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2951.

The given diagram is to prepare Iron(III) chloride in the laboratory: (i) What is substance B? (ii) What is the purpose of B? (iii) Why is iron(III) chloride to be stored in a closed container? (iv) Write the equation for the reaction between iron and chlorine.

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Solution :(i) FUSED CALCIUM CHLORINE
(ii) Acts as drying agnet
(iii) Because it is DELIQUESCENT salt
(iv) `3FE(s)+3Cl_(2)(g)to2FeCl_(3)(s)`
2952.

The general molecular formula of alkynes is………………

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SOLUTION :`C_(N)H_(2n-2)`
2953.

The general molecularformulaof alkyeneis __________ .

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SOLUTION :`C_nH_(2n-2)`
2954.

The general formula______ represents alkynes.

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SOLUTION :`C_nH_(2n-2)`
2955.

The general formula _____ represents alkenes.

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SOLUTION :`C_n H_(2N)`
2956.

The general formula of two specific groups of saturated and unsaturated hydrocarbons is C_nH_(2n) . Write the structure of the number of each group when n = 3 .

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SOLUTION :
2957.

The general formula of three compounds A,B and C is C_nH_(2n), Bhas the highest boiling point , and C has the lowest boiling point . (a) Mention the type of compounds A,B and C . (b) Which of them has the minimum number of carbon atoms? (c) Name the homologous series to which they belong.

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SOLUTION :a] Unsaturated hydrocarbons. `""` B] C.
c] ALKENES.
2958.

The general formula of saturated hydrocarbons is

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`C_nH_(2N + 1)`
`C_nH_(2n + 2)`
`C_nH_(2n)`
`C_nH_(2n -2)`

ANSWER :B
2959.

The general formula of carboxylic acid is :

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`C_(N)H_(2n+1)OH`
`C_(n)H_(2n+1)CHO`
`C_(n)H_(2n+1)COOH`
`C_(n)H_(2n+2)`

Answer :C
2960.

The general formula of carbodxylic acids is

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`R-CHO`
`R - COOR`
`R- COOH`
`R-O-R`

ANSWER :C
2961.

The general formula of alkenes is C_n H_(2n) , therefore, the first stable member of this series is____.

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SOLUTION :`C_2H_4`
2962.

The general formula of alkene is ..........

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SOLUTION :`C_(N)H_(2N)`
2963.

The general formula of a homologous series of carbon compounds is C_n H_(2n+1)OH . Write the molecular formula of the fourth and the fifth members of the series.

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SOLUTION :`C_4H_9OH ` and `C_5H_11OH`
2964.

The general formula of a group of organic compounds in C_(n) H_(2n+1)OH. . Write the molecular formula of first two members of this group. Examine whether these two compounds are in homologous series, based on their molecular formula.

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Solution :`C_(n)H_(2n+1)OH`
By TAKING n = 1, 2 we get
`C_(1)H_(2xx1+1)OH = CH_(3)OH , C_(2)H_(2xx2+1)OH=C_(2)H_(5)OH`
The COMPOUNDS are methanol and ethanol. Other compounds are ethanol, propanol etc,.
They are homologous.
2965.

The general formula for alkane is ___

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SOLUTION :`C_n H_(2N +2)`
2966.

The general formula C_n H_(2n+2)represents _____. (alkanes, alkenes)

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SOLUTION :ALKANES
2967.

The general formula C_n H_(2n+2) represents_____.

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SOLUTION :ALKANES
2968.

(a) How does speciation take place? (b) Define the term gene. (c) The gene for red hair is recessive to the gene for black hair. What will be the hair colour of a child if he inherits a gene for red colour from his mother and a gene for black hair from his father? Express with the help of flow chart.

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SOLUTION :Given,
Brown HAIR-Mother-RECESSIVE : bb
BLACK hair-Father-Dominant: BB

Thus , the child will have black hair.
(as the gene of brown coloured is recessive . )
2969.

The gas used in welding and cutting metals is ___

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Ethyne
Ethene
Ethane
Propane

Answer :A
2970.

The gas used in the welding and cutting of metals is

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ethane
ethene
ETHYNE
propene

Solution :Ethyne (ACETYLENE is USED WELDING and cutting of metals CALLED oxyacetylene welding.
2971.

The gas released when calcium carbonate reacts with dilute hydrochloric acid is ..

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`NO_(2)`
CO
`CO_(2)`
`H_(2)`

Answer :B::C
2972.

The gas released when a metal reacts with an acid is……….

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SOLUTION :NA
2973.

The gas liberated when magnesium reacts with boiling water is :

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Oxygen
Hydrogen
Carbon dioxide
Nitrogen

Answer :B
2974.

The gas jar used for collecting ammonia is kept inverted .Why?

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ANSWER :AMONIA is LIGHTER than AIR.
2975.

The gas evolved when solid sodium carbonate is treated with dilute HCl is

Answer»

HYDROGEN .
CARBON DIOXIDE
chlorine
NONE of these

Answer :B
2976.

The gap between the conduction band and valence band is largest in

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Semiconductors
Insulators
Conductors
None of the above

Answer :B
2977.

The fundamental particles not present in the nucleus of hydrogen atom is

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electron
proton
neutron
none of these

ANSWER :C
2978.

The functions of hormones are given in Column-A annd the names of the hormones are given in Column-B. Match them and write the answer along with its letters : ""{:("Column-A", "Column-B"), ("(A) Prepares the body to deal with the situation", "(i) Growth hormone"), ("(B) Regulates metabolism for body growth.", "(ii) Testoterone"), ("(C) Regulates blood sugar levels", "(iii) Adrenaline"), ("(D) Regulates the growth and development of the body", "(iv) Progesterone"), ("", "(v) Insulin"), ("", "(vi) Thyroxine"), ("", "(vii) Oestrogen"):}

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SOLUTION :(A) (iiii) ADRENALINE
(B) (vi) Thyroxine
(C) (V) INSULIN
(D) (i) Growth hormone
2979.

The functional groups present in propanol and propanal respectively are.

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`- OH and - CHO`
`-OH and - COOH`
`- COH and COOH`
`-CHO and - CO`

Answer :A
2980.

The functional groups present in propanol and propanal respectively are

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`-OH and -CHO`
`-OH and -COOH`
`-CHO and - COOH`
`-CHO and - CO`

ANSWER :A
2981.

The functional group present in the Compound CH_3-O-CH_3 is__________

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Hydroxy
Alkoxy
Methyl
Carboxylic

Answer :B
2982.

The functional group present in carboxylic acids is :

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`-COOH`

`-CHO`
`-OH`

ANSWER :B
2983.

The functional group present inC_(2)H_(5)CO_(2)H is ______

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SOLUTION :`CO_(2)` H
2984.

The functional group present in alcohol is :

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`-CHO`
`-COOH`
`-OH`

ANSWER :D
2985.

The functional group present in acetic acid is :

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Ketonic C = O
HYDROXYL -OH
Aldehydic -CHO
Carboxylic - COOH

Answer :A::B::C
2986.

The functional group Aldehdye is a

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ANSWER :A
2987.

Full form of IUCN :-

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SOLUTION :CONSERVATION
2988.

The frequency of power supply used in India

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70HZ
60HZ
50HZ
30HZ

Answer :C
2989.

The fractional distillation of coaltar yields

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CARBON disulphide
carbon TETRACHLORIDE
kerosene oil
BENZENE

SOLUTION :benzene
2990.

The formulae of oxides formed when barium burns in presence of oxygen are

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(a) `Ba_(2)O, BaO`
(b) `BaO, BaO_(2)`
(c) `BaO, Ba_(2) O_(2)`
(d) `Ba_(2) O, BaO_(2)`

SOLUTION :`2Ba+O_(2) to 2BaO` ("Barium OXIDE")
`BA+O_(2) to BaO_(2)` ("Barium PEROXIDE")
2991.

The formula of tetrachloro methane is

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`C ClH_3`
`C Cl_2`
`CHCl_3`
`C Cl_4`

SOLUTION :`C Cl_4`
2992.

The formula of sodium phosphate is

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`NaPO_(4)`
`Na_(2)PO_(4)`
`Na_(3)PO_(4)`
`NaPO_(2)`

SOLUTION :
2993.

The formula of soda ash is

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`Na_(2)CO_(3).10H_(2)O`
`Na_(2)CO_(3).2H_(2)O`
`Na_(2)CO_(3).H_(2)O`
`Na_(2)CO_(3)`

Answer :D
2994.

The formula of slaked lime is :

Answer»

CALCIUM Carbonate
Calcium Hydroxide
Calcium OXIDE
Calcium Chloride.

Solution :Calcium Oxide
2995.

Quicklime is :

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`Ca(OH)_2`
`CaCl_2`
`CaO`
`CaSO_4`

SOLUTION :The FORMULA of QUICK lime is CaO.
`Ca(OH)_2`is slaked lime
` CaCl_2` is CALCIUM Chloride
`CaSO_4` is Calcium SULPHATE
2996.

The densities of transition metals are greater than the alkali and alkaline earth metals. Justify.

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SOLUTION :(i) factors affecting density
(ii) comparison of electron filling in alkali, alkaline
EARTH AMD transition metals
(iii) effect on atomic size
(iv) comparison of MASS with respect to atomic VOLUME
among alkali, alkaline earth and transition metals
2997.

The Delta H^(0) for the following reaction at 298 K is -36.4 kJ 1//2 H_(2) (g) + 1//2Br_(2) (I) rarr HBr(g) Calculate DeltaU^(0) at 298 K. The universal gas constant, R, is 8.314 J/mol K.

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`-35.2kJ`
`+35.2kJ`
`-36.4 KJ`
`-37.6 kJ`

ANSWER :D
2998.

The Delta H and Delta S " for" 2 Ag_(2)O (s) rarr 4Ag(s) + O_(2) (g) are given + 61.18 kJ mol^(-) and + 132 JK^(-1) mol^(-1) respectively. Above what temperature will be reaction be spontaneous?

Answer»

SOLUTION :`GT 463.4 K`
2999.

The deficiency of vitamin B - 12 causes pernicious anaemia. The vitamin B - 12 is a complex of _____________metal.

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IRON
CHROMIUM
ALUMINIUM
cobalt

Answer :D
3000.

The decreasing order of electronegativity of F, O and Nis F gt O gt N.

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ANSWER :TRUE