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7001.

Carbon tetrachloride is not a good conductor of electricity give reason to justify your answer . .

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Solution :Carbon tetra CHLORIDE is a COVALENT compound and covalent compounds have only ATOMS and not IONS. Hence due to the ABSENCE of ions, there are generally bad conductors of electricity.
7002.

"Carbon tetrachloride is not a good conductor of electricity." Give reason to justify this statement.

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SOLUTION :Carbon tetrachloride is a COVALENT compound. Such COMPOUNDS do not produce ions.
7003.

Carbon tetrachloride dissolves in water, but sodium chloride does not.

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ANSWER :F
7004.

Carbon reduction process is used to obtain

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iron
sodium
calcium
zinc

Answer :A::D
7005.

Carbon monoxide is_______ oxide.

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amphotenic
ACIDIC
basic
NEUTRAL

SOLUTION :neutral
7006.

Carbonmonoxideis ________.

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SOLUTION :HETERO diatomicmolecule
7007.

Carbon monoxide and water vapor react to give Co_(2) and H_(2) in a vessel of 2 L capacity at 1090 K . Equilibrium is established and the number of moles of various components is found to be 0.8,0.6,0.4 and 1.2 mol , respectively. Calculate K_(c) value. 1.2 mol by increasing the concentration of CO_(2) at the equilibrium , find the number of moles of CO_(2) to be added to the reaction mixture at the same temperature.

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SOLUTION :(i) expression for EQUILIBRIUM constant
(ii) 1.5 (iii) balanced chemical reaction

(IV) calculation of equilibrium contant(v) calculation of composition of equilibrium mixture with CHANGE in concentration of CO
7008.

Carbon monoxide and water vapour react to give CO_(2) and H_(2) in a vessel of 2 L capacity at 1090K. Equilibriumis established and the number of moles of various components is found to be 0.8, 0.6, 0.4 and 1.02 respectively. Calculate K_(c) value. If the concentration of CO has to be increased to 1.2 mol by increasing the concentration of CO_(2) at the equilibrium , find the number of moles of CO_(2) to be added to the reaction mixture at the same temperature.

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Solution :`{:(CO+H_(2)O hArr CO_(2) + H_(2)),(0.8""0.6""0.4""1.2):}`
`K_(c)=(0.4xx1.2)/(0.8xx0.6)=1`
but 'a' moles of `CO_(2)` is added at EQUILIBRIUM . The new number of moles of CO is 1.2 SHOWING an INCREASE by 0.4 mol.
After the addition of 'a' moles of `CO_(2)` , balanced reaction takes PLACES :
`{:(CO+ H_(2)O"" hArr ""CO_(2) ""+ ""H_(2)),((0.8+0.4)(0.6+0.4)" "(0.4+a-0.4)(1.2-0.4)),(1.2""1.0""a""0.8):}`
`K_(c)=((0.6+0.4)(0.8+0.4))/((0.4+a-0.4)(1.2-0.4))=(1xx1.2)/(axx0.8)=1`
`implies a=(1.2)/(0.8)=1.5`
7009.

Carbon is a versatile element. Justify.

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Solution :The enormous existence of carbon in numerous forms is attributed to two of its properties:
TETRAVALENCY
CATENATION
Tetravalency: Carbon forms covalent compounds by sharing electrons and these compounds are very stable as the bonds INVOLVING carbon are very STRONG DUE to the smaller size of carbon atom, which enables to hold the shared pair of electrons tightly.
Catenation: One atom of carbon can bond with other carbon atoms, this phenomenon is also known as self-linking property.
7010.

Carbon has the unique ability to form bonds with other atoms of carbon.

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SOLUTION :TRUE - This PROPERTY is CALLED CATENATION.
7011.

Carbon has the unique property to form bonds with other atoms of carbon. -overset(|)(C)-underset(|)overset(|)(C)-overset(|)(C)- (i) Name the characteristic property of carbon as depicted in the fig. A (ii) Give reason for this unique property of carbon. (iii) Draw the structure of cyclohexane.

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SOLUTION :(i) Catenation
(ii) Carbon FORMS LARGE number of compounds due to the following :
(a) Catenation : Carbon forms bond with other atoms of carbon.
(b) Tetravalency: Carbon share four electrons with other atoms.
(iii) STRUCTURE of CYCLOHEXANE :
7012.

Carbon has the ability to form…………………bonds.

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ionic
covalent
electrovalent
dative

Answer :B
7013.

Carbon, Group (14) elementin the Periodic Table, is known to form compounds with many elements. Write an example of a compound formed with (a) Chlorine (Group 17 of Periodic Table) (b) Oxygen (Group 16 of Periodic Table)

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Solution :(a) CARBON tetrachloride `(C Cl_(4))` (b) Carbon dioxide `(CO_(2))`
7014.

Carbon (group 14), an element in the periodic table , forms compound with many elements . Write the example of a compound formed with (a) chlorine (group 17) "" (b) oxygen (group 16)

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SOLUTION :a] CARBON TETRACHLORIDE `(C CI_4)`.
b] Carbon dioxide `(CO_2)`.
7015.

Carbon forms ionic compounds by losing four electrons.

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Solution :FALSE - Carbon shares the ELECTRONS to form COVALENT compounds.
7016.

Carbon forms four covalent bonds by sharing its four valence electrons with four univalent atoms, for example, hydrogen. After the formation of four bonds, carbon attains the electronic configuration of … .

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HELIUM
NEON
ARGON
kryption

ANSWER :B
7017.

Carbon forms four covalent bonds by sharing its four valence electrons with four univalent atoms, e.g., hydrogen. After the formation of four bonds, carbon attains the electronic configuration of

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helium.
neon
argon.
krypton.

Solution :After sharing four electrons with four UNIVALENT atoms, carbon has 6 + 4 = 10 electrons. Neon also CONTAINS 10 electrons.
7018.

Carbon forms covalent bonds by sharing its four valence electrons with four univalent atoms , e.g, hydrogen . After the formation of four bonds, carbon attains the electronic configuration of

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HELIUM
NEON
ARGON
Krypton

Answer :B
7019.

Carbon forms bonds with other atoms

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by gaining electrons
by losing electrons.
by sharing electrons
none of the above

Solution :Carbon FORMS bonds with other ATOMS by sharing electrons because it requires LOT of energy to remove four electrons. Adding four electrons to carbon destabilises it. Therefore, it completes its octet by sharing electrons.
7020.

There is a large number of carbon compounds due to

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SOLUTION :CATENATION
7021.

Carbon compounds shwo isomerism and possess the characteristic property catenation.

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ANSWER :1
7022.

Carbon compounds have high melting and boiling points because of their electrovalent nature.

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SOLUTION :Carbon compounds have low MELTING and boiling POINTS because of their COVALENT nature.
7023.

Carbon circulates through air, plants, animals and soil by means of complex reactions is called kreb cycle.

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Solution :Carbon CIRCULATES through air, PLANTS, animals and soil by means of COMPLEX REACTIONS is CALLED carbon cycle.
7024.

Carbon can reduce copper oxide to copper but not CaO to Ca. Why?

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SOLUTION :C is a STRONG reducing agent and can reduce CUO as follows:
`CuO+C to Cu+CO uparrow`
Ca is much more REACTIVE than Cu and has greater AFFINITY for oxygen than C has, So, carbon cannot reduce CaO to Ca.
7025.

Carbon can reduce copper oxide but not aluminium oxide. Give reason.

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SOLUTION : Because AL is more REACTIVE than CARBON.
7026.

Carbon atoms has crystalline forms equal to :

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2
3
4
5

Answer :B
7027.

Carbon atoms form the building blocks of living organisms.

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ANSWER :1
7028.

Carbon (atomic number 6) and silicon (atomic number 14) are elements in the same group of the periodic table. Give the electronic arrangements of the carbon and silicon atoms, and state the group in which these elements, occur.

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Solution :Electronic arrangement of carbon : 2,4
Electronic arrangement of SILICON : 2, 8,4
Both C and SI belong to GROUP 14.
7029.

Carbon atoms are linked together with a ………… in saturated carbon compounds.

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SOLUTION :SINGLE BOND
7030.

Carbon atom in diamond are arranged in

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PLANAR CONFIGURATION
TETRAHEDRAL configuration
linear configuration
OCTAHEDRAL configuration

Solution : tetrahedral configuration
7031.

(i) Carbon atom does not form C^(4-) anion and C^(4+) cation. Why ? (ii) How can ethanol be converted into ethanoic acid?

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Solution :Carbon can gain four clectrons. But it would be difficult for the NUCLEUS with six protons to hold on to ten clectrons, tlhat is lour EXTRA electrons.
It can lose four electrons but it would require a large amount of energy to remove four electrons leaving belhind a carbon calion with SIX protons in its nucleus holding on to just two eleetrons.
Alkaline potassium permangnate or acidified potassium dichromate is ADDED to ETHYL alcohol. When it is heated it oxidises to FOMR ethanoie acid.
`CH_(3)- CH_(2)-OH underset("AciditK"_(2)Cr_(2)O_(7)+"Heat")overset("Basic KmnO4+Heat")rarr CH_(3)COOH`
7032.

Can zinc displace iron from a solution ofFeSO_(4) ?

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ANSWER :YES
7033.

Can you tell, Write the electronic configuration of the first four elements in this group.

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SOLUTION :
7034.

Can you tell, What similarity do you find in their electronic configuration?

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SOLUTION :The OUTERMOST SHELL contains ONE ELECTRON in all these elernents.
7035.

Can you tell, On going through the Modern Periodic table (fig 2.1) it is seen that the elements Li, Be, B, C, N, O, F and Ne belong to the period-2. Write down the electronic configuration.

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SOLUTION :
7036.

Can you tell, Is the number of valence electrons same for all these elements?

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SOLUTION :No, they are not the same.
7037.

Can you tell, Is the number of shells the same in these ?

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Solution :YES, the number of SHELLS are the same. Each ONE of this has 2 shells.
7038.

Can you tell, How many valence electrons are there in each of these elements?

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SOLUTION :Number of VALENCE ELECTRONS in each of the these ELEMENTS is 1.
7039.

Can you tell, Go through the Modem Periodic table (fig 2.1) and write the names one below the other of the elements of group 1.

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Solution :H - Hydrogen
Li - Lithium
NA - SODIUM
K - Potassium
Rb - Rubidium
Cs - Caesium
FR - Francium
are the elements of group 1.
7040.

Can you see the oil and water layers separately in both the test tubes immediately after you stop shaking them ?

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Solution :In TEST tube A, TWO SEPARATE LAYERS are seen, while in test tube B separate layers are not seen.
7041.

Can you concentrate nitric acid beyond 68% by boiling, if not then how is it concentrated ?

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Solution :No, dilute nitric acid cannot be concentrated beyond 68% by boiling. It can be concnetrated b y distilling it with concentrated sulphuric acid under reduced PRESSURE.
Pure 100% nitric acid is obtained by cooling the 98% acid when COLOURLESS crystals of pure nitric acid get SEPARATED at -`42^@C`.
7042.

Can we store a solution of sodium hydroxide in a zinc container ?

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ANSWER :YES
7043.

Can we stir silver nitrate solution with a copper spoon ? Why or why not ? Support your answer with reason.

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SOLUTION :We cannot STIR SILVER nitrate with a copper spoon. Copper being more reactive than silver, DISPLACES silver from siver nitrate, that is a reaction will take PLACE.
7044.

Can we store a solution of CuSO_(4) in a silver vessel ?

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ANSWER :No
7045.

Can wegetbackthe wood immediatelyfromcarbondioxideand water? Why ?

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SOLUTION :No,BECAUSEIT isapermanent CHANGE .
7046.

Can we cut the metals such as an iron, copper, aluminium and magnesium with a knife ?

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SOLUTION :No, we can.t CUT.
7047.

Can there be an element with atomic mass 53 or 54 in between the two elements, Chromium""_24^53Cr and Manganese ""_25^55Mn?

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Solution :It is not possible. Since their atomic NUMBERS are CONTINUOUS, there cannot be an element between CHROMIUM and MANGANESE.
7048.

Can the presence of helium gas protect the cooked rice frombeing oxidized ?

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ANSWER :YES
7049.

Can the following groups of elements be classified as Dobereiner's triad?(a)Na, Si, ci(b) Be, Mg, CaAtomic mass of Be 9, Na 23, Mg 24, Si 28, Cl 35, Ca 40Explain by giving reason.

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Solution :(a) No, because all these elements do not have similar properties although the ATOMIC mass of siliconis average of atomic masses of SODIUM (NA) and chlorine (CI).
(B)Yes, because they have similar properties and the mass of magnesium (Mg) is roughly the average of the atomic masses of Be and CA.
7050.

Can the following groups of elements be classified as Dobereiner's Triads. i] Na, Si, Cl "" ii] Be, Mg, CaAtomic mass of Be - 9. Na - 23, Mg -24, Si - 28, CI - 35, Ca - 40. Justify your answer.

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Solution :i] `Na-23, Si – 28, CI - 35`
ATOMIC mass of `Si = (23+35)/2 = 58/2 = 29`
II] `Be-9, Mg -24, CA = 40`
Atomic mass of Mg = `(40+9)/2 =49/2 = 24.5`
i) They cannot be classified as DOBEREINER triads because they donot resemble with each other, though atomic mass of Si is the AVERAGE of Na and CI.
ii) It can be classified as Dobereiner.s triads because the elements resemble each other.