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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7601. |
Arrange the following as per the instructiongiven in the brackets:Na, Li, K (Increasing lonisation Energy) |
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| 7602. |
Arrange the following as per the instructiongiven in the brackets: He, Ar, Ne (Increasing order of the numberof electron shells) |
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| 7603. |
Arrange the following as per the instructiongiven in the brackets: F, Cl, Br (Increasing electronegativity) |
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Answer» <BR> ANSWER :Br, CL, F |
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| 7604. |
Arrange the following as per the instructions givenin the brackets : Na, K, Cl, S, Si (increasing order of ionizationenergy). |
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| 7605. |
Arrange the following as per the instructions givenin the brackets : Mg, Cl, Na, S, Si (decreasing order of atomicsize). |
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| 7606. |
Arrange the following as per the instructions givenin the brackets : Cs, Na, Li, K, Rb (increasing order of metalliccharacter). |
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Answer» <BR> ANSWER :LI,NA, Br, I |
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| 7607. |
Arrange the following as per instructions given in the brackets: Cl, F, Br, I (increasing order of electron affinity) |
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Answer» <BR> ANSWER :I, Br, CL, F |
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| 7608. |
Arrange the elements Au, Fe, Cu, Mg, Ca, Zn, Ag and K in descending order of their reactivity. |
| Answer» Solution :Descending ORDER of reactivity: K > CA > Mg > Zn > FE > CU > Ag > Au. | |
| 7609. |
Arrange the above elements in an increasing order of atomic radii. Does this arrangement match with the pattern of the group in the above answer? |
Answer» Solution :The above ELEMENTS in an increasing ORDER of atomic radii are as follows. This ARRANGEMENT MATCH with the pattern of the group in the above answer (i.e. group 1) |
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| 7610. |
Arrange sodium, potassium and calcium metals in the increasing order of their reactivity with water. |
| Answer» SOLUTION : CA < NA < K | |
| 7611. |
Arrange O^(2-), O^(-1) , O in decreasing radius (size). |
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| 7612. |
Arrange giving reason the following elements in increasing order of their atomic size : (a) Be, O, F (Given that they beiong to 2nd, 16th and 17th groups respectively and to 2nd period). (b) I, CI, F (Given that they belong to 5th, 3rd and 2nd periods respectively of 17th group). (c) Mg, N, P (Given that Mg and P belong to 2^(nd)" and "15^(th) group respectively of 3^(rd) period and N belongs to 15^(th)" group of "2^(nd) period). |
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Answer» Solution :(a) All these elements are present in the `2^(nd)` period but in different group. The increasing order of their atomic RADIUS is : `FltOltBe.` (b) These elements are present in the same group but in different periods. Since the atomic size INCREASES down the group `(2^(nd) , 3^(RD)" and "5^(th) "periods")` the increasing order of atomic radius is : `FltClltI` (c) On similar line, the increasing order of atomic radius is : `NltPltMg.` For more clarification, please consult Long Form of PERIODIC Table. |
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| 7613. |
Arrange giving reason the following elements in the increasing order of their atomic size: a) Be, O, F (Given that they belong to 2nd, 8th, and 9th groups and 2nd period respectively) b) I, CI, F (Given that they belong to 5th, 3rd, and 2nd period respectively in the same group) c) Mg, N, P (Given that Mg and P belong to 2nd and 15th group respectively of 3rd period and N belongs to 15th group of 2nd period) |
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Answer» <P> Solution :a) `F < O < Be`, since atomic size decreases from left to right in a period.B] `F < Cl < 1`, since atomic size increases down a group. c)`N < P < Mg`, because Mg, being in LOWER group, has the largest atomic size. P has a LARGER size COMPARED to N as it lies below N in the same group. |
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| 7614. |
Aromicityof Sulphuris |
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Answer» 1 |
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| 7616. |
Argon is not an inert gas. |
| Answer» SOLUTION :False . ARGON is an INERT GAS, BELONGS togroup 18. | |
| 7618. |
Are the magnetic quantum number and angular momentum of an electron related to each other? Explain |
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Answer» Solution :(i) SIGNIFICANCE of MAGNETIC quantum NUMBER (II) degeneracy of orbitals (iii) effect of a magnetic FIELD |
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| 7619. |
______are the medicines that are used to treat indigestion. |
| Answer» Solution :ANTACIDS. INDIGESTION is caused by EXCESSIVE acidity in the STOMACH. The role of antacids is to neutralise acidity. | |
| 7620. |
Are the magnetic quantum number and angular momentum of an electron related to each other? Explain. |
| Answer» Solution :Magnetic quantum number represents the spatial orientation of the electrons that belong to same MAIN and subenergy levels. Angular momentum is fixed for the orbitals associated with same 'n' and 'l' values. The degeneracy of the orbit- als gets DISTURBED by applying externl magnetic field or electric field due to the CHANGE in angular momentum. Since the electrons are movingcharged particles, they have their own magneticfield that has a particular direction and the direc-tion of the magnetic field is different for different orbitals BELONGING to the same main and suben-ergy levels. Hence, the influence of the EXTERNAL magnetic or electric field is also different for different orbitals, which, in turn, changes the angu- lar momentum of the electrons and their degen-eracy gets lost. | |
| 7621. |
Are the elements now arranged in the pattern of a period in the periodic table ? |
| Answer» Solution :Now, the above ELEMENTS are ARRANGED in the pattern of a period in the periodic table. | |
| 7622. |
Are the boiling points and melting points of covalent compounds high or low in comparison to ionic compounds ? |
| Answer» Solution :Melting POINTS and BOILING points of COVALENT compounds are comparatively LOWER than the melting points and boiling points of IONIC compounds. | |
| 7623. |
Are synthetic detergents biogegradable ? |
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| 7624. |
Are structure isomers possible for bromopentane? |
Answer» SOLUTION :
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| 7625. |
………………….are salts of sulphonic acids. |
| Answer» SOLUTION :DETERGENTS | |
| 7626. |
Are ore gives carbon dioxide on treatment with a dilute acid. What steps will you take to convert such a concentrated ore into free metal? |
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Answer» Solution :A metal CARBONATE REACTS with a dilute acid to from carbon dioxide. Therefore, this ore is a carbonate ore. Carbonate ore is converted into free metal in the FOLLOWING two STEPS: (i) Calcination: the carbonate ore is strongly heated in the absence of AIR to get the metal oxide. Metal carbonate `to^(Calcination)` Metal oxide +Carbon dioxide (ii) Reduction: The metal oxide is reduced with carbon to get free metal. Metal oxide +`Carbon_((Coke)) to^(Reduction)`+Metal+Carbon monoxide. |
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| 7627. |
Are metals electropositive or electronegative? State reason also |
| Answer» Solution :Metals are ELEMENTS that have a TENDENCY to loose ELECTRON and FORM cation. The have electropositve CHARACTER. | |
| 7630. |
Are covalent compounds usually solids ? |
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| 7631. |
_______are characterised by the presence of only single covalent bonds between carbon atoms. |
| Answer» SOLUTION :ALKANES | |
| 7632. |
Are both acids indicated by the litmus test ? |
| Answer» Solution :Both acids TURN BLUE litmus to red, thus, both the acids are INDICATED by the litmus TEST. | |
| 7634. |
Write the balanced equation with state symbols for the following chemical reactions. (i) Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride. (ii) Sodium hydroxide solution (in water) with hydrochloric acid solution (in water) to produce sodium chloride solution and water. |
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Answer» Solution :When a solution of sodium sulphate is added to a solution of barium CHLORIDE a white precipitate of barium sulphate will be formed immediately. This precipitate is INSOLUBLE in dil-Hydrochloric ACID and also insoluble in water. This type of reaction is called precipitation reaction as the `BaSO_4`precipitate thus formed is of white COLOUR. `Na_2 SO_4 (aq) + BaCl_2 (aq) to BaSO_4(s) + 2NaCl(aq)` Since, barium sulphate is insoluble in water. So it will precipitate as a SOLID, whereas the sodium chloride will remain in solution. |
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| 7635. |
Aqueous solution of NaCl is not used for electrolytic isolation of sodium metal. Give reason. |
| Answer» SOLUTION :Because in an AQUEOUS solution of sodium chloride, the HYDROGEN ions of water are REDUCED in preference to sodium ions. | |
| 7636. |
Aqueous solution of electrolyte is a better conductor than fused electrolyte. Give reason. |
| Answer» Solution :Due to the high dielectric constant of water, the dissociations of electrolyte into ions is GREATER in aqueous solution than in fused electrolyte. As a RESULT, the CONCENTRATION of free ions in aqueous solution is greater than in fused state. Therefore, conductivity of aqueous solution of electrolyte is greater than that of fused electrolyte. | |
| 7637. |
Aquatic species are more comfortable in cold water because ...... |
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Answer» as the TEMPERATURE decreases, the SOLUBILITY of dissolved oxygen increases |
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| 7638. |
Aquatic animals live more in hot regions. |
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| 7639. |
Aqua regia is a mixture of |
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Answer» three parts of CONCENTRATED NITRIC ACID and one PART of concentrated hydrochloric acid |
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| 7640. |
Apart from organic beings, where else do we find carbon ? Mention the form in which it is available there and also its percentage. |
| Answer» Solution :In the ATMOSPHERE, it is found as `CO_(2)` and in the earth.s crust it is found as minerals like CARBONATES. The PERCENTAGE of CARBON in the AIR is 0.03% and in the earth.s crust, it is present to the extent of 0.02% | |
| 7643. |
Any reaction that produces a precipitate is called a redox reaction. |
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Answer» SOLUTION :FALSE CORRECT statement:Any reaction that PRODUCES a precipitate is called a precipitation reaction. |
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| 7644. |
Any two adjacent members of a homologous series differ by : |
| Answer» Answer :B | |
| 7645. |
Ant sting causes irratation due to the presence of |
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Answer» a BASE in the STING |
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| 7646. |
Answer the questions based on the given data. |
Answer» SOLUTION :
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| 7647. |
Answer the following : What happens when crystals of washing soda are left open in dry air ? |
| Answer» SOLUTION :When crystals of washing SODA is LEFT open in dry AIR, I loses water of crystallisation. | |
| 7648. |
Answer the following questions with respect to the solutions marked 'A' and 'B' having pH values 4 and 10 respectively. Which solution will give a red colour with methyl orange? |
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| 7649. |
Answer the following questions with respect to the solutions marked 'A' and 'B' having pH values 4 and 10 respectively. Which solution will liberate carbon dioxide from sodium carbonate? |
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| 7650. |
Answer the following questions with respect to the solutions marked 'A' and 'B' having pH values 4 and 10 respectively. Which solution will change red litmus blue? |
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