaction . Give reason .

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SOLUTION :Because `PB^(2+)` is REDUCED and `BR^(-)` is oxidised .
6290.

Electrolysis of aqueous CuSO_(4) with inert electrodes gives ______

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Cu at CATHODE, anode GETS dissolved
Cu at cathode, `O_(2)` at anode
`O_(2)` at anode, `H_(2)` at cathode
`O_(2)` at anode, cathode gets dissolved

Answer :B
6291.

Electrolysis is type of …….reaction

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SOLUTION :DECOMPOSITION REACTION
6292.

Electrolysis is a reaction caused of

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LIGHT
HEAT
ELECTRICITY
both heat and light

ANSWER :C
6293.

Electrolysis brings about a chemical change

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ANSWER :TRUE
6294.

Electro refining which is based on phenomenon of Electrolysis where

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impure metal is MADE ANODE and PURE metal is CATHODE
impure metal is cathode and pure metal is anode
pure metal makes both anode and cathode
none of the above

Solution : impure metal is made anode and pure metal is cathode
6295.

Electrical wires have a coating of an insulating material. The material, generally used is

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Sulphur
GRAPHITE
PVC
All can be used

Solution : Graphite conducts electricity and sulphur cannot be COATED on ELECTRICAL WIRES because of reactionbetween CU and S
6296.

Give reasons for the following : (i) School bells are made up of metals. (ii) Electrical wires are made up of copper.

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SOLUTION :It is because COPPER is GOOD CONDUCTOR of ELECTRICITY.
6297.

Eka boron is known as Germanium.

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SOLUTION :EKA - BORON is KNOWN asScandium.
6298.

Efflorescence is shown by

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BLEACHING powder
baking soda
washing soda
plaster of Paris

Answer :C
6299.

Each question contain statement-1 (Assertion) and statement-2 (Reason) Examine the statements carefully and work the correct answer according to the instruction given below : Statement - 1 : Equivalence point comes first before end point. Statement - 2 : Equivalence point cannot be obtained even by graphical method.

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If both the STATEMENTS are TRUE and Statement-2 is the CORRECT EXPLANATION of the statement-1
If both the statements are True and statement-2 is not the correct explanation of statement-1
If statement-1 is true and statement-2 is FALSE.
If statement-1 is false and statement-2 is True.

Answer :D
6300.

Each question contain statement-1 (Assertion) and statement-2 (Reason) Examine the statements carefully and work the correct answer according to the instruction given below : Statement - 1 : Cr_(2)O_(7)^(2-) is a self indicator. Statement - 2 : MnO_(4)^(-) acts as a self indicator.

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If both the STATEMENTS are TRUE and Statement-2 is the CORRECT EXPLANATION of the statement-1
If both the statements are True and statement-2 is not the correct explanation of statement-1
If statement-1 is true and statement-2 is FALSE.
If statement-1 is false and statement-2 is True.

Answer :D