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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7551. |
Assertion (A) : ""_(17)Cl^(35) and ""_(17)Cl^(37) are isotones. Reason (R ) : Atoms of same element have same atomic number but different mass number. |
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Answer» (A) are (R ) are CORRECT.(R ) EXPLAIN (A) |
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| 7552. |
Assertion: 81g ofAluminiumcontains 3xx6.023 xx 10 ^(23) atomsReason: themoleis definedas theamountof substancewhichcontainsAvogadro's numberofparticles . Reason :81gofaluminum contains3 molesofaluminum , whichwillcontain3xx6.023 xx 10 ^(23)atoms. |
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Answer» BothassertionandReasonaretrueandReasonis correctexplanationof assertion |
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| 7553. |
Assertion: 1 moleof O_2and N_2 occupy22.4latS.T.P Reason:Molarvolumeof allgasesat S.T.Phasthe samevalue . |
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Answer» BothassertionandReasonaretrueandReasonis correctexplanationof ASSERTION |
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| 7554. |
As we move from left to right in a periodof Modem Periodic table, atomic size of theelements gradually increases . |
| Answer» Solution :False . As we move from leftto right in a period of the Modern Periodic table,ATOMIC size of THEELEMENTS GRADUALLY DECREASES. | |
| 7555. |
As we move from left to right in the Periodic Table, the atoms lose the valence electrons more easily. |
| Answer» SOLUTION :False - EFFECTIVE NUCLEAR charge increases, THEREFORE, it LOSES the valence electrons with more difficulty. | |
| 7556. |
As we move across a period from left to right, nonmetallic character________ (decreases/increases) |
| Answer» SOLUTION :INCREASES | |
| 7557. |
As we move across a period from left to right, metallic character ______ (decreases/ increases) |
| Answer» SOLUTION :DECREASES | |
| 7558. |
As we move across a period in the periodic table, what is the gradation in the following properties ? (a) Atomic number (b) Atomic size (c) Electronegativity. |
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Answer» Solution :(a) Atomic numbers of the elements increase (b) Atomic SIZES of the elements decrease (c) Electronegativity of the elements INCREASES. For details, consult section 5.5. |
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| 7559. |
As we go down a group, the number of shells goes on __________ . |
| Answer» SOLUTION :INCREASING | |
| 7560. |
As we descend the electrochemical series containing cations , the tendency of the cations to get _______ at the cathod increases . |
| Answer» SOLUTION :REDUCED | |
| 7561. |
As the shell number increases, the distancebetween the valence shell and the nucleus _____________. |
| Answer» SOLUTION :INCREASES | |
| 7562. |
As the positive charge increases , the size of the cation also increases . |
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Answer» |
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| 7564. |
As the pH value of a neutral solution increases |
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Answer» basic PROPERTY DECREASES and number of `OH^(-)`ions increases (C) basic property increases and number of `OH^(-)`ions increases. |
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| 7566. |
As the molecule is dissociated by the absorption of heat It is otherwise called as ….. |
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Answer» THERMOLYSIS |
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| 7567. |
As the molecular mass increases in any ______series, a gradation, in physical properties is |
| Answer» SOLUTION :HOMOLOGOUS | |
| 7568. |
As the decomposition is caused by light,this kind of reaction is called…. |
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Answer» Thermolysis |
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| 7570. |
"As energy moves progressively through various trophic levels of food chain it is no longer available to the previous level". Give reasons. |
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Answer» Solution :(1) The flow of energy is unidirectional. (2) At every trophic level, LARGE amount of energy is lost in form of heat for maintaining METABOLIC activities. (3) The amount of heat lost is generally 90 % and only 10 % of energy is retained and is available ftom previous trophic level to the NEXT. (4) Thus it is said that no energy is available for the previous level. . |
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| 7571. |
As electron moves away from the nucleus, its potential energy |
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Answer» INCREASES |
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| 7572. |
Arvind delivered a speech in the school assembly on "How to minimise the use of heavy metals ?" He told how mercury thermometers when broken and thrown away in the garbage leads to pollution of soil and underground water pollution. He also showed how cadmium and lead also causes dangerous health problems. What value of Arvind is seen in the act ? |
| Answer» Solution : Arvind showed the VALUE of CONCERN for NATURE, aware citizen and RESPONSIBLE BEHAVIOUR. | |
| 7573. |
Arvind delivered a speech in the school assembly on "How to minimise the use of heavy metals ?" He told how mercury thermometers when broken and thrown away in the garbage leads to pollution of soil and underground water pollution. He also showed how cadmium and lead also causes dangerous health problems. Name the disease caused due to mercury entering into our food-chain. |
| Answer» SOLUTION :MERCURY CAUSES MINAMATA DISEASE. | |
| 7574. |
Arvind delivered a speech in the school assembly on "How to minimise the use of heavy metals ?" He told how mercury thermometers when broken and thrown away in the garbage leads to pollution of soil and underground water pollution. He also showed how cadmium and lead also causes dangerous health problems. Name two heavy metals which are present in the mobile batteries. |
| Answer» Solution : Lead and CADMIUM are USED in the MOBILE BATTERIES. | |
| 7575. |
Arun's elder sister Rama is getting married nex month. His father and mother were takingRama to a jeweller's shop to select and buy gold jewellery for this occasion. Arun insisted on going with them to the jeweller's shop. The family saw a number of jewellery pieces. Rama liked one of the gold necklaces very much and wanted to buy it immediately. The jeweller said that this necklace was made of 22 carat gold. Just when Arun's father was about to make payment for this necklace, Arun steped in. He asked the jeweller to show the hallmark on this gold necklace. The jeweller told him that this necklace is yet to be sent to the hallmarking laboratory for testing and stamping. Arun asked his father not to buy this necklace until the jeweller gets it hall marked. The jeweller then asked for one week's time to get the necklace hallmarked. Mean while Arun explained the need for hallmarking of gold jewellery to his family. When Arun and his family returned after one weak, the necklace carried hallmark. They also obtained hallmark certificate and a proper receipt from the jeweller before paying money and taking delivery of necklace. Rama was very happy to get this necklace. (a) How many carats is pure gold? Why are ornaments not make of pure gold? (b)What is meant by 22 carats gold? What can a dishonest jeweller do to earn more profit form gold jewellery? (c) What is hallmark? Which Government Organisation controls the hallmark scheme for jewellery in India? (d) Why should we buy only hallmarked gold jewellery? (e) What values are displayed by Arunin this episode? |
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Answer» Solution :(a) The pure gold is 24 carats. Ornaments are not made of pure gold because pure gold is very soft (and hence it becomes difficult to work with it). (B) 22 carat gold means that 22 parts of pure gold has been alloyed by mixing 2 parts of either silver or copper. The addition of little of silver or copper makes the gold hard. This hardened gold is more suitable for making ornaments (because it becomes easier to work with it). In India, gold ornaments are usually made of 22 carat gold. The dishonest jeweller can mix a large amount of chaeaper metal such as silver or copper to the pure gold and still SELL the ornaments made from it as 22 carat gold to earn more profit. (c) hallmark is a mark (or logo) stamped on the article of gold jewellery which certifies the purity of gold used for making that jewellery. the hallmark SCHEME ris controlled by a GOVERNMENT Organisation called Bureau of Indian Standards (BIS). Ther are many authorised hall marking laboratories in EVERY city of India which test the purity of gold in every piece of jewellery before hallmarking it (The term Hallmark has come from the Goldsmith's Hall in London where gold jewellery articles were tested and stamped). (d) We should buy only hallmarked gold jewellery because it contains th e gold and its alloyed metal (silver or copper) in the correct ratio. It does not contain more of the cheaper metals (like silver or copper). Hallmark is a quality assurance certification of the purity of gold used in every piece of jewellery. (e) The vales displayed by Arun in this episode are (i) Awareness (or knowledge) of the existence of hallmark certification for the purity of gold jewellery (ii) Correct decision making skills (in not buying unmarked jewellery) and (iii) Desire to protect his family from being cheated by jeweller. |
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| 7576. |
Arsenic is a metalloid . (TRUE/ FALSE) |
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Answer» |
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| 7577. |
Arrive at, systematically, the IUPAC name of the compound: CH_(3)-CH_(2)-CH_(2)-OH. |
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Answer» Solution :Step 1: The parent chain consists of 4 carbon atoms. The root WORLD is .but. Step 2: All are single BONDS between the carbon atoms of the chain. So the primary suffix is .ane. Step 3: Since the compound contains the - OH group, it is an ALCOHOL. The secondary suffix is .ol.. But + ane + ol = Butan-ol = Butanol |
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| 7578. |
Arrange these alcohols in the order of increasing carbon atoms to get a family. Can we call this family a homologous series ? |
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Answer» SOLUTION :Alcohols in the increasing order of carbon atoms are as follows : `CH_(3)OH,C_(2)H_(5)OH,C_(3)H_(7)OH,C_(4)H_(9)OH` Yes, we CALL this family a homologous series. |
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| 7579. |
Arrange the metals Mg, Al, Zn and Fe in the decreasing order of their reactivity towards dilute hydrochloric acid. |
| Answer» SOLUTION :Mg > AL > ZN > Fe | |
| 7580. |
Arrange the metals such as Al, Cu, Fe, Pb, Mg, Zn and Na in the decreasing order of their reactivity towards oxygen. |
| Answer» Solution :Na > Mg > AL > Zn > FE > Pb > CU. | |
| 7581. |
Arrange the given metals (in activity) in the decreasing order of their reactivity with water. |
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Answer» Solution :Decreasing order of the REACTIVITY of METALS with water is given as FOLLOWS: K> Na > Ca > Mg > Al > ZN > Fe Pb, Cu, Ag and Au does not react with water. |
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| 7582. |
Arrange the following orbitals in the order in which they are filled with electrons and justify the order: 6s, 5d, 6p, 75, Sf. |
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Answer» SOLUTION :(i) Aufbau PRINCIPLE (ii) N+l VALUES of the given orbitals (iii) RELATION between energy and n +I value (iv) relation between energy and the value ofnfor the orbitals that have the same n+l values |
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| 7583. |
Arrange the following metals in the order their decreasing reactivity : Aluminium, Gold , Sodium, Copper |
| Answer» Solution :Sodium (Na) `gt` Aluminium (Al) `gt` COPPER (CU) `gt` GOLD (Au). | |
| 7584. |
Arrange the following metals in decreasing order of their reactivity. Fe,Zn,Na,Cu,Ag |
| Answer» Solution :`NA gt Zn gt FE gt CU gt Ag` | |
| 7585. |
Arrange the following metal in the increasing order of their reactivity towards water, Zinc, Iron, Magnesium, Sodium |
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Answer» IRON `LT` MAGNESIUM `lt` SODIUM `lt` zinc |
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| 7586. |
Arrange the following ions in the increasing order of unpaired electrons Na^+,Cu^(+1),N^(-3),O^-,P and Cr |
| Answer» SOLUTION : ELECTRONIC CONFIGURATION of the RESPECTIVE IONS. | |
| 7587. |
Arrange the following in the increasing order of acidic strength. Acetic acid, water and hydrochloric acid. |
| Answer» SOLUTION :WATER `LT` ACETIC acid `lt` HYDROCHLORIC acid | |
| 7588. |
Arrange the following in decreasing order of the intermolecular forces |
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Answer» LiquidgtGasgtSolid |
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| 7589. |
Arrange the following in decreasing atomic size : (i) Na, Mg, K(ii) N, F, O (iii) N, S, P |
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Answer» <P> SOLUTION :(i) K, Na, MG(ii) N , O, F (iii) P, S, N. |
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| 7590. |
Arrange the following elements in the order of their increasing non-metallic character Li, O, C,Be, F |
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Answer» `F lt O LTC lt Be lt LI` |
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| 7591. |
Arrange the following elements in the order of their decreasing metallic character: Na, Si, CI, Mg, Al. |
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Answer» CI GT SI gt AI gt Mg gt Na |
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| 7592. |
Arrange the following elements in the increasing order of their metallic characterMg, Ca, K, Ge, Ga |
| Answer» SOLUTION :Ge < GA < Mg < Ca < K | |
| 7593. |
Arrange the following elements in the descending order of atomic size and give a reason for your answer. Mg, CI, P. Ar Atomic number of elements is 12, 17, 15, 18. |
| Answer» Solution :`Mg, P , Cl , Ar` Increase in the atomic NUMBER MEANS increase in NUCLEAR charge which tends to PULL the ELECTRONS closer to the nucleus and reduces the size of the atom. | |
| 7594. |
Arrange the following elements in increasing order of their atomic radii: a] Li, Be, F, N "" b] Cl, At, Br, l |
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Answer» SOLUTION :a) Li, Be, F and N belong to the same PERIOD of Modern Periodic Table. As we move left to right in the periodic table, the atomic radii of elements decreases. THUS these elements arranged in increasing order of atomic radii are: `F < N Thus these elements arranged in increasing order of atomic radii are: `CI < Br < l < At`. |
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| 7595. |
Arrange the following elements in increasing order of their atomic radii: (a) Li, Be, F, N(b) C1, At, Br, I |
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Answer» SOLUTION :(a) F < N < Be < LI as the atomic radii decreases along a period. (b) Cl < Br < I < At as the atomic radii increases down a GROUP. |
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| 7596. |
Arrange the following elements in increasing order of their atomic radii : CI,At,Br, I |
| Answer» SOLUTION :`CI LT BR lt I lt At` | |
| 7597. |
Arrange the following element in the increasing order of atomic size . Rb , Li , K, Na . |
| Answer» SOLUTION :`Li lt Na lt K lt RB `. | |
| 7598. |
Arrange thefollowing compounds in thecorrect order of percentage of metallic element. (a) potassium hydroxide (b) potassium carbonate (c ) potassium bicarbonate (d) potassium sulphide |
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Answer» `a gt b gt c gt d` % of potassium = `39/56 xx 100 = 69.64%` (b) potassium CARBONATE ` to K_(2)CO_(3)` % of potassium = `78/138 xx 100 = 56.52%` (c ) potassium bicarbonate ` to KHCO_(3)` % of potassium ` = 39/100 xx= 39%` (d) potassium sulphide ` to K_(2)S` % of potassium = `(39 xx 2)/110 xx 100 = 70.90%` `:. ` increasing order is `(d) gt (a) gt (b) gt(c )` |
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| 7599. |
Arrange the following atomic numbers in the increasing order of number of unpaired electrons |
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Answer» 16 Electronic configuration is Electronic configuration is ` 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^2`number of unpaired electrons is 2. Electronic configuration is ` 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^2` number of unpaired electrons is 2. Electronic configuration is `[Xe] 6s^2 5d^1` number of unpaired electrons 1 `therefore` ORDER is (i) = (ii)= (iii) gt (IV) |
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| 7600. |
Arrange the following as per the instructiongiven in the brackets: Na, K, Li (Increasing atomic size) |
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